a)128-3(x+4)=23 

    125.(x+4)=23

             ( x +4)=23 : 125

             x+4 = 0,184

                x = 0,184 -4

                  x = -3 .816

theo mềnh nhóe ( làm từng câu )

c: =>12x-64=32

=>12x=96

hay x=8

g: =>3x-16=14

hay x=10

e: =>5(x+4)=85

=>x+4=17

hay x=13

\(\left[\left(4x+28\right).3+55\right]:5=35\)

\(\Rightarrow\left(4x+28\right).3+55=35.5\)

\(\Rightarrow\left(4x+28\right).3+55=175\)

\(\Rightarrow\left(4x+28\right).3=175-55\)

\(\Rightarrow\left(4x+28\right).3=120\)

\(\Rightarrow4x+28=120:3\)

\(\Rightarrow4x+28=40\)

\(\Rightarrow4x=40-28\)

\(\Rightarrow4x=12\)

\(\Rightarrow x=12:4\)

\(\Rightarrow x=3\)

[ ( 4x + 28 ). 3 + 55 ] ÷ 5 = 35

( 4x + 28 ). 3 + 55 = 35.5

( 4x + 28 ). 3 + 55 = 175

( 4x + 28 ). 3 = 175 - 55

( 4x + 28 ). 3 = 120

4x + 28 = 120 : 3

4x + 28 = 40

4x = 40 - 28

4x = 12

x = 12 : 4

x = 3

⇒ ( 4x + 28 ) . 3 + 55  = 35 . 5

 ⇒ ( 4x + 28 ) . 3 + 55 = 175

  ⇒ ( 4x + 28 ) . 3 = 175 - 55

  ⇒ ( 4x + 28 ) .3 = 120

   ⇒  4x + 28 = 120 : 3

    ⇒ 4x + 28 = 40

   ⇒  4x = 40 -  28

    ⇒ 4x = 12

     ⇒ x = 12: 4

⇔ x = 3.

Vậy x= 3.

\(\left[\left(4x+28\right)\times3+55\right]\div5=35\)

\(\left(4x+28\right)\times3+55=175\)

\(12x+84+55=175\)

\(12x=175-55-84\)

\(12x=36\)

\(x=3\)

a) 128 - 3(x + 4) = 23

             3(x + 4) = 128 -23

             3(x + 4) = 105

                x + 4  = 105 : 3

                x + 4  = 35

                x        = 35 - 4

                x        = 31

\(a.128-3\left(x+4\right)=23.\)

\(3\left(x+4\right)=128-23\)

\(3\left(x+4\right)=105\)

\(x+4=105:3=35\)

\(x=35-4=31\)

\(b.\left[\left(4x+28\right)\cdot3+55\right]:5=35\)

\(\left(4x+28\right)\cdot3+55=35\cdot5=175\)

\(\left(4x+28\right)\cdot3=175-55=120\)

\(4x+28=120:3=40\)

\(4x=40-28=12\)

\(x=12:4=3\)

a, \(128-3.\left(x+4\right)=23\)

\(\Rightarrow\) \(3.\left(x+4\right)=105\)

\(\Rightarrow\) \(x+4=35\)

\(\Rightarrow\) \(x=31\)

b, \(\left[\left(4x+28\right).3+55\right]:5=35\)

\(\Rightarrow\) \(\left(4x+28\right).3+55=175\)

\(\Rightarrow\) \(\left(4x+28\right).3=120\)

\(\Rightarrow\) \(4x+28=40\)

\(\Rightarrow\) \(4x=12\)

\(\Rightarrow\) \(x=3\)

`@` `\text {Ans}`

`\downarrow`

`b)`

\([(4x+28).3+55] \div 5=35\)

`=> (4x + 28) * 3 + 55 = 35 * 5`

`=> (4x + 28)*3 + 55 = 175`

`=> (4x + 28)*3 = 175 - 55`

`=> (4x + 28)*3 =120`

`=> 4x + 28 = 120 \div 3`

`=> 4x + 28 = 40`

`=> 4x = 40 - 28`

`=> 4x = 12`

`=> x = 12 \div 4`

`=>x = 3`

Vậy, `x = 3.`

=>[12x+84+55]=175

=>12x=175-84-55=120-84=36

=>x=36/12=3

<=>[12x+84+55]:5=35

<=>[12x+139]:5=35

<=>12x+139=35.5

<=>12x=175-139

<=>x=3

[ ( 4X + 28 ) x 3 + 55 ] : 5 = 35

=> ( 4X + 28 ) x 3 + 55 = 175

=> ( 4X + 28 ) x 3 = 120

=> 4X + 28 = 40

=> 4X = 12

=> X = 12 : 4

=> X = 3

[(4x + 28) . 3 + 55] : 5 = 35

=> [(4x + 28) . 3 + 55] = 35 x 5

=> [(4x + 28) . 3 + 55]  = 175

=> (4x + 28) . 3             = 175 - 55

=> (4x + 28) . 3              = 120

=>  4x + 28                     = 120 : 3

=>  4x + 28                     = 40

=>  4x                             = 40 - 28

=>  4x                             = 12

=>    x                              = 12 : 4

=>    x                              = 3

mk có trả lời ở bài b đăng trc nhưng sai đề nhé

kết quả là-11

x=3 nha ban :))))))))))

t i c k nha

mik tính đc 11 bn nha 

[(4x + 28).3 + 55] : 5 = 35

=> (4x + 28).3 + 55 = 175

=> (4x + 28).3 = 120

=> 4x + 28 = 40

=> 4x = 12

=> x = 3

vậy_

a,

128-3x-12=23

3x=128-12-23

3x=93

x=93:3

= 31

b,

(12x+84+55):5=35

12x+84+55=35.5

12x+84+55=175

12x=175-55-84

12x=36

x=36:12

x=3