4x - 15 = -25 - 3x
1) 7x.49=790
2) 2x.4=128
3) 3x-1=24.5
4) 3x+15=42
5) 4.2x-3=125
6) 5x=515:53
7) 4x=415:16
8) 7x=720:710
9) 11x=1111:11
10) 315.3x=330
11) 10+2x=45:43
12) 20+5x=55:53
13) 4x-20=25:22
14) 15+2x=380:377
Chu y: dau "." la dau nhan.
Mình làm 5 câu thôi nhé !:
1) \(7^x\cdot49=7^{90}\)
\(\Rightarrow7^x\cdot7^2=7^{90}\)
\(\Rightarrow7^{x+2}=7^{90}\)
\(\Rightarrow x=90-2\)
\(\Rightarrow x=88\)
2) \(2^x\cdot4=128\)
\(\Rightarrow2^x\cdot2^2=2^7\)
\(\Rightarrow2^{x+2}=2^7\)
\(\Rightarrow x=7-2\)
\(\Rightarrow x=5\)
3) \(3^x-1=2^4\cdot5\)
\(\Rightarrow3^x=80+1\)
\(\Rightarrow3^x=81\)
\(\Rightarrow3^x=3^4\)
\(\Rightarrow x=4\)
4) \(3^x+15=42\)
\(\Rightarrow3^x=42-15\)
\(\Rightarrow3^x=27\)
\(\Rightarrow3^x=3^3\)
\(\Rightarrow x=3\)
5) \(4\cdot2^x-3=125\)
\(\Rightarrow2^2\cdot2^x=128\)
\(\Rightarrow2^{x+2}=2^7\)
\(\Rightarrow x=7-2\)
\(\Rightarrow x=5\)
6)
\(5^x=5^{15}:5^3\\ \Leftrightarrow5^x=5^{15-3}\\ \Leftrightarrow5^x=5^{12}\\ \Leftrightarrow x=12\)
7)
\(4^x=4^{15}:16\\ \Leftrightarrow4^x=4^{15}:4^2\\ \Leftrightarrow4^x=4^{15-2}\\ 4^x=4^{13}\\ \Leftrightarrow x=13\)
8)
\(7^x=7^{20}:7^{10}\\ \Leftrightarrow7^x=7^{20-10}\\ \Leftrightarrow7^x=7^{10}\\ \Leftrightarrow x=10\)
9)
\(11^x=11^{11}:11\\ \Leftrightarrow11^x=11^{11-1}\\ \Leftrightarrow11^x=11^{10}\\ \Leftrightarrow x=10\)
10)
\(3^{15}.3^x=3^{30}\\ \Leftrightarrow3^x=3^{30}:3^{15}\\ 3^x=3^{30-15}\\ \Leftrightarrow3^x=3^{15}\\ \Leftrightarrow x=15\)
11)
\(10+2x=4^5:4^3\\ \Leftrightarrow10+2x=4^2\\ \Leftrightarrow2x=6\\ \Leftrightarrow x=3\)
12)
\(20+5x=5^5:5^3\\ \Leftrightarrow20+5x=5^2\\ \Leftrightarrow5x=5\\ \Leftrightarrow x=1\)
13)
\(4x-20=2^5:2^2\\ \Leftrightarrow4x-20=2^3\\ \Leftrightarrow4x=28\\ \Leftrightarrow x=12\)
14)
\(15+2x=3^{80}:3^{77}\\ \Leftrightarrow15+2x=3^3\\ \Leftrightarrow2x=12\\ \Leftrightarrow x=6\)
Bài 1 ;Tìm x biết
1) (2x+1 )^3 - (2x+1)(4x^2-2x+1)-3(2x-1)=15
2) x(x-4)(x+4)-(x-5)(x^2 + 5x +25)=13
Bài 2 : Cmr các giá trị của biểu thức sau không thuộc vào giá ttij của biến :
A= (x+5)(x^2-5x+25)-(2x+1)^3-28x^3+3x(-11x+5)
B = (3x+2)^3 - 18x(3x+2)+(x-1)^3-28^3+3x(x-1)
C= (4x-1)(16x^2+4x+1)-(4x+1)^3+12(4x+1)^3+12(4x+1)-15
Tính giúp mình ạ ! Cảm ơn các cậu rất nhieeufuuuu :3
Bài 1.
