(x+5)^3 = -64
Tìm x:
a, (-3 / 4) ^ 3x-1 = -27 / 64
b, (4/5) ^ 2x+5 = 256 / 625
c, (x+3) ^5 / (x+2) ^2 = 64 / 27
d, x-1 / x+5 = 6/7
(-3/4)63x-1=(3/4)^3
3x-1=3+1
3x=3=1
x=4;3
x=4/3
Vậy x=4/3
(x-5)^3=-64
\(\Leftrightarrow x-5=-4\)
\(\Leftrightarrow x=-4+5=1\)
Vậy ...
(x - 5)3 = - 64
\(\Rightarrow\) (x - 5)3 = - 64 = (- 4)3
\(\Rightarrow\) x - 5 = - 4
\(\Rightarrow\) x = 1
Vậy x = 1
(x - 5)3 = -64
=> x - 53 = -64
=> x - 125 = -64
=> x = -64 + 125
=> x = 61
(x+5)\(^3\)=-64
\(\left(x+5\right)^3=-64=\left(-4\right)^3\\ Vậy:x+5=-4\\Vậy:x=-4-5=-9 \)
\(\left(x+5\right)^3=-64\)
\(\Rightarrow\left(x+5\right)^3=\left(-4\right)^3\)
\(\Rightarrow x+5=-4\)
\(\Rightarrow x=-4-5\)
\(\Rightarrow x=-9\)
Vậy: \(x=-9\)
(x - 5)3 = 64
(x-5)3=64=43
=>x-5=4
=>x=4+5=9
Vậy x=9
Tìm x biết 1+3 +5+...+x =64
A. 9
B. 11
C. 15
D. 17
Tìm x:
a) (2x/3 - 3) : (-10) = 2/5
b) (x + 5)^3 = 64
a) \(\left(\frac{2x}{3}-3\right)\div\left(-10\right)=\frac{2}{5}\)
\(\Rightarrow\left(\frac{2x}{3}-\frac{9}{3}\right).-\frac{1}{10}=\frac{2}{5}\)
\(\Rightarrow\frac{2x-9}{3}.-\frac{1}{10}=\frac{2}{5}\)
\(\Rightarrow\frac{9-2x}{30}=\frac{2}{5}\Rightarrow\left(9-2x\right).5=60\)
\(\Rightarrow45-10x=60\Rightarrow-10x=15\Rightarrow x=-\frac{15}{10}=-1,5\)
b)\(\left(x+5\right)^3=64\)
\(\Rightarrow\left(x+5\right)^3=4^3\)
\(\Rightarrow x+5=4\Rightarrow x=-1\)
A, 2x/3-3=-4
2x/3=-1
2x=-3
X=-3/2
B,(x+5)^3=4^3
=> x+5=4
X=-1
k nha
(64-X^3).(5^X-25)=0.tìm x
Tìm x,biết :
a) (x+5)3=-64 b) (2x-3)2=9
\(a.\left(x+5\right)^3=-64\Leftrightarrow x+5=-4\Leftrightarrow x=-9\\ b.\left(2x-3\right)^2=9\Leftrightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\)
( Nhớ kết luận! )
a.
\(\left(x+5\right)^3=\left(-4\right)^3\)
\(\Leftrightarrow x+5=-4\)
\(\Leftrightarrow x=-9\)
b.
\(\left(2x-3\right)^2=3^2\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}2x=6\\2x=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\)
a)(x+5)3=−64
\(\left(x+5\right)^3=\left(-4\right)^3\)
x+5=−4
x=−4−5=-9
Vậy x=−9
b)(2x−3)3=8(9 không được)
\(\left(2x-3\right)^3=2^3\)
2x−3=2
2x=5
x\(=\dfrac{5}{2}\)
P/s Nhớ tick cho mình nha. Thanks bạn
1.Tìm x biết
a,2^x=128 b,8^x-1=64
c,3+3^x=30 d,(x+2)=64
e,3^2.x=3^5 f,(2x-1^3)=343
Giải nhanh giúp mik vs mik sắp đi hc r ai nhanh mik tick cho
1.
a) \(2^x=128\)
\(2^x=2^7\)
\(=>x=7\)
b) \(8^{x-1}=64\)
\(8^{x-1}=8^2\)
\(=>x-1=2\)
\(x=2+1\)
\(=>x=3\)
c) \(3+3^x=30\)
\(3^x=30-3\)
\(3^x=27=3^3\)
\(=>x=3\)
d) \(\left(x+2\right)=64\) -> đề có thiếu không vậy?
e) \(3^2.x=3^5\)
\(x=3^5:3^2\)
\(=>x=3^3=27\)
f) \(\left(2x-1\right)^3=343\)
\(\left(2x-1\right)^3=7^3\)
\(=>2x-1=7\)
\(2x=7+1\)
\(2x=8\)
\(x=8:2\)
\(=>x=4\)
\(#Wendy.Dang\)
a,\(2^x\)=128 b,\(8^{x-1}\)=64 c,3+\(3^x\)=30 d,x+2=64
\(2^7\)=128 \(8^{x-1}\)=\(8^2\) \(3^x\)=30-3 x=64-2
=>x=7 =>x-1=2 \(3^x\)=27 x=62
x=2+1=3 \(3^x\)=\(3^3\)
=>x=3
e,\(3^2\).x=\(3^5\) f,(2x-\(1^3\))=343
x=\(3^5\):\(3^2\) 2x=1+343
x=27 2x=344
x=344:2
x=172