\(\left(x-5\right)^2=\left(18\dfrac{1}{3}:5\right).\dfrac{11}{3}\)

\(\Leftrightarrow\left(x-5\right)^2=\dfrac{55}{3}.\dfrac{1}{5}.\dfrac{11}{3}\)

\(\Leftrightarrow\left(x-5\right)^2=\dfrac{121}{9}\)

\(\Leftrightarrow\left[{}\begin{matrix}x-5=\dfrac{11}{3}\\x-5=-\dfrac{11}{3}\end{matrix}\right.\)

\(\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{26}{3}\\x=\dfrac{4}{3}\end{matrix}\right.\)

* x+y có thể bằng:
- 1+1
- 0+1
- 1+0

1+1
0+1
1+0

=>36/18>x>8/15

=>2>x>8/15

mà x nguyên

nên x=1

A

B

A?

27:(x-3/2)^3=(x-3/2):3

Ta có: \(\dfrac{27}{\left(x-\dfrac{3}{2}\right)^3}=\dfrac{\left(x-\dfrac{3}{2}\right)}{3}\)

\(\Rightarrow\left(x-\dfrac{3}{2}\right)^3.\left(x-\dfrac{3}{2}\right)\)=27.3

\(\Rightarrow\left(x-\dfrac{3}{2}\right)^4\)=81

\(\Rightarrow\left(x-\dfrac{3}{2}\right)^4=3^4\)

\(\Rightarrow\left[{}\begin{matrix}x-\dfrac{3}{2}=4\\x-\dfrac{3}{2}=-4\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=4+\dfrac{3}{2}\\x=-4+\dfrac{3}{2}\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{8}{2}+\dfrac{3}{2}\\x=\dfrac{-8}{2}+\dfrac{3}{2}\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{11}{2}\\x=\dfrac{-5}{2}\end{matrix}\right.\)

Vậy x∈\(\left\{\dfrac{11}{2};\dfrac{-5}{2}\right\}\)

Tìm x, biết:

(2,8.x-32):2/3=90

=>(2,8.x-32)  =90.2/3

=>2,8.x-32     =60

=>2,8.x          =60+32

=>x                =92:2,8

=>x                =

Í mà đề sai rồi, xem lại giúp mk nha !

K viết lại đề là:

2,8 x X - 32 = 90 x \(\frac{2}{3}\)

2,8 x X - 32 = \(\frac{180}{3}=60\)

2,8 x X = 60 + 32

2,8 x X = 92

x = 92 : 2,8

x = gần 32 bn nhé, có thể viết thành phân số  nếu bn muốn\(\frac{920}{28}=\frac{230}{7}\)

Hội con 🐄 chúc bạn học tốt!!!

( 2,8x - 32 ) : 2/3 = 90

( 2,8x - 32 ) = 90 . 2/3

( 2,8x - 32 ) = 60

 2,8x = 60 + 32

2,8x = 92

x = 92 : 2,8 

x = 32,8571...

2/x = 14/21

=> 2 . 21 = 14 . x 

=> 42 = 14 . x

x = 42 : 14

x = 3

mk nghĩ là :

Ta có : 14/21 = 28/22

2/x = 28/22

= 2/x = 2/11

suy ra : x=11

2/x=14/21=>2/x=2/3=>x=3