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a) \(5+3^{x+1}=86\)

\(=>3^{x+1}=86-5\)

\(=>3^{x+1}=81=3^4\)

\(=>x+1=4\) ( cùng cơ số )

\(=>x=4-1\)

\(=>x=3\)

b) \(15:\left(x+2\right)=\left(3^3+3\right):10\)

\(=>15:\left(x+2\right)=\left(27+3\right):10\)

\(=>15:\left(x+2\right)=30:10=3\)

\(=>x+2=15:3\)

\(=>x+2=5\)

\(=>x=5-2\)

\(=>x=3\)

c) \(\left(9x+2\right).4=80\)

\(=>9x+2=80:4\)

\(=>9x+2=20\)

\(=>9x=20-2\)

\(=>9x=18\)

\(=>x=18:9\)

\(=>x=2\)

d) \(\left(245-x\right)+7^2=14\)

\(=>\left(245-x\right)+14=14\)

\(=>245-x=14-14\)

\(=>245-x=0\)

\(=>x=245-0\)

\(=>x=245\)

?

a).\(541+\left(218-x\right)=735\)

                        \(218-x=735-541\)

                       \(218-x=194\)

                                      \(x=218-194\)

                                       \(x=24\)

b).\(5\left(x+35\right)=515\)

         \(x+35=515:5\)

          \(x+35=103\)

         \(x=103-35\)

          \(x=68\)

c).\(96-3\left(x+1\right)=42\)

                 \(3\left(x+1\right)=96-42\)

                   \(3\left(x+1\right)=54\)

                      \(\left(x+1\right)=54:3\)

                      \(\left(x+1\right)=18\)

                        \(x=18-1\)   

                        \(x=17\)

d)\(12x-33=3^2\cdot3^3\)

   \(12x-33=3^5\)

   \(12x-33=243\)

                \(12x=243+33\)

                \(12x=276\)

                     \(x=276:12\)

                     \(x=23\)

\(Nhớ\)\(tk\)\(mình\)\(nha\)\(!\)

`@` ` \text {Ans}`

`\downarrow`

`a,`

`1/4+3/4*x=3/2-x`

`=> 1/4 + 3/4x - 3/2 + x = 0`

`=> (1/4 - 3/2) + (3/4x + x) = 0`

`=> -5/4 + 7/4x = 0`

`=> 7/4x = 5/4`

`=> x = 5/4 \div 7/4`

`=> x = 5/7`

Vậy, `x=5/7`

`b,`

`3/5*x-1/4=1/10*x-1/2`

`=> 3/5x - 1/4 - 1/10x + 1/2 = 0`

`=> (3/5x - 1/10x) + (-1/4 + 1/2)=0`

`=> 1/2x + 1/4 = 0`

`=> 1/2x = -1/4`

`=> x = -1/4 \div 1/2`

`=> x = -1/2`

Vậy, `x=-1/2`

`c,`

`3x-3/5=x-1/4`

`=> 3x - 3/5 - x + 1/4 = 0`

`=> (3x - x) - (3/5 - 1/4) = 0`

`=> 2x - 7/20 = 0`

`=> 2x = 0,35`

`=> x = 0,35 \div 2`

`=> x = 7/40`

Vậy, `x=7/40`

`d,`

`3/2*x-2/5=1/3*x-1/4`

`=>  3/2x - 2/5 - 1/3x + 1/4 = 0`

`=> (3/2x - 1/3x) - (2/5 - 1/4) = 0`

`=> 7/6x - 3/20 = 0`

`=> 7/6x = 3/20`

`=> x = 3/20 \div 7/6`

`=> x = 9/70`

Vậy, `x=9/70`

`@` `\text {Kaizuu lv uuu}`

Giải:

a) \(2^5=4^x\) 

\(\Rightarrow2^5=\left(2^2\right)^x\) 

\(\Rightarrow2^5=2^{2x}\) 

\(\Rightarrow2x=5\) 

\(\Rightarrow x=\dfrac{5}{2}\) 

b) \(2.4^2.8^3.16^4=8^x\) 

\(\Rightarrow2.\left(2^2\right)^2.\left(2^3\right)^3.\left(2^4\right)^4=\left(2^3\right)^x\) 

\(\Rightarrow2.2^4.2^9.2^{16}=2^{3x}\) 

\(\Rightarrow2^{30}=2^{3x}\) 

\(\Rightarrow3x=30\) 

\(\Rightarrow x=30:3\) 

\(\Rightarrow x=10\) 

c) \(3^3:3^5=9^x\) 

\(\Rightarrow3^{-2}=\left(3^2\right)^x\) 

\(\Rightarrow3^{-2}=3^{2x}\) 

\(\Rightarrow2x=-2\) 

\(\Rightarrow x=-2:2\)

\(\Rightarrow x=-1\) 

Chúc bạn học tốt!

a) Ta có: \(2^5=4^x\)

nên \(2^{2x}=2^5\)

\(\Leftrightarrow2x=5\)

hay \(x=\dfrac{5}{2}\)

b) Ta có: \(2\cdot4^2\cdot8^3\cdot16^4=8^x\)

\(\Leftrightarrow2^{3x}=2\cdot2^5\cdot2^9\cdot2^{16}=2^{31}\)

\(\Leftrightarrow3x=31\)

hay \(x=\dfrac{31}{3}\)

c) Ta có: \(3^3:3^5=9^x\)

\(\Leftrightarrow3^{-2}=3^{2x}\)

\(\Leftrightarrow2x=-2\)

hay x=-1

a) \(\left(5x+3^4\right).6^8=6^9.3^4\)

\(=>6x+3^4=3^4.6^9:6^8\)

\(=>6x+3^4=3^4.6\)

\(=>6x=6.3^4-3^4\)

\(=>6x=0\)

\(=>x=0:6\)

\(=>x=0\)

a/(5x + 3⁴).6⁸=6⁹.3⁴

   (5x + 3⁴) = 6⁹:6⁸.3⁴

   5x + 81 = 6.81

   5x = 6.81 - 81

   5x = 486 - 81

   5x = 425

   x = 425:5

   x = 85

b/92 - 2x = 2.4²- 3.4 + 120:15
   92 - 2x = 2.16 - 12 + 8

   92 - 2x = 32 - 12 + 8

   92 - 2x = 28

   2x = 92 - 28

   2x = 64

   x = 64:2

   x = 32

c/5³.(3x + 2) : 13 = 10³: (13⁵:13⁴)

  125.(3x + 2) : 13 = 1000:13 

  125.(3x+2) = 1000:13.13

  125.(3x+2) = 1000

   3x + 2 = 1000:125

   3x + 2 = 8

   3x = 8 - 2

   3x = 6

   x = 6:3

   x = 2

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a/(5x + 34).68=69.34

   (5x + 34) = 69:68.34

   5x + 81 = 6.81

   5x = 6.81 - 81

   5x = 486 - 81

   5x = 405

   x = 405:5

   x = 81

b/92 - 2x = 2.42- 3.4 + 120:15
   92 - 2x = 2.16 - 12 + 8

   92 - 2x = 32 - 12 + 8

   92 - 2x = 28

   2x = 92 - 28

   2x = 64

   x = 64:2

   x = 32

c/53.(3x + 2) : 13 = 103: (135:134)

  125.(3x + 2) : 13 = 1000:13 

  125.(3x+2) = 1000:13.13

  125.(3x+2) = 1000

   3x + 2 = 1000:125

   3x + 2 = 8

   3x = 8 - 2

   3x = 6

   x = 6:3

   x = 2

Cái này mới đúng

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