(x+20):(x-10)=(x+40):(x+70)
Tìm x (x-20):(x-10)=(x+40):(x+70)
ĐKXĐ: \(\hept{\begin{cases}x\ne10\\x\ne-70\end{cases}}\)
\(\frac{x-20}{x-10}=\frac{x+40}{x+70}\)
\(\Rightarrow\left(x-20\right)\left(x+70\right)=\left(x+40\right)\left(x-10\right)\)
\(\Rightarrow x^2+70x-20x-1400=x^2-10x+40x-400\)
\(\Rightarrow20x=1000\Rightarrow x=50\)
Vậy x = 50
Tìm x, biết: (x-20):(x-10)=(x+40):(x+70)
\(\frac{x-20}{x-10}=\frac{x+40}{x+70}=\frac{-20-40}{-10-70}=\frac{6}{8}=\frac{3}{4}.\)
\(\Rightarrow4\cdot\left(x-20\right)=3\cdot\left(x-10\right)\Leftrightarrow4x-80=3x-30\Leftrightarrow x=50.\)
bn dinh thuy linh gioi that, toàn dung ngôn ngữ toán hoc nên bai lam rat ấn tuong
Tìm x biết:
(x-20)÷(x-10)=(x+40)÷(x+70)
\(\frac{x-20}{x-10}=\frac{x+40}{x+70}\)
\(\Rightarrow\left(x-20\right)\left(x+70\right)=\left(x-10\right)\left(x+40\right)\)
\(\Rightarrow x^2+70x-20x-1400=x^2+40x-10x-400\)
\(\Rightarrow x^2+70x-20x-x^2-40x+10x=1400-400\)
\(\Rightarrow20x=1000\Rightarrow x=50\)
Tính nhẩm:
a) 10 x 7 20 x 4 40 x 2 30 x 3
b) 60 : 2 90 : 3 70 : 7 40 : 2
a) 10 x 7 = ? Nhẩm: 1 chục x 7 = 7 chục 10 x 7 = 70 20 x 4 = ? Nhẩm: 2 chục x 4 = 8 chục 20 x 4 = 80 40 x 2 = ? Nhẩm: 4 chục x 2 = 8 chục 40 x 2 = 80 30 x 3 = ? Nhẩm: 3 chục x 3 = 9 chục 30 x 3 = 90 | b) 60 : 2 = ? Nhẩm: 6 chục : 2 = 3 chục 60 : 2 = 30 90 : 3 = ? Nhẩm: 9 chục : 3 = 3 chục 90 : 3 = 30 70 : 7 = ? Nhẩm: 7 chục : 7 = 1 chục 70 : 7 = 10 40 : 2 = ? Nhẩm: 4 chục : 2 = 2 chục 40 : 2 = 20 |
\(\frac{x-20}{x-10}=\frac{x+40}{x+70}\)
\(\frac{x-20}{x-10}=\frac{x+40}{x+70}\)
\(\Leftrightarrow\left(x-20\right)\left(x+70\right)=\left(x-10\right)\left(x+40\right)\)
\(\Leftrightarrow x^2+70x-20x-140=x^2+40x-10x-140\)
\(\Leftrightarrow50x=30x\)
\(\Leftrightarrow50x-30x=0\)
\(\Leftrightarrow20x=0\)
\(\Leftrightarrow x=0\)
Chết , sửa chút !!! Nhân ngu wá
\(\frac{x-20}{x-10}=\frac{x+40}{x+70}\)
\(\Leftrightarrow\left(x-20\right)\left(x+70\right)=\left(x-10\right)\left(x+40\right)\)
\(\Leftrightarrow x^2+70x-20x-140=x^2+40x-10x-400\)
\(\Leftrightarrow20x+260=0\)
\(\Leftrightarrow x=-13\)
Incursion_03 :>
\(\frac{x-20}{x-10}=\frac{x+40}{x+70}\)
\(\Rightarrow\left(x-20\right).\left(x+70\right)=\left(x-10\right).\left(x+40\right)\)
\(\Rightarrow x^2+50x-1400=x^2+30-400\)
\(\Rightarrow20x=1000\Rightarrow x=50\)
a, (7,5-x):(3,5+x)=5:6
b, (x-20):(x-10)=(x+40):(x+70)
a, \(\left(7,5-x\right):\left(3,5+x\right)=5:6\)
\(\Leftrightarrow\frac{7,5-x}{3,5+x}=\frac{5}{6}\)
\(\Leftrightarrow6.\left(7,5-x\right)=5.\left(3,5+x\right)\)
\(\Leftrightarrow45-6x=17,5+5x\)
\(\Leftrightarrow45-17,5=5x+6x\)
\(\Leftrightarrow27,5=11x\)
\(\Leftrightarrow x=\frac{27,5}{11}=2,5\)
Vậy : \(x=2,5\)
b) Tương tự như câu a.
Chúc bạn học tốt nhé !!
Tìm x biết:
(x - 20) : ( x + 40)= ( x -10) : ( x +70)
Tìm x, biết:
a) (x+15) : x = 4:3
b) (x-20) : (x-10) = (x+40) : (x+70)
a) (x + 15) : x = 4 : 3
=> x : x + 15 : x = \(\frac{4}{3}\)
=> 1 + 15 : x = \(\frac{4}{3}\)
=> 15 : x = \(\frac{4}{3}\)- 1 = \(\frac{1}{3}\)
=> x = 15 : \(\frac{1}{3}\)
=> x = 45
phượng quyên là otaku sa( hình đại diện so cute)
bài 1
a,(x+7) :x=4:5
b,(x-20):(x+40)=(x+70):(x-10)