1) ( 2x + 1 )3 - ( 2x + 1 )( 4x2 - 2x + 1 ) - 3( 2x - 1 ) = 15
<=> 8x3 + 12x2 + 6x + 1 - [ ( 2x )3 - 13 ] - 6x + 3 = 15
<=> 8x3 + 12x2 + 4 - 8x3 + 1 = 15
<=> 12x2 + 15 = 15
<=> 12x2 = 0
<=> x = 0
2) x( x - 4 )( x + 4 ) - ( x - 5 )( x2 + 5x + 25 ) = 13
<=> x( x2 - 16 ) - ( x3 - 53 ) = 13
<=> x3 - 16x - x3 + 125 = 13
<=> 125 - 16x = 13
<=> 16x = 112
<=> x = 7
Bài 2.
A = ( x + 5 )( x2 - 5x + 25 ) - ( 2x + 1 )3 - 28x3 + 3x( -11x + 5 )
= x3 + 53 - ( 8x3 + 12x2 + 6x + 1 ) - 28x3 - 33x2 + 15x
= -27x3 + 125 - 8x3 - 12x2 - 6x - 1 - 33x2 + 15x
= -33x3 - 45x2 + 9x + 124 ( có phụ thuộc vào biến )
B = ( 3x + 2 )3 - 18x( 3x + 2 ) + ( x - 1 )3 - 28x3 + 3x( x - 1 )
= 27x3 + 54x2 + 36x + 8 - 54x2 - 36x + x3 - 3x2 + 3x - 1 - 28x3 + 3x2 - 3x
= 7 ( đpcm )
C = ( 4x - 1 )( 16x2 + 4x + 1 ) - ( 4x + 1 )3 + 12( 4x + 1 )3 + 12( 4x + 1 ) - 15
= ( 4x )3 - 13 - [ ( 4x + 1 )3 - 12( 4x + 1 )3 - 12( 4x + 1 ) ] - 15
= 64x3 - 1 - ( 4x + 1 )[ ( 4x + 1 )2 - 12( 4x + 1 )2 - 12 ] - 15
= 64x3 - 16 - ( 4x + 1 )[ 16x2 + 8x + 1 - 12( 16x2 + 8x + 1 ) - 12 ]
= 64x3 - 16 - ( 4x + 1 )( 16x2 + 8x - 11 - 192x2 - 96x - 12 )
= 64x3 - 16 - ( 4x + 1 )( -176x2 - 88x - 23 )
= 64x3 - 16 - ( -704x3 - 528x2 - 180x - 23 )
= 64x3 - 16 + 704x3 + 528x2 + 180x + 23
= 768x3 + 528x2 + 180x + 7 ( có phụ thuộc vào biến )
Giúp mình v
Bài10872917292872917 tìm x bt
5x-16=40+x
4x-10=15-x
-12+x=5x-2
7x-4=20+3x
5x-7=20+3x
x+15=7+6x
17-x=7-6x
3x+(-21)=12-8x
125:(3x-13)=25
541+(218-z)=735
3(2x+1)-19=14
175-5(x+3)=85
4x-40=|4|+12
x+15=20-4x
8x+|-3|=-4x+39
6(x-2)+(-2)=20-4x
5x-16=40+x
=> 5x-16-x = 40
=> 5x-x -16=40
4x-16=40
4x= 40+16
4x=56
x= 56:4
x=14
Vậy...
4x-10=15-x
=> 4x-10+x= 15
4x+x -10=15
5x= 15+10
5x= 25
x= 25:5
x=5
Vậy....
5x -16=40+x
=> 5x-x=40+16
=>4x=56
=>x=56:4
x=14
Giải các phương trình sau:
a) 4 x + 2 5 − 5 x − 19 2 10 = 3 x − 2 4 − 5 ;
b) 2 x − 1 + 3 3 − 9 x − 1 4 = 3 2 x + 1 5 − 1 .
