Tính giá trị biểu
B=\(\dfrac{30.4^7.3^{29}-5.14^5.2^{12}}{54.6^{14}.9^7-12.8^5.7^5}\)
\(\dfrac{30.4^7.3^{29}-5.14^5.2^{12}}{54.6^{14}.9^2-12.8^5.7^5}\)
Mọi người giúp mình bài toán này
= \(\dfrac{5}{2}\)
bạn THAM KHẢO thôi nhé!
Kq = 5/2 nha bạn câu này đã có người hỏi rồi bạn tự tham khảo nhé
\(...=\dfrac{2.3.5.2^{14}.3^{29}-5.2^5.7^5.2^{12}}{3^2.2.3.2^{14}.3^{14}.3^4-3.2^2.2^{15}.7^5}\)
\(=\dfrac{2^{15}.3^{30}.5-2^{17}.5.7^5}{2^{15}.3^{21}-2^{17}.3.7^5}\)
\(=\dfrac{2^{15}.5\left(3^{30}-2^2.7^5\right)}{2^{15}.3.\left(3^{20}-2^2.7^5\right)}\)
\(=\dfrac{5\left(3^{30}-2^2.7^5\right)}{3.\left(3^{20}-2^2.7^5\right)}\)
thực hiện phép tính:
\(B=\dfrac{30.4^7.3^{29}-5.14^5.2^{12}}{54.6^{14}.9^7-12.8^5.7^5}\)
\(=\dfrac{3^{30}\cdot2^{15}\cdot5-5\cdot2^{17}\cdot7^5}{2^{14}\cdot3^{14}\cdot3^3\cdot2\cdot3^{14}-2^{15}\cdot7^5\cdot2^2\cdot3}\)
\(=\dfrac{2^{15}\cdot5\left(3^{30}-2^2\cdot7^5\right)}{2^{15}\cdot3^{31}-2^{17}\cdot7^5\cdot3}\)
\(=\dfrac{2^{15}\cdot5\left(3^{30}-2^2\cdot7^5\right)}{2^{15}\cdot3\left(3^{30}-2^2\cdot7^5\right)}=\dfrac{5}{3}\)
Tính
C= \(\frac{30.4^7.3^{29}-5.14^5.2^{12}}{54.6^{14}.9^7-12.8^5.7^5}\)
Mik ko chắc lắm đâu nha(/Mik làm tắc nên mất phấn tắc ra TSNT)
Tính :\(A=\frac{30.4^7.3^{29}-5.14^5.2^{12}}{54.6^{14}.9^7-12.8^5.7^5}\)
tính B = \(\frac{30.4^7.3^{29}-5.14^5.2^{12}}{54.6^{14}.9^7-12.8^5.7^5}\)
Mọi người giúp mình với, mình tick cho!
Thực hiện phép tính : \(B=\frac{30.4^7.3^{29}-5.14^5.2^{12}}{54.6^{14}.9^7-12.8^5.7^5}\)
giúp mình giải chi tiết nha
\(B=\frac{5.2^{15}.3^{30}-5.7^5.2^5.2^{12}}{5^4.2^{14}.3^{14}.3^7.3^7-2^2.3.2^{15}.7^5}\)
=> \(B=\frac{5.2^{15}.3^{30}-5.7^5.2^{17}}{5^4.2^{14}.3^{28}-2^{17}.3.7}\)
=> \(B=\frac{5.2.3^{30}-5.7^5.2^3}{5^4.3^{28}-2^3.3.7}=0,144\)
B=(30.4^7.3^29-5.14^5.2^12)/(54.6^14.9^7-12.8^5.7^5)
Giúp mk gấp nha 😊
Tính
C = \(\frac{30.4^7.3^{29}-5.14^5.2^{12}}{5^4.6^{14}.9^7-12.8^5.7^5}\)
Thực hiện phép tính :
1) A = \(\dfrac{155-\dfrac{10}{7}-\dfrac{5}{11}+\dfrac{5}{23}}{403-\dfrac{26}{7}-\dfrac{13}{11}+\dfrac{13}{23}}+\dfrac{\dfrac{3}{5}+\dfrac{3}{13}-0,9}{\dfrac{7}{91}+0,2-\dfrac{3}{10}}\)
2) B = \(\dfrac{30.4^7.3^{29}-5.14^5.2^{12}}{54.6^{14}.9^7-12.8^5.7^5}\)
1: \(A=\dfrac{5\left(31-\dfrac{2}{7}-\dfrac{1}{11}+\dfrac{1}{23}\right)}{13\left(31-\dfrac{2}{7}-\dfrac{1}{11}+\dfrac{1}{23}\right)}+\dfrac{3\left(\dfrac{1}{5}+\dfrac{1}{13}-\dfrac{3}{10}\right)}{\dfrac{1}{13}+\dfrac{1}{5}-\dfrac{3}{10}}\)
=5/13+3
=5/13+39/13
=44/13
2: \(B=\dfrac{2^{15}\cdot3^{30}\cdot5-5\cdot2^5\cdot7^5\cdot2^{12}}{3^3\cdot2\cdot2^{14}\cdot3^{14}\cdot3^{14}-2^2\cdot3\cdot2^{15}\cdot7^5}\)
\(=\dfrac{5\cdot2^{15}\left(3^{30}-2^2\cdot7^5\right)}{3^{31}\cdot2^{15}-2^{17}\cdot3\cdot7^5}\)
\(=\dfrac{5\cdot2^{15}\left(3^{30}-2^2\cdot7^5\right)}{3\cdot2^{15}\cdot\left(3^{30}-2^2\cdot7^5\right)}=\dfrac{5}{3}\)