1/4 + 5/6
>, <, = ?
| 3 + 4 … 6 | 6 + 1 … 6 | 5 + 1 … 6 |
| 3 + 4 … 7 | 5 + 2 … 6 | 7 – 5 … 3 |
| 7 – 4 … 4 | 7 – 2 … 5 | 7 – 6 … 1 |
Lời giải chi tiết:
| 3 + 4 > 6 | 6 + 1 > 6 | 5 + 1 = 6 |
| 3 + 4 = 7 | 5 + 2 > 6 | 7 – 5 > 3 |
| 7 – 4 < 4 | 7 – 2 = 5 | 7 – 6 = 1 |
2/5+2/3+3/4
2/6+3/12
5/6+1/3
1/3+5/12+5/6
5/8+4/7
1/5+5/35
5/8+3/4
1/6+1/3+1/12
1/6+5/24+2/3
7/3+8/7
2/5+1/6
1/7+1/4+6/7+3/4
giúp với
và ai giải được gọi cụ
\(\dfrac{2}{5}+\dfrac{2}{3}+\dfrac{2}{4}\)
= \(\dfrac{24}{60}\) + \(\dfrac{40}{60}\) + \(\dfrac{30}{60}\)
= \(\dfrac{64}{60}\) + \(\dfrac{30}{60}\)
= \(\dfrac{47}{30}\)
\(\dfrac{2}{6}+\dfrac{3}{12}\)
= \(\dfrac{4}{12}\) + \(\dfrac{3}{12}\)
= \(\dfrac{7}{12}\)
\(\dfrac{5}{6}\) + \(\dfrac{1}{3}\)
= \(\dfrac{5}{6}\) + \(\dfrac{2}{6}\)
= \(\dfrac{7}{6}\)
9/10
17/36
7/6
19/12
67/56
12/35
11/8
7/12
25/24
73/21
17/30
2
ok chưa bạn!
\(\dfrac{1}{3}\) + \(\dfrac{5}{12}\) + \(\dfrac{5}{6}\)
= \(\dfrac{4}{12}\) + \(\dfrac{5}{12}\) + \(\dfrac{10}{12}\)
= \(\dfrac{9}{12}\) + \(\dfrac{10}{12}\)
= \(\dfrac{19}{12}\)
\(\dfrac{5}{8}\) + \(\dfrac{4}{7}\)
= \(\dfrac{35}{56}\) + \(\dfrac{32}{56}\)
= \(\dfrac{67}{56}\)
\(\dfrac{7}{3}\) + \(\dfrac{8}{7}\)
= \(\dfrac{49}{21}\) + \(\dfrac{24}{21}\)
= \(\dfrac{73}{21}\)
\(\dfrac{1}{5}+\dfrac{5}{35}\)
= \(\dfrac{7}{35}\) + \(\dfrac{5}{35}\)
= \(\dfrac{12}{35}\)
Bài 1
a, Tính P=1+1/2(1+2)+1/3(1+2+3)+1/4(1+2+3+4)+....+1/2012(1+2+3+...+2012)
b,Tìm x thỏa mãn 4^5+4^5+4^5+4^5/3^5+3^5+3^5.6^5+6^5+6^5+6^5+6^5+6^5/2^5+2^5=2^x
Kho..................wa.....................troi.....................thi......................lanh.................ret.......................ai........................tich..........................ung.....................ho........................minh.....................cho....................do....................lanh
Kho..................wa.....................troi.....................thi......................lanh.................ret.......................ai........................tich..........................ung.....................ho........................minh.....................cho....................do....................lanh
Bài 1:Tính
1) (1/2)^3 (3/2)^2
2) (2/3)^3 (3/2)^5
3) (5/4)^5 (4/5)^7
4) (-5/6)^6 (6/5)^8
5)(-4/3)^3 (9/16)^5
6) (1/3)^4 (-9/2)^6
7)(-4/9)^3 (-27/20)^4
8) (0,2)^4 . 5^6
9) (-4/3)^3 (9/16)^5
10) (-0,2)^3 .(-5)^5
11) (-4)^4 .(0,25)^6
12) $^2 . (0,2)^3
13) (0,5)^2 . 2^4
14) (-0,5)^3 .2^6
15) (-0,5)^5 .(-2)^10
16) (0,125)^2 .8^4
17) (0,125)^5 . (-8)^4
18) (-0,125)^7 . 8^10
19) (-0,1)^4 . 10^7
20) (0,1)^5 . (-10)^10
Giúp mình với ạ,mình cảm ơn ạ
1: =1/8*9/4=9/32
2: =8/27*243/32=9/4
3: =(5/4*4/5)^5*(4/5)^2=16/25
4: \(=\left(-\dfrac{5}{6}\cdot\dfrac{6}{5}\right)^2\cdot\left(\dfrac{6}{5}\right)^2=\dfrac{36}{25}\)
5: \(=\left(-\dfrac{4}{3}\right)^3\cdot\left(\dfrac{3}{4}\right)^{10}=\left(-1\right)\left(\dfrac{3}{4}\right)^7=-\left(\dfrac{3}{4}\right)^7\)
