\(I=100mA=0,1A\)

\(l=200cm=2m\)

Lực từ tác dụng lên dây dẫn:

\(F=B\cdot I\cdot l\cdot sin\alpha\)

\(\Rightarrow F=4\cdot10^{-2}\cdot0,1\cdot2=8\cdot10^{-3}N\)

a: \(125\left(19-135\right)-135\left(19-125\right)\)

\(=125\cdot19-125\cdot135-135\cdot19+135\cdot125\)

\(=125\cdot19-135\cdot19\)

\(=19\left(125-135\right)=-10\cdot19=-190\)

b: \(\left(-125\right)\left(135-19\right)-135\left(19-135\right)\)

\(=-125\cdot135+125\cdot19-135\cdot19+135^2\)

\(=135^2-135\cdot125+125\cdot19-135\cdot19\)

\(=135\left(135-125\right)+19\left(125-135\right)\)

\(=135\cdot10-19\cdot10\)

\(=116\cdot10=1160\)

c: \(125\left(19-135\right)+135\left(125-19\right)\)

\(=125\cdot19-125\cdot135+135\cdot125-135\cdot19\)

\(=125\cdot19-135\cdot19\)

\(=19\left(125-135\right)=19\cdot\left(-10\right)=-190\)

d: \(146\left(46-259\right)+259\left(146-46\right)\)

\(=146\cdot46-146\cdot259+259\cdot146-259\cdot46\)

\(=146\cdot46-259\cdot46\)

\(=46\left(146-259\right)\)

\(=46\cdot\left(-113\right)=-5198\)

e: \(195\left(17-185\right)-185\left(17-185\right)\)

\(=195\cdot17-195\cdot185-185\cdot17+185^2\)

\(=\left(195\cdot17-185\cdot17\right)-\left(195\cdot185-185^2\right)\)

\(=17\left(195-185\right)-185\left(195-185\right)\)

\(=10\left(17-185\right)=-168\cdot10=-1680\)

g: \(\left(-146\right)\left(19-156\right)+156\left(19-146\right)\)

\(=-146\cdot19+146\cdot156+156\cdot19-156\cdot146\)

\(=156\cdot19-146\cdot19=19\left(156-146\right)=190\)

h: \(\left(-243\right)\left(25-763\right)+763\left(25-243\right)\)

\(=-243\cdot25+243\cdot763+763\cdot25-763\cdot243\)

\(=763\cdot25-243\cdot25\)

\(=25\left(763-243\right)=520\cdot25=13000\)

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# Study

1) copy nhấn phím ctrl and v

2) xóa nhấn phím mũi tên <

ctrl+c=copy

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\(a,=x^2+x+4x+4=\left(x+1\right)\left(x+4\right)\\ b,=x^2+2x-3x-6=\left(x-3\right)\left(x+2\right)\\ c,=x^2-2x-3x+6=\left(x-2\right)\left(x-3\right)\\ d,=3\left(x^2-2x+5x-10\right)=3\left(x-2\right)\left(x+5\right)\\ e,=-3x^2+6x-x+2=\left(x-2\right)\left(1-3x\right)\\ f,=x^2-x-6x+6=\left(x-1\right)\left(x-6\right)\\ h,=4\left(x^2-3x-6x+18\right)=4\left(x-3\right)\left(x-6\right)\\ i,=3\left(3x^2-3x-8x+5\right)=3\left(x-1\right)\left(3x-8\right)\\ k,=-\left(2x^2+x+4x+2\right)=-\left(2x+1\right)\left(x+2\right)\\ l,=x^2-2xy-5xy+10y^2=\left(x-2y\right)\left(x-5y\right)\\ m,=x^2-xy-2xy+2y^2=\left(x-y\right)\left(x-2y\right)\\ n,=x^2+xy-3xy-3y^2=\left(x+y\right)\left(x-3y\right)\)

Bào quan riboxom trong chất tế bào có chức năng gì? 

a) \(=\left(x^2+x\right)+\left(4x+4\right)=x\left(x+1\right)+4\left(x+1\right)=\left(x+1\right)\left(x+4\right)\)

b) \(=\left(x^2+2x\right)-\left(3x+6\right)=x\left(x+2\right)-3\left(x+2\right)=\left(x+2\right)\left(x-3\right)\)

c) \(=\left(x^2-2x\right)-\left(3x-6\right)=x\left(x-2\right)-3\left(x-2\right)=\left(x-2\right)\left(x-3\right)\)

d) \(3x^2+9x-30=3\left(x^2+3x-10\right)=3\left[\left(x^2+5x\right)-\left(2x+10\right)\right]=3\left[x\left(x+5\right)-2\left(x+5\right)\right]=3\left(x-2\right)\left(x+5\right)\)

e) \(=-\left(3x^2-5x-2\right)=-\left[\left(3x^2-6x\right)+\left(x-2\right)\right]=-\left[3x\left(x-2\right)+\left(x-2\right)\right]=-\left(3x+1\right)\left(x-2\right)\)

f) \(x^2-7x+6=\left(x^2-x\right)-\left(6x-6\right)=x\left(x-1\right)-6\left(x-1\right)=\left(x-1\right)\left(x-6\right)\)

h) \(=4\left(x^2-9x+14\right)=4\left[\left(x^2-7x\right)-\left(2x-14\right)\right]=4\left[x\left(x-7\right)-2\left(x-7\right)\right]=4\left(x-2\right)\left(x-7\right)\)

i) \(=3\left(3x^2-8x+5\right)=3\left[\left(3x^2-3x\right)-\left(5x-5\right)\right]=3\left[3x\left(x-1\right)-5\left(x-1\right)\right]=3\left(x-1\right)\left(3x-5\right)\)

k) \(=-\left(2x^2+5x+2\right)=-\left[\left(2x^2+4x\right)+\left(x+2\right)\right]=-\left[2x\left(x+2\right)+\left(x+2\right)\right]=-\left(x+2\right)\left(2x+1\right)\)

l) \(=\left(x^2-5xy\right)-\left(2xy-10y^2\right)=x\left(x-5y\right)-2y\left(x-5y\right)=\left(x-5y\right)\left(x-2y\right)\)

m) \(=\left(x^2-2xy\right)-\left(xy-2y^2\right)=x\left(x-2y\right)-y\left(x-2y\right)=\left(x-2y\right)\left(x-y\right)\)

n) \(=\left(x^2-3xy\right)+\left(xy-3y^2\right)=x\left(x-3y\right)+y\left(x-3y\right)=\left(x+y\right)\left(x-3y\right)\)

6 đội,16 người

người ta mới học lớp 3 thôi

Em muốn lấy đầy đủ cả bài hay chỉ những phần học ở lớp 9 vậy

\(BC=\sqrt{8^2+5^2}=\sqrt{89}\approx9,4\left(cm\right)\)