\(\dfrac{21}{16}\times\dfrac{8}{5}\times\dfrac{15}{7}=\dfrac{21\times8\times15}{16\times5\times7}=\dfrac{7\times3\times8\times5\times3}{8\times2\times5\times7}=\dfrac{3\times3}{2}=\dfrac{9}{2}\)

\(\dfrac{18}{9}\times\dfrac{9}{36}\times\dfrac{27}{3}=2\times\dfrac{1}{4}\times9=\dfrac{1}{2}\times9=\dfrac{9}{2}\)

AI lấy đêf kiểm tra toán giữa kì 1 không

ai nhanh thì mình sẽ cho

cho mình 

\(\frac{8}{13}\times\frac{3}{7}+\frac{5}{13}\times\frac{9}{21}=\frac{8}{13}\times\frac{3}{7}+\frac{5}{13}\times\frac{3}{7}\)

\(\Rightarrow\left(\frac{8}{13}+\frac{5}{13}\right)\times\frac{3}{7}=1\times\frac{3}{7}\)

\(=\frac{3}{7}\)

k tớ đi

a) 3/7+5/2+4/7

=(3/7+4/7)+5/2

=1+5/2

=7/2

b)6/8+4/5+1/4

=(6/8+1/4)+4/5

=1+4/5

=9/5

đến đó thôi mệt quá

a; \(\dfrac{3}{7}\) + \(\dfrac{5}{2}\) + \(\dfrac{4}{7}\)

= (\(\dfrac{3}{7}+\dfrac{4}{7}\)) + \(\dfrac{5}{2}\)

= 1 + \(\dfrac{5}{2}\)

= \(\dfrac{2}{2}+\dfrac{5}{2}\)

=  \(\dfrac{7}{2}\)

b; \(\dfrac{6}{8}\) + \(\dfrac{4}{5}\) + \(\dfrac{1}{4}\) 

= \(\dfrac{1}{4}\) + \(\dfrac{4}{5}\) + \(\dfrac{1}{4}\)

= (\(\dfrac{1}{4}\) + \(\dfrac{1}{4}\)) + \(\dfrac{4}{5}\)

= \(\dfrac{2}{4}\) + \(\dfrac{4}{5}\)

= \(\dfrac{1}{2}\) + \(\dfrac{4}{5}\)

= \(\dfrac{5}{10}\) + \(\dfrac{8}{10}\)

= \(\dfrac{13}{10}\)

c; \(\dfrac{21}{34}\) + \(\dfrac{4}{9}\) + 7 + 17

= (\(\dfrac{21}{34}\) + \(\dfrac{4}{9}\)) + (7 + 17)

= \(\dfrac{325}{306}\) + 24

= \(\dfrac{7669}{306}\)

21+22+23+24+25+26+9+8+7+6+5+4 =180

mình thấy rồng con lon ton làm đúng đấy

21 + 22 + 23 + 24 + 25 + 26 + 9 + 8 + 7 + 6 + 5 + 4

= (21 + 9) + (22 + 8) + (23 + 7) + (24 + 6) + (25 + 5) + (26 + 4)

= 30 + 30 + 30 + 30 + 30 + 30

= 30 x 6

= 180

bạn lấy 21+9+22+8+23+7+24+6+25+5+26+4=30+30+30+30+30+30=180

Bài 4: 

a: \(=\dfrac{11}{21}\left(\dfrac{7}{4}+\dfrac{5}{4}\right)=\dfrac{11}{21}\cdot3=\dfrac{11}{7}\)

b: \(=\dfrac{6}{13}\left(\dfrac{23}{14}-\dfrac{9}{14}\right)=\dfrac{6}{13}\)

Bài 4: 

a: =11/21(7/4+5/4)=11/21x3=11/7

b: =6/13(23/14-9/14)=6/13

=(3/7+4/7)+(4/9+5/9)

=1+1=2

\(\dfrac{3}{7}+\dfrac{4}{9}+\dfrac{4}{7}+\dfrac{5}{9}=\left(\dfrac{3}{7}+\dfrac{4}{7}\right)+\left(\dfrac{4}{9}+\dfrac{5}{9}\right)=\dfrac{7}{7}+\dfrac{9}{9}=1+1=2\)

=(3/7+4/7)+(5/9+4/9)=1+1=2