6: \(=\left(\dfrac{1}{3}\cdot\dfrac{-9}{2}\right)^4\left(-\dfrac{9}{2}\right)^2=\left(-\dfrac{3}{2}\right)^4\cdot\dfrac{81}{4}=\dfrac{9}{4}\cdot\dfrac{81}{4}=\dfrac{729}{16}\)
8: =(0,2*5)^4*5^2=25
10: =-0,5^5*2^10
=-0,5^5*2^5*2^5
=-32
13: =(0,5*2)^2*2^2=4
Tính
1. 6/5 - 1/4 + 4/5 - 3/4
2. 7/9 - 5/12 + 2/9 - 7/12
3. -4/15 + 5/13 - 11/15 + 8/13
4. 9/15 - 7/13 +6/15 - 6/13
5. 12/5 - 3/7 + 3/5 - 4/7
6. 6/5 - 1/4 + 4/5 - 3/4 + 1/2
7. 13/7 - 8/6 + 8/7 - 4/6 - 1/3
Tính:
a, 4 1/3 . 4/9 + 13 2/3 . 4/9
b, 5 1/4 . 3/8 + 10 3/4 . 3/8
c, 6 1/5 . ( -2/7 ) + 14 4/5 . ( -2/7 )
d, 7 1/6 . ( -7/6 ) + 10 5/6 . ( -7/6 )
Tính
1. 6/5 - 1/4 + 4/5 - 3/4
2. 7/9 - 5/12 + 2/9 - 7/12
3. -4/15 + 5/13 - 11/15 + 8/13
4. 9/15 - 7/13 +6/15 - 6/13
5. 12/5 - 3/7 + 3/5 - 4/7
6. 6/5 - 1/4 + 4/5 - 3/4 + 1/2
7. 13/7 - 8/6 + 8/7 - 4/6 - 1/3
6/5 có nghĩa là sáu phần năm đó nha mn
\(\frac{6}{5}-\frac{1}{4}+\frac{4}{5}-\frac{3}{4}\)
\(=\left(\frac{6}{5}+\frac{4}{5}\right)-\left(\frac{1}{4}+\frac{3}{4}\right)\)
\(=2-1\)
\(=1\)
\(\frac{7}{9}-\frac{5}{12}+\frac{2}{9}-\frac{7}{12}\)
\(=\left(\frac{7}{9}+\frac{2}{9}\right)-\left(\frac{5}{12}+\frac{7}{12}\right)\)
\(=1-1\)
\(=0\)
các câu sau tương tự
A=1
B=0
C=ÂM 8/15
D=0
E=2
F=3/2
H=2/3
LẦN SAU CHO KHÓ SÍU NHA LỚP 5 CŨNG LÀM ĐC
Số?
| 5 + 1 = … | 4 + 2 = … | 3 + 3 = … |
| 1 + … = 6 | … + 4 = 6 | … + 3 = 6 |
| 6 – 5 = … | 6 – 2 = … | 6 – 3 = … |
| 6 – 1 = … | 6 – 4 = … | 6 - … = 3 |
Lời giải chi tiết:
| 5 + 1 = 6 | 4 + 2 = 6 | 3 + 3 = 6 |
| 1 + 5 = 6 | 2 + 4 = 6 | 3 + 3 = 6 |
| 6 – 5 = 1 | 6 – 2 = 4 | 6 – 3 = 3 |
| 6 – 1 = 5 | 6 – 4 = 2 | 6 - 3 = 3 |
a,12 1/3 - (3 3/4 + 4 3/4)
b,3 5/6 + 2 1/6 x 6
c,3 1/2 + 4 5/7 - 5 5/14
d,4 1/2 + 1/2 : 5 1/2
a) \(12\dfrac{1}{3}-\left(3\dfrac{3}{4}+4\dfrac{3}{4}\right)=\dfrac{37}{3}-\left(\dfrac{15}{4}+\dfrac{19}{4}\right)\)
\(=\dfrac{37}{3}-\dfrac{34}{4}=\dfrac{37}{3}-\dfrac{17}{2}=\dfrac{74}{6}-\dfrac{51}{6}=\dfrac{23}{6}\)
b) \(3\dfrac{5}{6}+2\dfrac{1}{6}.6=\dfrac{23}{6}+\dfrac{13}{6}.6=\dfrac{23}{6}+\dfrac{78}{6}=\dfrac{101}{6}\)
c) \(3\dfrac{1}{2}+4\dfrac{5}{7}-5\dfrac{5}{14}=\dfrac{7}{2}+\dfrac{33}{7}-\dfrac{75}{14}=\dfrac{49}{14}+\dfrac{66}{14}-\dfrac{75}{14}=-\dfrac{92}{14}=-\dfrac{46}{7}\)
d) \(4\dfrac{1}{2}+\dfrac{1}{2}:5\dfrac{1}{2}=\dfrac{9}{2}+\dfrac{1}{2}:\dfrac{11}{2}=\dfrac{9}{2}+\dfrac{1}{2}.\dfrac{2}{11}=\dfrac{9}{2}+\dfrac{1}{11}=\dfrac{99}{22}+\dfrac{2}{22}=\dfrac{101}{22}\)
a. \(12\dfrac{1}{3}-\left(3\dfrac{3}{4}+4\dfrac{3}{4}\right)=\dfrac{37}{3}-\left(\dfrac{15}{4}+\dfrac{19}{4}\right)\)
\(=\dfrac{37}{3}-\dfrac{34}{4}=\dfrac{23}{6}\)
\(b.3\dfrac{5}{6}+2\dfrac{1}{6}.6=\dfrac{23}{6}+13=\dfrac{101}{6}\)
\(c.3\dfrac{1}{2}+4\dfrac{5}{7}-5\dfrac{5}{14}=\dfrac{7}{2}+\dfrac{33}{7}-\dfrac{75}{14}=\dfrac{20}{7}\)
d \(4\dfrac{1}{2}+\dfrac{1}{2}:5\dfrac{1}{2}\)
\(=\dfrac{9}{2}+\dfrac{1}{2}:\dfrac{11}{2}\)
\(=\dfrac{9}{2}+\dfrac{1}{11}\)
\(=\dfrac{101}{22}\)