Nửa chu vi hcn là : 5/2 : 2 = 5/4

Chiều dài hcn là : ( 5/4 + 1/4 ) : 2 = 3/4

Chiều rộng hcn là : 5/4 - 3/4 = 1/2

Nửa chu vi là:

5/2:2=5/4(m)

Chiều dài là:

(5/4+1/4):2=3/4(m)

Chiều rộng là:

5/4-3/4=1/2(m)

ĐS:...

Nửa chu vi hcn là:
\(\dfrac{5}{2}:2=\dfrac{5}{4}\left(m\right)\)

Chiều dài hcn là:
\(\left(\dfrac{5}{4}+\dfrac{1}{4}\right):2=\dfrac{3}{4}\left(m\right)\)

Chiều rộng hcn là:

\(\dfrac{5}{4}-\dfrac{3}{4}=\dfrac{1}{2}\left(m\right)\)

a: 6/5-2/3=18/15-10/15=8/15

b: 9/7-5/8=72/56-35/56=37/56

c: 7/6-3/4=14/12-9/12=5/12

d: 9/8-8/9=81/72-64/72=17/72

e: 7/5-7/6=7(1/5-1/6)=7/30

f: 3/4-2/5=15/20-8/20=7/20

g: 4/7-5/6=24/42-35/42=-11/41

i: 6/13-5/11=66/143-65/143=1/143

k: 1-4/5=1/5

m: 2-5/9=18/9-5/9=13/9

n: 3-9/5=15/5-9/5=6/5

p: 4-3/4=16/4-3/4=13/4

a) \(\dfrac{6}{5}-\dfrac{2}{3}=\dfrac{18}{15}-\dfrac{10}{15}=\dfrac{8}{15}\)

b) \(\dfrac{9}{7}-\dfrac{5}{8}=\dfrac{72}{56}-\dfrac{35}{56}=\dfrac{37}{56}\)

c) \(\dfrac{7}{6}-\dfrac{3}{4}=\dfrac{28}{24}-\dfrac{18}{24}=\dfrac{10}{24}=\dfrac{5}{12}\)

d) \(\dfrac{9}{8}-\dfrac{8}{9}=\dfrac{81}{72}-\dfrac{64}{72}=\dfrac{17}{72}\)

e) \(\dfrac{7}{5}-\dfrac{7}{6}=\dfrac{42}{30}-\dfrac{35}{30}=\dfrac{7}{30}\)

h) \(\dfrac{4}{7}-\dfrac{5}{6}=\dfrac{24}{42}-\dfrac{35}{42}=-\dfrac{11}{42}\)

i) \(\dfrac{6}{13}-\dfrac{5}{11}=\dfrac{66}{143}-\dfrac{65}{143}=\dfrac{1}{143}\)

k) \(1-\dfrac{4}{5}=\dfrac{5}{5}-\dfrac{4}{5}=\dfrac{1}{5}\)

m) \(2-\dfrac{5}{9}=\dfrac{18}{9}-\dfrac{5}{9}=\dfrac{13}{9}\)

n) \(3-\dfrac{9}{5}=\dfrac{15}{5}-\dfrac{9}{5}=\dfrac{6}{5}\)

p) \(4-\dfrac{3}{4}=\dfrac{16}{4}-\dfrac{3}{4}=\dfrac{13}{4}\)

a: 13/35=1/5+1/7+1/35

b: 17/63=1/9+1/7+1/63

a: 13/35=1/5+1/7+1/35

b: 17/63=1/9+1/7+1/63

a: 1-1/2=1/2

b: 1-3/10=7/10

c:3-1/3=8/3

d: 4-1/9=35/9

e: 8-2/3=22/3

f: 5-2/5=23/5

a: bằng 1 phần 2

b: bằng 7 phần 10

c: bằng 2 phần 3

d:bằng 35 phần 9

e: bằng 22 phần 3

g: bằng 23 phần 5

chúc bn học tốt

a: \(\dfrac{5}{3}\cdot\dfrac{4}{5}=\dfrac{4}{3}\)

b: \(\dfrac{2}{3}\cdot\dfrac{3}{5}=\dfrac{2}{5}\)

c: \(\dfrac{7}{6}\cdot\dfrac{6}{5}=\dfrac{7}{5}\)

d: \(\dfrac{8}{5}\cdot\dfrac{5}{7}=\dfrac{8}{7}\)

e: \(\dfrac{7}{6}\cdot\dfrac{6}{7}=\dfrac{7}{7}=1\)

g: \(\dfrac{9}{5}\cdot\dfrac{5}{2}=\dfrac{9}{2}\)

h: \(\dfrac{4}{3}\cdot\dfrac{3}{5}=\dfrac{4}{5}\)

