tìm x :
a, x + 5 = 25 - x
b ,x - 15 + 10 = 50
Tìm x, biết:
a) x-(-25+x)=13-x
b) 15-(30+x)=x-(27-l-8l)
c) (12x-43).83=4.84
a) x-(-25+x)=13-x
⇒ x+25-x=13-x
⇒ 13-x=25
⇒ x= -12
b) 15-(30+x)=x-(27-l-8l)
⇒ 15-30-x=x-(27-8)
⇒ -15-x=x-19
⇒ -x-x=-19+15
⇒ -2x+4=0
⇒ -2x=-4
⇒ x=2
c) (12x-43).83=4.84
⇒ 12x.83-43.83=4.84
⇒ 6144x-32768=16384
⇒ 6144x=49152
⇒ x=8
a: Ta có: \(x-\left(-25+x\right)=13-x\)
\(\Leftrightarrow13-x=25\)
hay x=-12
b: Ta có: \(15-\left(30+x\right)=x-\left(27-\left|-8\right|\right)\)
\(\Leftrightarrow-15-x=x-19\)
\(\Leftrightarrow-2x=-4\)
hay x=2
c: Ta có: \(\left(12x-4^3\right)\cdot8^3=4\cdot8^4\)
\(\Leftrightarrow\left(12x-64\right)\cdot512=16384\)
\(\Leftrightarrow12x-64=32\)
hay x=8
Tìm x bằng quy tắc chuyển vế:
a) (-25) + 15+x=50
b) (-25) + 15+x= -35
c) (-25) + 15+x= -10
a)(-25)+15+x=50
(-10)+x=50
x=50-(-10)
x=50+10
x=60
b)(-25)+15+x=-35
(-10)+x=-35
x=(-35)-(-10)
x=(-35)+10
x=-25
c)(-25)+15+x=-10
(-10)+x=-10
x=-10-(-10)
x=-10+10
x=0
a) x = 50 + 25 - 15 = 60
b) x = -35 + 25 - 15 = -25
c) x = -10 + 25 - 15 = 0
a x e x
b x f x
c x x
2
3
2 1 1 1 17 26
3 2 10 5 25 25
4 2 5 7 24
2 50 51 1 3
5 3 27 9 27
1 2
2 0
2 3 ) :
) ) ,
g x
d x h x x
3 1
1 4
7 28
17 3 7 2 7
2 0 5
2 4 4 3 12
Tìm x :
a, x - ( 27 + 50 ) - ( -37 - 36 ) = 34
b, 25 - ( x + 8 ) - ( 15 + 10 ) = 36 + 10
a,x-77-(-73)=34
x-77 =34+(-73)
x-77 =-39
x =(-39)+77
x =38
b,25-(x+8)-25=46
25-(X+8) =46-25
25-(x+8) =21
x+8 =25-21
x+8 =4
x =4-8
x =-4
25 . 15 + 75 . 45
-10 . 25 - 10 . 75 + 10 . 50
3^x-2 - 2^3 = 19
(2 x - 5)^3 = - 64
2(x-1)^2 + 3 = 35
125 - 25 (x + 3) = 50
2(x+ 3) - 1x = 4
a: =25(15+45*3)
=25*150
=3750
b: \(=-10\left(25+75-50\right)=-10\cdot50=-500\)
c: =>3^x-2=27
=>x-2=3
=>x=5
d: =>2x-5=-4
=>2x=1
=>x=1/2
e: =>2(x-1)^2=32
=>(x-1)^2=16
=>x-1=4 hoặc x-1=-4
=>x=-3 hoặc x=5
f: =>25(x+3)=75
=>x+3=3
=>x=0
A) 35 ⋮ x
B) 15 ⋮ x
C) x ⋮ 25 và x < 100
D) x + 16 ⋮ x + 1
a) \(x\in\left\{1;-1;5;-5;7;-7;35;-35\right\}\)
b) \(x\in\left\{1;-1;3;-3;5;-5;15;-15\right\}\)
c) \(x\in\left\{0;25;50;75\right\}\)
d) Ta có: \(x+16⋮x+1\)
nên \(15⋮x+1\)
\(\Leftrightarrow x+1\in\left\{1;-1;3;-3;5;-5;15;-15\right\}\)
hay \(x\in\left\{0;-2;2;-4;4;-6;14;-16\right\}\)
a) 35 \(⋮\) x \(\Rightarrow\) x \(\in\) Ư(35) = {\(\pm1;\pm5;\pm7;\pm35\)}
b) 15 \(⋮\) x \(\Rightarrow\) x \(\in\) Ư(15) = {\(\pm1;\pm3;\pm5;\pm15\)}
c) x \(⋮\) 25 \(\Rightarrow\) x \(\in\) B(25) = {\(0;25;50;75;100;...\)}
