a, A =1 + 2 -  3 - 4 + 5 + 6 - 7 - 8 + 9 +...+ 82 - 83 - 84 + 85

A =(1+2-3-4)+(5+6-7-8)+...+(81+82-83-84) + 85

Xét dãy số: 1; 5;...;81

Dãy số trên là dãy số cách đều với khoảng cách là: 5-1 = 4

Số số hạng của dãy số trên là: (81-1):4+1 = 21 (số hạng)

Vậy tổng A là tổng của 21 nhóm và 85, trong đó mỗi nhóm có giá trị bằng 1+2-3-4 =  - 4

A = -4. 21 + 85 = 1

yêu cầu của câu c là gì thế em

mình cần gấp

a, 28 + 2x = 35 - ( -13 )

=> 2x = 35 + 13 - 28

=>2x = 20

=> x = 10. vậy x = 10

a, \(28+2x=35+13\Leftrightarrow28+2x=48\Leftrightarrow2x=20\Leftrightarrow x=10\)

b, \(-25-x-5=415+5x-415\Leftrightarrow-6x=30\Leftrightarrow x=-5\)

1: -5>-10

=>x-5>x-10

2: -4>-8

=>x-4>x-8

3: 2>-6

=>x+2>x-6

4: -3<7

=>x-3<x+7

5: 5<8

=>x+5<x+8

6: 10>7

=>x+10>x+7

Bài 1:

a: \(x=\dfrac{2}{3}:\dfrac{3}{5}=\dfrac{2}{3}\cdot\dfrac{5}{3}=\dfrac{10}{9}\)

b: \(x=\dfrac{17}{8}:\dfrac{7}{17}=\dfrac{17}{8}\cdot\dfrac{17}{7}=\dfrac{289}{56}\)

c: \(x=-\dfrac{3}{4}:\dfrac{7}{12}=\dfrac{-3}{4}\cdot\dfrac{12}{7}=\dfrac{-63}{28}=-\dfrac{9}{4}\)

d: \(\Leftrightarrow x\cdot\dfrac{1}{6}=\dfrac{3}{8}-\dfrac{1}{4}=\dfrac{1}{4}\)

hay \(x=\dfrac{1}{4}:\dfrac{1}{6}=\dfrac{3}{2}\)

e: \(\Leftrightarrow\dfrac{1}{2}:x=-4-\dfrac{1}{3}=-\dfrac{17}{3}\)

hay \(x=-\dfrac{1}{2}:\dfrac{17}{3}=\dfrac{-3}{34}\)

dad

   43 x 166 + 14 x 83 

= 43 x ( 83 x 2 ) + 14 x 83

= (43 x 2) x 83 + 14 x 83

= 86 x 83 + 14 x 83

= ( 86 + 14 ) x 83

= 100 x 83

= 8300

43 x 166 + 14 x 83

= 43 x ( 83 x 2 ) + 14 x 83

= ( 43 x 2 ) x 83 + 14 x 83

= 86 x 83 + 14 x 83

= 83 x ( 86 + 14 )

= 83 x 100

= 8300

\(\frac{7}{2}\)- \(\frac{3}{2}\): x = \(\frac{5}{4}\)

\(\frac{3}{2}\): x = \(\frac{7}{2}-\frac{5}{4}\)

\(\frac{3}{2}\): x = \(\frac{14}{4}-\frac{5}{4}\)

\(\frac{3}{2}\): x = \(\frac{9}{4}\)

           x = \(\frac{3}{2}:\frac{9}{4}\)

           x = \(\frac{3}{2}x\frac{9}{4}\)

           x = \(\frac{27}{8}\)

14x6=

\(5\dfrac{3}{4}:3+2\dfrac{1}{4}\times\dfrac{1}{3}-\dfrac{1}{8}=\left(5\dfrac{3}{4}+2\dfrac{1}{4}\right)\times\dfrac{1}{3}-\dfrac{1}{8}\\ =8\times\dfrac{1}{3}-\dfrac{1}{8}=\dfrac{8}{3}-\dfrac{1}{8}=\dfrac{61}{24}\\ ----\\ \dfrac{3}{5}:\dfrac{5}{6}:\dfrac{6}{7}:\dfrac{7}{8}+\dfrac{2}{5}+\dfrac{23}{35}\\ =\dfrac{3}{5}\times\dfrac{6}{5}\times\dfrac{7}{6}\times\dfrac{8}{7}+\dfrac{2}{5}+\dfrac{23}{35}=\dfrac{18}{25}\times\dfrac{4}{3}+\dfrac{2}{5}+\dfrac{23}{35}=\dfrac{353}{175}\)

a) \(\dfrac{5}{7}\times\dfrac{5}{9}+\dfrac{4}{9}\times\dfrac{5}{7}\)

\(=\dfrac{5}{7}\times\left(\dfrac{4}{9}+\dfrac{5}{9}\right)\)

\(=\dfrac{5}{7}\times1\)

\(=\dfrac{5}{7}\)

b) \(\dfrac{1}{10}+\dfrac{5}{9}+\dfrac{4}{9}+\dfrac{9}{10}-1\)

\(=\left(\dfrac{5}{9}+\dfrac{4}{9}\right)+\left(\dfrac{1}{10}+\dfrac{9}{10}-1\right)\)

\(=1+0\)

\(=1\)

c) \(\dfrac{5}{7}\times\dfrac{5}{9}+\dfrac{4}{9}\times\dfrac{5}{7}+\dfrac{2}{7}\)

\(=\dfrac{5}{7}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)+\dfrac{2}{7}\)

\(=\dfrac{5}{7}+\dfrac{2}{7}\)

\(=1\)

d) \(\dfrac{2}{7}+\dfrac{2}{8}+\dfrac{1}{4}+\dfrac{1}{7}+\dfrac{4}{7}\)

\(=\left(\dfrac{2}{8}+\dfrac{1}{4}\right)+\left(\dfrac{2}{7}+\dfrac{1}{7}+\dfrac{4}{7}\right)\)

\(=\left(\dfrac{1}{4}+\dfrac{1}{4}\right)+1\)

\(=\dfrac{1}{2}+1\)

\(=\dfrac{3}{2}\)

e) \(\dfrac{4}{5}+\dfrac{3}{10}+\dfrac{2}{10}+0,7\)

\(=\dfrac{4}{5}+\dfrac{5}{10}+\dfrac{7}{10}\)

\(=\dfrac{4}{5}+\dfrac{12}{10}\)

\(=\dfrac{4}{5}+\dfrac{6}{5}\)

\(=\dfrac{10}{5}\)

\(=2\)

g) \(362\times728+326\times272\)

\(=326\times\left(728+272\right)\)

\(=326\times1000\)

\(=326000\) 

1: 7-x=8+(-7)

=>7-x=8-7=1

=>x=7-1=6

2: \(x-8=\left(-3\right)-8\)

=>x-8=-11

=>\(x=-11+8=-3\)

3: \(2-x=10-9+23\)

=>\(2-x=33-9=24\)

=>x=2-24=-22

4: \(-2-x=15\)

=>\(x=-2-15=-17\)

5: \(-7+x-8=-3-1+13\)

=>x-14=13-4=9

=>x=9+14=23

6: 100-x+7=-x+3

=>107-x=3-x

=>107=3(vô lý)

7: \(23+x=8-2x\)

=>\(x+2x=8-23\)

=>3x=-15

=>x=-15/3=-5