tính bằng cách thuận tiênj nhất
1/2+1/4+1/16+1/32+1/64
tính bằng cách thuận tiện nhất B 1/2+1/4+1/8+1/16+1/32+1/64
1/2+1/4+1/8+1/16+1/32+1/64
=(1/2+1/4+1/8)+(1/16+1/32+1/64)
=(4/8+2/8+1/8)+(4/64+2/64+1/64)
=7/8+7/64
=56/64+7/64
=63/64
B = \(\dfrac{1}{2}\) + \(\dfrac{1}{4}\) + \(\dfrac{1}{8}\) + \(\dfrac{1}{16}\) + \(\dfrac{1}{32}\) + \(\dfrac{1}{64}\)
2 x B = 1 + \(\dfrac{1}{2}\)+ \(\dfrac{1}{4}\) + \(\dfrac{1}{8}\) + \(\dfrac{1}{16}\)+ \(\dfrac{1}{32}\)
2 x B - B = 1 - \(\dfrac{1}{64}\)
B = \(\dfrac{63}{64}\)
tính bằng cách thuận tiện nhất
A=1/2 + 1/4 + 1/8 + 1/16+ 1/32 + 1/64
đặt `A= 1/2 + 1/4 + 1/8 + 1/16+ 1/32 + 1/64`
`=> 2A = 2(1/2 + 1/4 + 1/8 + 1/16+ 1/32 + 1/64)`
`2A = 1+1/2 +1/4 +1/8+1/16 +1/32`
`=>A =2A -A =1+1/2 +1/4 +1/8+1/16 +1/32-1/2-1/4-1/8-1/16-1/32 -1/64`
`A = 1-1/64 = 64/64 -1/64 =63/64`
tính bằng cách thuận tiện nhất:
1/2+1/4+1/8+1/16+1/32+1/64+1/128+1/256
Đặt A = 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256
=> 2A = 1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128
=> 2A - A = (1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128) - (1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256)
=> A = 1 - 1/256
=> A = 255/256
Vậy: ...
tính bằng cách thuận tiện nhất
1\2+1\4+1\8+1\16+1\32+1\64
voi lai phan so sau hon phan so truoc la 2 doi vi anh nhat linh a?
qua don giai lop bon da hoc roi goi y cho
buoc 1 : Dat A
buoc 2:nhan ca hai ve voi N
buoc 3: tru ca hai ve cho nhau
tính tổng các phân số sau bằng cách thuận tiện nhất:
1/2, 1/4, 1/8, 1/16, 1/32, 1/64
Tính bằng cách thuận tiện nhất chỉ cần đáp án thôi nhé.
1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256
tính bằng cách thuận tiện nhất
1/2 + 1/3 +1/4 +1/5 +4/5 +3/4 + 2/3 + 1/2
1/2 + 1/3 + 1/4 + 1/5 + 4/5 + 3/4 + 2/3 + 1/2
= (1/2 + 1/2) + (1/3 + 2/3) + (1/4 + 3/4) + (1/5 + 4/5)
= 1 + 1 + 1 + 1
= 4
Tính bằng cách thuận tiện:
a.A=1/2+1/4+1/8+1/16+1/32+1/64
b.B=1/3+1/9+1/27+1/81+1/243
\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+\frac{1}{16}-\frac{1}{32}+\frac{1}{32}-\frac{1}{64}\)
\(A=1-\frac{1}{64}\)
\(A=\frac{63}{64}\)
\(B=\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}+\frac{1}{243}\)
\(3B=1+\frac{1}{3}+\frac{1}{9}+\frac{1}{27}+\frac{1}{81}\)
\(3B-B=1-\frac{1}{243}\)
\(2B=\frac{242}{243}\)
\(B=\frac{242}{243}\div2\)
\(B=\frac{121}{243}\)
a.A=1/2+1/4+1/8+1/16+1/32+1/64
A= \(\frac{1}{1\cdot2}+\frac{1}{2\cdot2}+\frac{1}{2\cdot4}+\frac{1}{4\cdot4}+\frac{1}{4\cdot8}+\frac{1}{8\cdot8}\)
= \(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{8}\)
= 1 - 1/8 = 7/8
b.B=1/3+1/9+1/27+1/81+1/243
B= \(\frac{1}{1\cdot3}+\frac{1}{3\cdot3}+\frac{1}{3\cdot9}+\frac{1}{9\cdot9}+\frac{1}{9\cdot27}\)
= 1 - 1/27 = 26/27
1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 ( Tính bằng 2 cách )