Cmr: A=1/2-1/4+1/8-1/16+1/32-1/64<1/3
CMR
a,1/2-1/4+1/8-1/16+1/32-1/64<1/3
CMR: 1/2-1/4+1/8-1/16+1/32-1/64<1/3
đúng rồi đó Trương Quang Hải ( đừng tik cho Trương Quang Hải)
1/2+1/4+1/8+1/16+1/32+1/64?
giải
1/2+1/4+1/8+1/16+1/32+1/64
= 1/2+1/4+1/8+1/16+1/32+1/64+ 1/64 -1/64
=1-1/64=63/64
CMR:1/2-1/4+1/8-1/16+1/32-1/64 < 1/3
CMR 1/2-1/4+1/8-1/16+1/32-1/64<1/3
=(1/2 _ 1/4) + (1/8 + 1/16 ) + ( 1/32 - 1/64 )
= 1/4 +1/16 + 1/64
= 16 + 4 + 1/ 64
= 21/64 < 21/63
= 1/3
=> 1/2 -1/4 + 1/8 - 1/16 + 1/32 - 1/ 64 < 1/3
Chúc bạn làm bài tốt =))
Nguyễn Văn Anh là người ngu học !
CMR:
a)1/2-1/4+1/8-1/16+1/32-1/64<1/3
b)1/3 - 2/3^2 + 3/3^3 - 4/3^4 +...+ 99/3^99 -100/3^100 < 3/16
cmr
a) 1/2 -1/4+1/8-1/16+1/32-1/64 <1/3
b) 1/3-2/3^2+3/3^3-4/3^4+...+99/3^99-100/3^100<3/16
CMR Nếu \(\dfrac{1}{a}+\dfrac{1}{b}+\dfrac{1}{c}=0\) thì (a+b)\(\left(a^2+b^2\right)\left(a^4+b^4\right)\left(a^8+b^8\right)\left(a^{16}+b^{16}\right)\left(a^{32}+b^{32}\right)\)= \(a^{64}-b^{64}\)
Sao tự nhiên lại lòi ra số c vậy?
CMR
1/2-1/4+1/8-1/16+1/32-1/64<1/3
1/3-2/3^2+3/3^3+4/3^4+...+99/3^99<3/16
Cmr
1/2-1/4+1/8-1/16+1/32-1/64<1/3
Giúp mk với
A=1/2 - 1/4 + 1/8 - 1/16 + 1/32 - 1/64
A= ( 1/2 - 1/4 ) + ( 1/8 - 1/16 ) + ( 1/32 - 1/64 )
A= 1/4 + 1/16 + 1/64
A = 16/64 + 4/64 + 1/64
A = 16+4+1/64
A= 21/64
Ta có : 1/3 = 21/63 mà 21/64 < 21/63 => 21/64 < 1/3 => 1/2 - 1/4 + 1/8 - 1/16 + 1/32 - 1/ 64 < 1/3
Vậy 1/2 - 1/4 + 1/8 - 1/16 + 1/32 - 1/ 64 < 1/3