Bài 6 :

a) \(\dfrac{625}{5^n}=5\Rightarrow\dfrac{5^4}{5^n}=5\Rightarrow5^{4-n}=5^1\Rightarrow4-n=1\Rightarrow n=3\)

b) \(\dfrac{\left(-3\right)^n}{27}=-9\Rightarrow\dfrac{\left(-3\right)^n}{\left(-3\right)^3}=\left(-3\right)^2\Rightarrow\left(-3\right)^{n-3}=\left(-3\right)^2\Rightarrow n-3=2\Rightarrow n=5\)

c) \(3^n.2^n=36\Rightarrow\left(2.3\right)^n=6^2\Rightarrow\left(6\right)^n=6^2\Rightarrow n=6\)

d) \(25^{2n}:5^n=125^2\Rightarrow\left(5^2\right)^{2n}:5^n=\left(5^3\right)^2\Rightarrow5^{4n}:5^n=5^6\Rightarrow\Rightarrow5^{3n}=5^6\Rightarrow3n=6\Rightarrow n=3\)

Bài 7 :

a) \(3^x+3^{x+2}=9^{17}+27^{12}\)

\(\Rightarrow3^x\left(1+3^2\right)=\left(3^2\right)^{17}+\left(3^3\right)^{12}\)

\(\Rightarrow10.3^x=3^{34}+3^{36}\)

\(\Rightarrow10.3^x=3^{34}\left(1+3^2\right)=10.3^{34}\)

\(\Rightarrow3^x=3^{34}\Rightarrow x=34\)

b) \(5^{x+1}-5^x=100.25^{29}\Rightarrow5^x\left(5-1\right)=4.5^2.\left(5^2\right)^{29}\)

\(\Rightarrow4.5^x=4.25^{2.29+2}=4.5^{60}\)

\(\Rightarrow5^x=5^{60}\Rightarrow x=60\)

c) Bài C bạn xem lại đề

d) \(\dfrac{3}{2.4^x}+\dfrac{5}{3.4^{x+2}}=\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{10}}\)

\(\Rightarrow\dfrac{3}{2.4^x}-\dfrac{3}{2.4^8}+\dfrac{5}{3.4^{x+2}}-\dfrac{5}{3.4^{10}}=0\)

\(\Rightarrow\dfrac{3}{2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)+\dfrac{5}{3.4^2}\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)=0\)

\(\Rightarrow\left(\dfrac{1}{4^x}-\dfrac{1}{4^8}\right)\left(\dfrac{3}{2}+\dfrac{5}{3.4^2}\right)=0\)

\(\Rightarrow\dfrac{1}{4^x}-\dfrac{1}{4^8}=0\)

\(\Rightarrow\dfrac{4^8-4^x}{4^{x+8}}=0\Rightarrow4^8-4^x=0\left(4^{x+8}>0\right)\Rightarrow4^x=4^8\Rightarrow x=8\)

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a) \(\frac{16}{2^n}=2\)

=> 2.2ⁿ = 16

=> 2¹⁺ⁿ = 2⁴

=> 1 + n = 4

=> n = 4 - 1

=> n = 3

Vậy n = 3

b) \(\frac{\left(-3\right)^n}{81}=-27\)

=> (-3)ⁿ = -27.81

=> (-3)ⁿ = -3³.3⁴

=> (-3)ⁿ = (-3)⁷

=> n = 7

Vậy n = 7

c) 8ⁿ : 2ⁿ = 4

=> (8 : 2)ⁿ = 4

=> 4ⁿ = 4¹

=> n = 1

Vậy n = 1

a) \(2^n:4=16\Rightarrow2^n:2^2=2^4\Rightarrow2^{n-2}=2^4\Rightarrow n-2=4\Rightarrow n=6\)

b) \(6\cdot2^n+3\cdot2^n=9\cdot2^9\)

=> \(\left(6+3\right)\cdot2^n=9\cdot2^9\)

=> \(9\cdot2^n=9\cdot2^9\Rightarrow n=9\)

c) \(3^n:3^2=243\)

=> \(3^{n-2}=3^5\)

=> n - 2 = 5 => n = 7

d) 25 < 5ⁿ < 3125

=> 5² < 5ⁿ < 5⁵

=> n \(\in\){3;4}

a) \(11^n=1331\)

\(\Rightarrow11^n=11^3\)

\(\Rightarrow n=3\)

b) \(n^3=125\)

\(\Rightarrow n^3=5^3\)

\(\Rightarrow n=5\)

c) \(5^4=n\)

\(\Rightarrow625=n\)

\(\Rightarrow n=625\)

d) \(\left(n+1^2\right)=9\)

\(\Rightarrow n+1=9\)

\(\Rightarrow n=9-1\)

\(\Rightarrow n=8\)

a) 11^n = 1331

⇒ 11^n = 11^3

⇔ n = 3

b) n^ 3 = 125

⇒ n^3 = 5^3

⇔ n = 5

c) 5^4 = n 

⇒ n = 625

d) ( n + 1^2 ) = 9

⇒ ( n + 1 ) = 9

⇒ n = 8 

TL:

a.\(2^6.2^n=2^{11}\) 

 \(2^{6+n}=2^{11}\) 

\(\Rightarrow n=5\) 

b. \(3^7:3^n=3^4\) 

  \(3^{7-n}=3^4\) 

\(\Rightarrow n=3\) 

c.\(2^n.32=2^{10}\)

 \(2^{n+5}=2^{10}\) 

\(\Rightarrow n=5\) 

a

\(^{81^2=\left(3^4\right)^2}\)=\(3^8\)

..........(cần cù thì bù siêng năng chỉ có làm thì mới có ăn, mấy cái loại ko làm mà đòi có ăn thì ăn ĐẦU B**I)

NHÁ ĂN CỨT

a/ \(27^{11}=\left(3^3\right)^{11}=3^{33}\); \(81^8=\left(3^4\right)^8=3^{32}< 3^{33}\Rightarrow81^8< 27^{11}\)

b/ \(3^{2n}=\left(3^2\right)^n=9^n\); \(2^{3n}=\left(2^3\right)^n=8^n< 9^n\Rightarrow2^{3n}< 3^{2n}\)

a. 27¹¹= (3³)¹¹ = 3³³

    81⁸ = (3⁴)⁸ = 3³²

Suy ra 3³³>3³² hay 27¹¹>81⁸

b. 3²ⁿ = (3²)ⁿ = 9ⁿ

     2³ⁿ = (2³)ⁿ = 8ⁿ

Mà 9>8 suy ra 9ⁿ>8ⁿ hay 3²ⁿ>2³ⁿ

c. 5²³ = 5²² . 5

   (6.5)²² = 6²² . 5²²

Vì 6²²>5 suy ra 5²² . 5<6²² . 5²² hay 5²³<(6.5)²²

d. 72⁴⁵-72⁴⁴ = 72⁴⁴(72-1) = 72⁴⁴ . 71

    72⁴⁴-72⁴³ = 72⁴³(72-1) = 72⁴³ . 71

Vì 72⁴⁴>72⁴³ suy ra 72⁴⁴ . 71>72⁴³ . 71 hay 72⁴⁵-72⁴⁴>72⁴⁴-72⁴³

a​)Ta có: 27¹¹=(3³)¹¹=3³³

              81⁸=(3⁴)⁸​=3³²

​vậy 81⁸<27¹¹

\(3^5=32\)                       \(n=5\)

n không tồn tại                  n không tồn tại