1+3+5+...+2x-1=1225
tìm số nguyên x biết
a, 2x+1/3=x-5/2 b, 4(x-2) ^2/3=12
25/30=2x+3/6 -7/x+1=6/x+27
a: =>2x-x=-5/2-1/3
=>x=-17/6
b: =>4(x-2)2=36
=>(x-2)2=9
=>x-2=3 hoặc x-2=-3
hay x=5 hoặc x=-1
c: =>2x+1/2=5/6
=>2x=1/3
hay x=1/6
a: =>2x-x=-5/2-1/3
=>x=-17/6
b: =>4(x-2)2=36
=>(x-2)2=9
=>x-2=3 hoặc x-2=-3
hay x=5 hoặc x=-1
c: =>2x+1/2=5/6
=>2x=1/3
hay x=1/6
a, (2.x-1)+(2.x-2) + (2.x-3) + ........+(2.x-200) = 5+10+15+.......+1000
b, 1+3+5+7+......+ (2x-1) =1225
BT1:
1) 1 + 2 + 3 +..... + X = 1225
2) 2 + 4 + 6 +........ + 2X = 210
1) 1 + 2 + 3 + ... + x = 1225
=> (1 + x).x:2 = 1225
=> (1 + x).x = 1225.2
=> (1 + x).x = 2450
=> (1 + x).x = 50.49 = (-49).(-50)
Vậy \(x\in\left\{50;-49\right\}\)
2) 2 + 4 + 6 + ... + 2x = 210
=> 2.(1 + 2 + 3 + ... + x) = 210
=> 2.(1 + x).x:2 = 210
=> (1 + x).x = 15.14 = (-14).(-15)
Vậy \(x\in\left\{15;-14\right\}\)
a)
\(1+2+......+x=1225\)
\(\Rightarrow\frac{\left(x+1\right)x}{2}=1225\)
\(\Rightarrow\left(x+1\right)x=2450\)
\(\Rightarrow\left(x+1\right)x=49.50\)
=> x = 49
Vậy x = 49
b)
\(2+4+....+2x=210\)
\(\Rightarrow2\left(1+2+....+x\right)=210\)
\(\Rightarrow2.\frac{\left(x+1\right)x}{2}=210\)
\(\Rightarrow x\left(x+1\right)=210\)
\(\Rightarrow x\left(x+1\right)=210\)
\(\Rightarrow x\left(x+1\right)=14.15\)
=> x = 14
Vậy x = 14
1) 1 + 2 + 3 +..... + X = 1225
Đặt A= 1 + 2 + 3 +..... + X
Tổng A có số số hạng theo x là:
\(\left(x-1\right):1+1=x\) (số)
Tổng A theo x là:
\(\left(x+1\right)\cdot x:2=\frac{x^2+x}{2}\)
Thay A vào ta đc:
\(\frac{x^2+x}{2}=1225\)\(\Leftrightarrow x^2+x-2450=0\)
\(\Leftrightarrow x^2-49x+50x-2450=0\)
\(\Leftrightarrow x\left(x-49\right)+50\left(x-49\right)=0\)
\(\Leftrightarrow\left(x-49\right)\left(x+50\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=49\left(tm\right)\\x=-50\left(loai\right)\end{array}\right.\)
2)Đặt B= 2 + 4 + 6 +........ + 2X
Tổng B có số số hạng theo x là:
\(\left(2x-2\right):2+1=x\) (số)
Tổng B theo x là:
\(\left(2x+2\right)\cdot x:2=x^2+x\)
Thay B vào ta dc:
\(x^2+x=210\)\(\Leftrightarrow x^2+x-210=0\)
\(\Leftrightarrow x^2-14x+15x-210=0\)
\(\Leftrightarrow x\left(x-14\right)+15\left(x-14\right)=0\)
\(\Leftrightarrow\left(x+15\right)\left(x-14\right)=0\)
\(\Leftrightarrow\left[\begin{array}{nghiempt}x=14\left(tm\right)\\x=-15\left(loai\right)\end{array}\right.\)
tính hợp ly
A=(1225-1*1)(1225-2*2)(1225-3*3)....(1225-50*50)
1+ 3 + 5 +...+ ( 2n - 1)= 1225
goi bieu thuc tren la S ta co
S=1+3+5+...+(2n-1)=1225
S=(2n-1+1). n :2=2n.2/2=n.n=1225 suy ra n =35
Bài 1 : Tìm x biết:
a)1 + 3 + 5 + ... (2x - 1) = 1225
b)(x + 1 ) + ( x + 2 ) + ... + (x + 100)
c)( 5 -x ) + ( 10 - x ) + (15 - x ) + ... + ( 80 - x) + ( 85 - x)=102
Đag cần gấp , ai lm tk 2 tk nhắ!Mơn
1 + 3 + 5 + .................. + ( 2 x X - 1 ) = 1225
1+3+5+....+(2n-1)= 1225. Tìm n
tim n
1+ 3 + 5 +7 + ...+ (2n - 1) = 1225