the number of solutions to the polynomial x^8 + 8 is......
let P(x) be a polynomial of degree 3 and x1, x2, x3 are the solutions of P(x)=0. let \(\frac{P\left(\frac{1}{3}\right)-P\left(\frac{-1}{3}\right)}{P\left(0\right)}=8,\frac{P\left(\frac{1}{4}\right)-P\left(\frac{-1}{4}\right)}{P\left(0\right)}=9\)and x1+x2+x3 = 35. find the value of \(\frac{x2+x3}{x1}+\frac{x1+x3}{x2}+\frac{x1+x2}{x3}\)
Suppose that the polynomial f(x) = x5 - x4 - 4x3 + 2x2 + 4x + 1 has 5 solutions x1; x2; x3; x4; x5. The other polynomial k(x) = x2 - 4.
Find the value of P = k(x1) x k(x2) x k(x3) x k(x4) x k(x5)
Answer: P = .............
Exam number 219:12
Fill in the blank with the suitable number (Note: write decimal number with "the dot" between number part and fraction part. Example: 0.5)
Question 1:
Given .
Find the value of "" such that its degree is equal to 4.
Answer: The value of "" is
Question 2:
The value of with is
Question 3:
Given .
The degree of is
Question 4:
Given .
The degree of is
Question 5:
Given .
The value of is
Question 6:
In this figure, if the length of the line segment is an even number.
Then .
Question 7:
Given .
The value of
Question 8:
The value of with is
Question 9:
Given with .
Then the minimum of is
Question 10:
The minimum value of is
A certain number of fifty-cent coins is to from an equilateral triangle. The same number of fifty-cent coins can also be used to from a square. The number of fiftty-cent coins on each side of the square is 6 fewer than the number of fifty-cent coins on each side of the equilateral traingle. How many fifty-cent coins are there altogether?
let p(x) be a real polynomial of degree 2015. suppose that P(n) =n/n+1 for all n=0;1;2;...;2015
The value of P(2016) is .........
it is given ab/a+b=8. the value of a+b is square number. find a and b.
Giải Toán Tiếng Anh đi chúng cậu!!!!
1) Find the number not equal to O such that triple its square is equal to twice of its cube.
(Write your answer as a decimal number in the simplest form)
2) If \(\frac{x}{2}-\frac{x}{6}\)is an integer. Find the following statement must be true???
Given a square with the length of one side is 8 cm and a isosceles triangle with the length of its base is 12 cm. If the area of the square is equal to the area of the isosceles triangle then what is the length of the height of the isosceles triangle, in cm?