95 stop - throwing

96 to increase

97 cutting

98 learning

99 to offer

100 reading

101 to drive

102 smoking

103 keeping

104 borrowing

105 to get

106 making

107 to run

108 to rain

109 to take

110 listaning

111 writing

112 trying

113 doing

114 to go

115 to find

116 staying

117 not to be

118 to finish

119 to allow - to think

120 wash - to play

121 stay

122 to do

123 saying

124 to wait

125 translate

126 to talk

127 to download

129 watching - practicing

130 to inform

131 to see

132 to go

133 to know

134 asking - telling - to buy

135 waitng

II

1 a clinician

2 muscles

3 a apprentice

4 a switch

5 a plumber

chịu

chịu thua

.

\(\left(4x-1\right)^3=\frac{-1}{27}\)

\(\Rightarrow\left(4x-1\right)^3=\left(\frac{-1}{3}\right)^3\)

\(\Rightarrow4x-1=\frac{-1}{3}\)

\(\Rightarrow4x=\frac{-1}{3}+1\)

\(\Rightarrow4x=\frac{2}{3}\)

\(\Rightarrow x=\frac{2}{3}:4\)

\(\Rightarrow x=\frac{1}{6}\)

a.

Đặt \(\left\{{}\begin{matrix}\sqrt{x^2+2x+3}=a>0\\\sqrt{x^2+x+2}=b>0\end{matrix}\right.\) \(\Rightarrow a^2-b^2=x+1\)

Pt trở thành:

\(a+b=2\left(a^2-b^2\right)\)

\(\Leftrightarrow a+b=\left(2a-2b\right)\left(a+b\right)\)

\(\Leftrightarrow2a-2b=1\) (do \(a+b>0\))

\(\Leftrightarrow2a=2b+1\)

\(\Leftrightarrow2\sqrt{x^2+2x+3}=2\sqrt{x^2+x+2}+1\)

\(\Leftrightarrow4\left(x^2+2x+3\right)=4\left(x^2+x+2\right)+1+4\sqrt{x^2+x+2}\)

\(\Leftrightarrow4x+3=4\sqrt{x^2+x+2}\)

\(\Leftrightarrow\left\{{}\begin{matrix}x\ge-\dfrac{3}{4}\\16\left(x^2+x+2\right)=\left(4x+3\right)^2\end{matrix}\right.\)

\(\Leftrightarrow\left\{{}\begin{matrix}x\ge-\dfrac{3}{4}\\8x=23\end{matrix}\right.\) \(\Rightarrow x=\dfrac{23}{8}\)

b.

ĐKXĐ: \(x\ge3\)

Đặt \(\left\{{}\begin{matrix}\sqrt{x-3}=a\ge0\\\sqrt{x+2}=b>0\end{matrix}\right.\) \(\Rightarrow a^2-b^2=-5\)

Phương trình trở thành:

\(\left(a-b\right)\left(ab+1\right)=a^2-b^2\)

\(\Leftrightarrow\left(a-b\right)\left(ab+1\right)=\left(a-b\right)\left(a+b\right)\)

\(\Leftrightarrow\left[{}\begin{matrix}a=b\left(vô-nghiệm\right)\\ab+1=a+b\end{matrix}\right.\)

\(\Rightarrow ab-a-b+1=0\)

\(\Leftrightarrow\left(a-1\right)\left(b-1\right)=0\)

\(\Rightarrow\left[{}\begin{matrix}a=1\\b=1\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}\sqrt{x-3}=1\\\sqrt{x+2}=1\end{matrix}\right.\)

\(\Rightarrow\left[{}\begin{matrix}x=4\\x=-1\left(ktm\right)\end{matrix}\right.\)

Ta có x + y = x.y

=> x + y - x.y = 0

=> x + y(1 - x) = 0

=> x - y(x - 1) = 0

=> (x - 1) - y(x - 1) = -1

=> (x - 1) . (1 - y) = -1

=> x - 1 và 1 - y là ước của -1 = {1;-1}

Nếu x - 1 = 1; 1 - y = -1 =>  x = 2 ; y = 2

Nếu x - 1 = -1; 1 - y = 1 => x = 0; y = 0

x=12

A) 150-[10²-(14-11)² .2021⁰

=150-[10²-3².2021⁰  ]

=150-[100-9.1]

=150-91

= 59

p=3

3 nhé

Bn có thể giải chi tiết giúp mk đc ko?