mn ơi giúp mình với ạ, mình cần gấp ạ
nhìn thế nhưng k dài đâu ạ
thanks mn nhiều
giúp mình với ạ
thanks mn nhiều ạ
Mn ơi giúp mình bài này với mình đang cần gấp ko cần dịch đâu ạ
1 think
2 that
3 said
4 that
5 that
6 tell
7 that
8 that
9 that
10 that
11 think
12 assurance
13 that
14 That
15 That
mn ơi giúp mik bài 11 với ạ, mình cần gấp ạ
Cảm ơn mn nhiều ạ
mn ơi giúp mình với ạ, mình cần gấp,mình cảm ơn mn
Mn ơi giúp mình với ạ mình cần gấp ạ
1 his illness, he cannot come
2 her busyness, she couldn't help us
3 his illness, he tries to go to school on time
4 the bad weather, we tried to finish the work on the road
5 the bad weather, we got to the station late
6 the old house, she liked it
7 not wearing any shoes, Carol ran outside to see what was happening
8 being afraid of flying, Fiona had to get on the plane
Mn ơi giúp mình với. Đầu bài là: Nêu dẫn chứng về đức tính giản dị của Bác Hồ (Bằng sơ đồ tư duy). Nhanh ạ mình đg cần gấp ai đúng mình sẽ vote cho ạ. C.ơn mn rất nhiều
What you must / mustn't in Ly Son island ?
Giúp mình với mn ơi mình đang cần gấp "Cảm ơn mọi người nhiều ạ"
You must wear sun scream when you're on Ly Son island
- You must go to Ly Son Island in the early morning or late afternoon
- You mustn't litter on the island
- You mustn't swim alone. You must wear sun scream when you're on my son's island
- You must go to the Sam Son beach in the early morning or late afternoon
- You mustn't litter on the island
- You mustn't swim alone.
chucbanhoctot
#tranhuyentuanh
Mn ơi giúp mình với mình cần gấp ạ
\(a,A=\dfrac{x+2\sqrt{x}+1+x-2\sqrt{x}+1-3\sqrt{x}-1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\\ A=\dfrac{2x-3\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}=\dfrac{\left(\sqrt{x}-1\right)\left(2\sqrt{x}-1\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}=\dfrac{2\sqrt{x}-1}{\sqrt{x}+1}\\ b,A=\dfrac{2\left(\sqrt{x}+1\right)-3}{\sqrt{x}+1}=2-\dfrac{3}{\sqrt{x}+1}\in Z\\ \Leftrightarrow\sqrt{x}+1\inƯ\left(3\right)=\left\{1;3\right\}\left(\sqrt{x}+1\ge1\right)\\ \Leftrightarrow\sqrt{x}\in\left\{0;2\right\}\\ \Leftrightarrow x\in\left\{0;4\right\}\left(tm\right)\)
a) \(A=\dfrac{\sqrt{x}+1}{\sqrt{x}-1}+\dfrac{\sqrt{x}-1}{\sqrt{x}+1}-\dfrac{3\sqrt{x}+1}{x-1}\)
\(\Rightarrow A=\dfrac{\left(\sqrt{x}+1\right)^2}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}+\dfrac{\left(\sqrt{x}-1\right)^2}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}-\dfrac{3\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)
\(\Rightarrow A=\dfrac{x+2\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}+\dfrac{x-2\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}-\dfrac{3\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)
\(\Rightarrow A=\dfrac{x+2\sqrt{x}+1+x-2\sqrt{x}+1-3\sqrt{x}-1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)
\(\Rightarrow A=\dfrac{2x-3\sqrt{x}+1}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)
\(\Rightarrow A=\dfrac{\left(2x-2\sqrt{x}\right)-\left(\sqrt{x}-1\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)
\(\Rightarrow A=\dfrac{2\sqrt{x}\left(\sqrt{x}-1\right)-\left(\sqrt{x}-1\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)
\(\Rightarrow A=\dfrac{\left(2\sqrt{x}-1\right)\left(\sqrt{x}-1\right)}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}\)
\(\Rightarrow A=\dfrac{2\sqrt{x}-1}{\sqrt{x}+1}\)
Giúp mình b13 với ạ! (0 cần vẽ hình đâu nhé) Camon mn trc ạ, mình cần gấp :((