Mà x < 100 \(\Rightarrow\) x \(\in\){\(0;25;50;75\)}
d) x + 16 \(⋮\) x + 1
\(\Rightarrow\) x + 16 - (x + 1) \(⋮\) x + 1
\(\Rightarrow\) 15 \(⋮\) x + 1
\(\Rightarrow\) x + 1 \(\in\) Ư(15) = {\(\pm1;\pm3;\pm5;\pm15\)}
\(\Rightarrow\) x \(\in\) {\(0;-2;2;-4;4;-6;14;-16\)}
Rút gọn A=\(\left(\frac{5\sqrt{x}+50}{x+5\sqrt{x}}+\frac{2\sqrt{x}-10}{\sqrt{x}}+\frac{x}{5\sqrt{x}+25}\right).\frac{7}{15+3\sqrt{x}}\)
bài 1 :tìm x
a,245-5.(16+x)=140
b,(x-1954).5=50
c,30.(60-x)=30
d,[(250-25):15]:x=(450-60):130
e,x:[(1800+600)]=560:(315-35)
f,x.(x+1)=2+4+6+8+10+.......................+2500
a, 245 - 5 . ( 16 + x ) = 140
5 . ( 16 + x ) = 245 - 140
5 . ( 16 + x ) = 145
16 + x = 145 : 5
16 + x = 29
x = 29 - 16
x = 13 .
b, ( x - 1945 ) . 5 = 50
x - 1945 = 50 : 5
x - 1945 = 10
x = 10 + 1945
x = 1955 .
c, 30 . ( 60 - x ) = 30
60 - x = 30 : 30
60 - x = 1
x = 60 - 1
x = 59 .
d, [ ( 250 - 25 ) : 15 ] : x = ( 450 - 60 ) : 130
[ 225 : 15 ] : x = 390 : 130
15 : x = 3
x = 15 : 3
x = 5 .
e, x : [ ( 1800 + 600 ) ] = 560 : ( 315 - 35 )
x : 2400 = 560 : 280
x : 2400 = 2
x = 2 . 2400
x = 4800 .
f, x . ( x + 1 ) = 2 + 4 + 6 + 8 + 10 + ... + 2500
2 + 4 + 6 + 8 + 10 + ... + 2500
Số số hạng của dãy số trên là :
( 2500 - 2 ) : 2 + 1 = 1250 ( số hạng )
=> 2 + 4 + 6 + 8 + 10 + 2500
= ( 2 + 2500 ) . 1250 : 2
= 2502 . 1250 : 2
= 3127500 : 2
= 1563750 .
Ta có :
x . ( x + 1 ) = 1563750
Mà : 1563750 = 1250 . 1251
=> x = 1250 .
Tìm x :
a) ( 2.x - 40 ) : 10 = -55
b) (2.x + 15) : 5= -40
c) ( 2.x - 72) : 8 = 25
\(a,\left(2\times x-40\right):10=-55\)
\(2\times x-40=-55\times10\)
\(2\times x-40=-550\)
\(2\times x=-550+40\)
\(2\times x=-510\)
\(x=-510:2\)
\(\Rightarrow x=-255\)
\(b,\left(2\times x+15\right):5=-40\)
\(2\times x+15=-40\times5\)
\(2\times x+15=-200\)
\(2\times x=-200-15\)
\(2\times x=-215\)
\(x=-215:2\)
\(\Rightarrow x=-\dfrac{215}{2}\)
\(c,\left(2\times x-72\right):8=25\)
\(2\times x-72=25\times8\)
\(2\times x-72=200\)
\(2\times x=200+72\)
\(2\times x=272\)
\(x=272:2\)
\(\Rightarrow x=136\)
a. ( 2.x - 40 ) ÷ 10 = -55
2.x - 40 = (-55) × 10
2.x - 40 = -550
2.x = (-550) + 40
2.x = -510
x = (-510) ÷ 2
x = -255
b. ( 2.x + 15 ) ÷ 5 = -40
2.x + 15 = (-40) × 5
2.x + 15 = -200
2.x = (-200 ) - 15
2.x = -215
x = (-215) ÷ 2
x = -107,5
c. ( 2.x - 72 ) ÷ 8 = 25
2.x - 72 = 25 × 8
2.x - 72 = 200
2.x = 200 + 72
2.x = 272
x = 272 ÷ 2
x = 136