Trong các hàm số bậc nhất dưới đây, hàm số nghịch biến là:
A . y = 5 - 7 - x 3 B . y = 15 - - 3 x - 1 2 C . y = 4 x + 5 3 - 1 D . y = 4 x + 1 3 - 2 5
A)3x - 15= -25 - x
B)49 - 3x= 4x + 14
Ai giải được hai bài này thì có thể giảng ở dưới cho em được không ạ:))
a) \(3x-15=-25-x\)
\(3x+x=-25+15\)
\(4x=-10\)
\(x=\frac{-5}{2}\)
b) \(49-3x=4x+14\)
\(49-14=4x+3x\)
\(35=7x\)
\(x=5\)
a, \(3x-15=-25-x\Leftrightarrow3x-15+25+x=0\Leftrightarrow4x+10=0\)
\(\Leftrightarrow4x=-10\Leftrightarrow x=-\frac{5}{2}\)
b, \(49-3x=4x+14\Leftrightarrow49-3x-4x-14=0\Leftrightarrow35-7x=0\)
\(\Leftrightarrow7x=35\Leftrightarrow x=5\)
Tìm GTNN
E=3x^2-6x+15
F= 5x^2+6x-12
G=4x^2-4x+25
H=9x^2+6x^2+4
+) ta có : \(E=3x^2-6x+15=3\left(x^2-2x+1\right)+12\)
\(=3\left(x-1\right)^2+12\ge12\) \(\Rightarrow E_{min}=12\) khi \(x=1\)
+) ta có : \(F=5x^2+6x-12=5\left(x^2+\dfrac{6}{5}x+\dfrac{9}{25}\right)-\dfrac{69}{5}\)
\(=5\left(x+\dfrac{3}{5}\right)^2-\dfrac{69}{5}\ge\dfrac{-69}{5}\) \(\Rightarrow F_{min}=-\dfrac{69}{5}\) khi \(x=\dfrac{-3}{5}\)
+) ta có : \(G=4x^2-4x+25=4\left(x^2-x+\dfrac{1}{4}\right)+24\)
\(=4\left(x-\dfrac{1}{2}\right)^2+24\ge24\) \(\Rightarrow G_{min}=24\) khi \(x=\dfrac{1}{2}\)
+) ta có : \(H=9x^2+6x^2+4=15x^2+4\ge4\)
\(\Rightarrow H_{min}=4\) khi \(x=0\)
Tìm GTNN
E=3x^2-6x+15
F= 5x^2+6x-12
G=4x^2-4x+25
H=9x^2+6x^2+4
Bài 1: Tìm x
a) 5x - 7 = -19 + 2x
b) 35- 3x= 45 - 4x
c) 4x - 15 = - 75 - x
d) x - 12 = ( - 9 ) - 15
Bài 2 : Tìm x
a) 11- ( 15 + 14 ) = x - ( 25 - 9 )
b) 4x - 6 = - 20 + 3x
c) 45 - 2x = 55 - 5x
d) 6x - 15 =- 55 - 2x
a) 3x + 2 . (-7) = 10
b) 25 -(30 + x) = - (27 - 8)
c) 15 - x = 12 - ( -14)
d) (4x + 11) - ( x + 34) = 67
e) 3 - 17 - x = 289 - (36 + 289)
a: =>3x=10+14=24
=>x=8
b: =>25-30-x=-19
=>-5-x=-19
=>x+5=19
=>x=14
c: =>15-x=12+14=26
=>x=-11
d: =>4x+11-x-34=67
=>3x-23=67
=>3x=90
=>x=30
e: =>-x-14=289-36-289=-36
=>x+14=36
=>x=22
a) 3x=24
x=8
b) 25-30-x=-19
25-30+19=x
14=x
c) 15-x=26
x=-11
d) 4x+11-x-34=67
3x=90
x=30
e) -14-x= -36
x=-14 -36
x= 22