tinh A = 3^6 :3^2 + 2^3 x 2^2
giup minh voi minh dang gap lam!!!!!
Tinh gia tri bieu thuc
A=5a^3b^8 voi a=-1, b=1
B=-9a^4b^2 voi a=-1, b=2
C=ax+ay+bx+by biet a+b=-3, x+y=17
Minh dang can gap lam cac ban giup minh voi
Thay a = -1 , b=1 vào biểu thức A
=> A = 5.(-1)^3.1^8 = - 5
Thay a = -1 , b= 2 vào biểu thức B
=>B = -9.(-1)^4 . 2^2 = - 36
Ta có :
C = ax + ay + bx + by = a(x+y) + b(x+y) = (x+y)(a+b)
Thay a+b = - 3 , x+y = 17 vào biểu thức C
C = ( -3)(17) = -51
Tinh tong sau hop li :
A=2+2 mu 2 + 2 mu 3 + ............+2 mu 100
B=1+3 mu 2 + 3 mu 3 + .......... + 3 mu 2009
C = 4+ 4 mu 2 + 4 mu 3 + ...............+ 4 mu n
Giup minh voi sory may minh ko co dau minh dang can gap lam !!!
Lần sau viết cái đề rõ rõ ra nhs!!!
a) \(A=2+2^2+2^3+................+2^{100}\)
\(\Rightarrow2A=2^2+2^3+2^4+................+2^{100}+2^{101}\)
\(\Rightarrow2A-A=\left(2^2+2^3+..............+2^{100}+2^{101}\right)-\left(2+2^2+............+2^{100}\right)\)
\(\Rightarrow A=2^{101}-2\)
b) \(B=1+3+3^2+..................+3^{2009}\)
\(\Rightarrow3B=3+3^2+3^3+..................+3^{2009}+3^{2010}\)
\(\Rightarrow3B-B=\left(3+3^2+...............+3^{2010}\right)-\left(1+3+3^2+.............+3^{2009}\right)\)
\(\Rightarrow2B=3^{2010}-1\)
\(\Rightarrow B=\dfrac{3^{2010}-1}{2}\)
c) \(C=4+4^2+4^3+................+4^n\)
\(\Rightarrow4C=4^2+4^3+.................+4^n+4^{n+1}\)
\(\Rightarrow4C-C=\left(4^2+4^3+.............+4^n+4^{n+1}\right)-\left(4+4^2+............+4^n\right)\)
\(\Rightarrow3C=4^{n+1}-4\)
\(\Rightarrow C=\dfrac{4^{n+1}-4}{3}\)
\(A=2+2^2+2^3+...+2^{100}\)
\(2A=2^2+2^3+2^4+...+2^{101}\)
\(\Rightarrow2A-A=2^{101}-2\)
\(\Rightarrow A=2^{101}-2\)
Vậy \(A=2^{101}-2\).
\(B=1+3^2+3^3+...+3^{2009}\)
\(3B=3+3^3+3^4+...+3^{2010}\)
\(\Rightarrow3B-B=3^{2010}-7\)
\(\Rightarrow2B=3^{2010}-7\)
\(\Rightarrow B=\dfrac{3^{2010}-7}{2}\)
Vậy \(B=\dfrac{3^{2010}-7}{2}\).
\(C=4+4^2+4^3+...+4^n\)
\(4C=4^2+4^3+4^4+...+4^{n+1}\)
\(\Rightarrow4C-C=4^{n+1}-4\)
\(\Rightarrow3C=4^{n+1}-4\)
\(\Rightarrow C=\dfrac{4^{n+1}-4}{3}\)
Vậy \(C=\dfrac{4^{n+1}-4}{3}\).
tim x để 3.x chia hết cho x-2
giup minh voi minh dang gap lam!
Tinh bang hai cach:
a. (1/3 + 1/5) x 1/2 b. (1/3 - 1/5) x 1/2
giup minh voi, tra loi minh tick cho nha
a.\(=\dfrac{8}{15}\times\dfrac{1}{2}=\dfrac{4}{15}\)
b.\(=\dfrac{1}{3}\times\dfrac{1}{2}-\dfrac{1}{5}\times\dfrac{1}{2}=\dfrac{1}{6}-\dfrac{1}{10}=\dfrac{1}{15}\)
a.(1/3+1/5) x 1/2
=8/15 x 1/2=8/30=4/15
b)(1/3-1/5) x 1/2=2/15 x 1/2=1/15
Tim x
A,740:(x+10)=102-2×13
B,12(x-1):3=43+23
C,10+2x:42011=42013
Giup minh voi minh dang gap lam !!!!
a) 740:(x+10)=102-2x13
=>740:(x+10)=100-2x13
=>740:(x+10)=1274
=>x=10,5808477237048(6)
6 là chu kì (có nghĩa là 6soos 6 kéo dài mãi mãi không giới hạn)
☹➞cac ban giup minh cau nay voi
☛ tinh tong
M = 1+\(\dfrac{1}{5}\)+\(\dfrac{3}{35}\)+...\(\dfrac{3}{9603}\)+\(\dfrac{3}{9999}\)
➜giup minh nhanh nhe minh dang can gap lam moi nguoi a
➞thank you cac ban ❕
\(M=1+\dfrac{1}{5}+\dfrac{3}{35}+...+\dfrac{3}{9999}\\ =\dfrac{3}{3}+\dfrac{3}{15}+\dfrac{3}{35}+...+\dfrac{3}{9999}\\ =\dfrac{3}{2}\left(\dfrac{2}{1\cdot3}+\dfrac{2}{3\cdot5}+...+\dfrac{2}{99\cdot101}\right)\\ =\dfrac{3}{2}\left(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{99}-\dfrac{1}{101}\right)\\ =\dfrac{3}{2}\left(1-\dfrac{1}{101}\right)=\dfrac{3}{2}\cdot\dfrac{100}{101}=\dfrac{150}{101}\)
tinh nhanh
( 1 + 3 + 5 + 7 + .... + 2003 + 2005) x ( 1212 x 27 - 2727 x 12)giup minh voi minh dang can gap lam
nhanh len nha
cam on truoc
( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x ( 1212 x 27 - 2727 x 12 )
= ( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x ( 32724 -32724 )
= ( 1 + 3 + 5 + 7 + ... + 2003 + 2005 ) x 0
= 0
vu cao minh sai roi
de keu la tinh nhanh ma
Thì thế gọi là tính nhanh còn gì
CMR neu a thuoc Z thi:
M=a(2+a)-(a-5)-7 la boi cua 7
N=(a-2)(a+3)-(a-3(a+2) la so chan
Giup minh voi minh dang gap lam
Tinh bang cach thuan tien nhat
4/7-2/5+17/7-3/5
giup minh voi minh dang can gap
= 17/7 + 4/7 - 2/5 + 3/5
= 21/7 - 5/5
= 3 - 1
= 2