\(a,\dfrac{13}{4}\times\dfrac{2}{3}\times\dfrac{4}{13}\times\dfrac{3}{2}=\left(\dfrac{13}{4}\times\dfrac{4}{3}\right)\times\left(\dfrac{2}{3}\times\dfrac{3}{2}\right)=1\times1=1\)

\(b,\dfrac{75}{100}+\dfrac{18}{21}+\dfrac{19}{32}+\dfrac{1}{4}+\dfrac{3}{21}+\dfrac{13}{32}=\left(\dfrac{3}{4}+\dfrac{1}{4}\right)+\left(\dfrac{18}{21}+\dfrac{3}{21}\right)+\left(\dfrac{19}{32}+\dfrac{13}{32}\right)=1+1+1=3\\ c,\dfrac{4}{7}\times\dfrac{5}{6}+\dfrac{4}{7}\times\dfrac{1}{6}=\dfrac{4}{7}\times\left(\dfrac{5}{6}+\dfrac{1}{6}\right)=\dfrac{4}{7}\times1=\dfrac{4}{7}\\ d,\dfrac{3}{5}\times\dfrac{7}{9}-\dfrac{3}{5}\times\dfrac{2}{9}=\dfrac{3}{5}\times\left(\dfrac{7}{9}-\dfrac{2}{9}\right)=\dfrac{3}{5}\times\dfrac{5}{9}=\dfrac{1}{3}\)

\(e,\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{3}{12}=\dfrac{5}{9}\times\dfrac{1}{4}+\dfrac{4}{9}\times\dfrac{1}{4}=\dfrac{1}{4}\times\left(\dfrac{5}{9}+\dfrac{4}{9}\right)=\dfrac{1}{4}\times1=\dfrac{1}{4}\\ f,\dfrac{7}{9}\times\dfrac{8}{5}\times\dfrac{3}{5}=\dfrac{56}{75}\\ g,\dfrac{2}{5}\times\dfrac{3}{4}+\dfrac{3}{4}\times\dfrac{3}{5}=\dfrac{3}{4}\times\left(\dfrac{2}{5}+\dfrac{3}{5}\right)=\dfrac{3}{4}\times1=\dfrac{3}{4}\\ h,\dfrac{2006}{2005}\times\dfrac{3}{4}-\dfrac{3}{4}\times\dfrac{1}{2005}=\dfrac{3}{4}\times\left(\dfrac{2006}{2005}-\dfrac{1}{2005}\right)=\dfrac{3}{4}\times1=\dfrac{3}{4}\)

a: \(=\dfrac{13}{4}\cdot\dfrac{4}{13}\cdot\dfrac{2}{3}\cdot\dfrac{3}{2}=1\cdot1=1\)

b: \(=\dfrac{3}{4}+\dfrac{1}{4}+\dfrac{6}{7}+\dfrac{1}{7}+\dfrac{19}{32}+\dfrac{13}{32}=1+1+1=3\)

c: \(=\dfrac{4}{7}\left(\dfrac{5}{6}+\dfrac{1}{6}\right)=\dfrac{4}{7}\)

d: \(=\dfrac{3}{5}\left(\dfrac{7}{9}-\dfrac{2}{9}\right)=\dfrac{3}{5}\cdot\dfrac{5}{9}=\dfrac{1}{3}\)

e: \(=\dfrac{1}{4}\left(\dfrac{5}{9}+\dfrac{4}{9}\right)=\dfrac{1}{4}\)

C

C

c. 27/7 nha bn

I.
1. near
2. above
3. in front of
4. under
5. inside
II. bài hai bạn chụp thiếu đáp án rồi.
Mà mắc gì bạn viết cảm ơn bằng tiếng Trung???

bài này là bài nào

bài gì vậy

minh đăng lại nha