ta có : (ghi lại đề)

=6+12+18+24+30/3+6+9+12+15

=2*(3/3+6/6+9/9+12/12+15/15)

=2*(1+1+1+1+1)

=2*5=10

chúc main học tốt nhé

hi

trl sẽ có like

a=8x3x6x4x(427+573)

a=8x3x6x4x1000

a=576000

a)

`1/3+3/4+2/3+1/4`

`=1/3+2/3+3/4+1/4`

`=1+1`

`=2`

b)

`3/4+3/5+2/8+4/10`

`=3/4+2/8+3/5+4/10`

`=6/8+2/8+6/10+4/10`

`=1+1`

`=2`

c)

`1/10+2/10+3/10+4/10+5/10+6/10+7/10+8/10+9/10`

`=1/10+9/10+2/10+8/10+3/10+7/10+6/10+4/10+5/10`

`=1+1+1+1+5/10`

`=4+5/10`

`=40/10+5/10`

`=45/10=9/2`

a: =1/3+2/3+3/4+1/4

=1+1

=2

b: =3/4+1/4+3/5+2/5

=1+1

=2

c: =(1+2+3+4+5+6+7+8+9)/10

=45/10

=9/2

\(M=1-\left(\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}\right)\)

\(=1-\left(\dfrac{3}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}\right)\)

\(=1-\left(\dfrac{7}{8}+\dfrac{1}{16}+\dfrac{1}{32}\right)\)

\(=1-\left(\dfrac{15}{16}+\dfrac{1}{32}\right)\)

\(=1-\dfrac{31}{32}=\dfrac{1}{32}\)

a) \(\dfrac{3}{7}-\dfrac{4}{11}-\dfrac{3}{7}\)

=\(\left(\dfrac{3}{7}-\dfrac{3}{7}\right)-\dfrac{4}{11}\)

\(=-\dfrac{4}{11}\)

b) \(-\dfrac{5}{11}+\dfrac{3}{8}-\dfrac{6}{11}\)

\(=\left(-\dfrac{5}{11}-\dfrac{6}{11}\right)+\dfrac{3}{8}\)

\(=-1+\dfrac{3}{8}=-\dfrac{8}{8}+\dfrac{3}{8}=-\dfrac{5}{8}\)

c) \(\dfrac{3}{4}-\dfrac{1}{3}-\dfrac{11}{4}\)

\(=\left(\dfrac{3}{4}-\dfrac{11}{4}\right)-\dfrac{1}{3}\)

\(=-2-\dfrac{1}{3}=-\dfrac{6}{3}-\dfrac{1}{3}=-\dfrac{7}{3}\)

`a, 3/7 -4/11-3/7`

`=(3/7-3/7)-4/11`

`= 0/7-4/11`

`= -4/11`

__

`b, -5/11 +3/8 -6/11`

`=(-5/11-6/11)+3/8`

`=-11/11 + 3/8`

`= -1+3/8`

`= -8/8+3/8`

`=- 5/8`

__

`c,3/4 -1/3-11/4`

`=(3/4-11/4)-1/3`

`= -8/4-1/3`

`=-2-1/3`

`= -6/3-1/3`

`=-7/3`

Ta có: \(A=\left(1-\dfrac{1}{2}\right)\left(1-\dfrac{1}{3}\right)\left(1-\dfrac{1}{4}\right)\cdot...\cdot\left(1-\dfrac{1}{9}\right)\)

\(=\dfrac{1}{2}\cdot\dfrac{2}{3}\cdot\dfrac{3}{4}\cdot\dfrac{4}{5}\cdot...\cdot\dfrac{8}{9}\)

\(=\dfrac{1}{9}\)

a: =(375-175)+(369-169)+...+(207-7)

=200+200+...+200

=200*[(375-207)/2+1]

\(=200\cdot85=17000\)

b: \(=\left(24-11\right)+\left(32-19\right)+\left(40-27\right)+...+\left(336-323\right)\)

\(=13\cdot\left[\left(336-24\right):8+1\right]=13\cdot40=520\)

c: \(=\left(5-2\right)+\left(8-4\right)+\left(11-6\right)+...+\left(140-92\right)\)

=3+4+5+...+48

Số số hạng là (48-3):1+1=45+1=46(số)

Tổng là: (48+3)*46/2=51*23=1173

d: \(=\left(300-285\right)+\left(295-278\right)+\left(290-271\right)+...+\left(100-5\right)+10\)

=15+17+19+...+95+10

Số số lẻ trong khoảng từ 15 đến 95 là:

(95-15):2+1=41(số)

Tổng của dãy số trên là:

10+(95+15)*41/2

=10+55*41

=2265

a: =17-70-163+246

=-43-163+246

=246-206

=40

Ai giải giùm mình với

Mình đang cần gấp