-25 , 72 + 25 .21 - 49 . 25

=25 . -72 + 25 . 21 - 49 . 25

=25 . (-72 + 21 - 49)

=25 . -100

=-2500

k mk nha

\(-25.72+25.21-49.25\\ =25.\left(-72+21-49\right)\\ =25.\left(-100\right)\\ =-2500\)

-25 . 72 + 25 .21 - 49 .25 = 25 . (-72) + 25 .21 - 49 .25

= 25 ( -72 + 21 -49 ) = 25 . (-100) = -2500

1: Ta có: \(2155-\left(174+2155\right)+\left(-68+174\right)\)

\(=2155-174-2155-68+174\)

=-68

2) Ta có: \(-25\cdot72+25\cdot21-49\cdot25\)

\(=-25\cdot\left(72-21+49\right)\)

\(=-25\cdot100=-2500\)

1) 2155-(174+2155)+(-68+174-7)-1911-(1234-1911)

=2155-174-2155+(-68)+174-7-1911-1234+1911

=(2155-2155)+(174-174)+(1911-1911)-(68+7+1234)

= 0 + 0 + 0 - 1309

= -1309

a) Ta có:

16^19=(2⁴)¹⁹=2⁷⁶                       ;             8²⁵=(2³)²⁵=2⁷⁵

Vì 76>75 nên 2⁷⁶>2⁷⁵. Vậy 16¹⁹>8²⁵

b) Ta có:

72⁴⁵-72⁴⁴=72(72⁴⁴-72⁴³)

Vậy 72⁴⁵-72⁴⁴ > 72⁴⁴-72⁴³

^{c) chịu}

a, Ta có:16^19=(2^4)^19=2^76

8^25=(2^3)^25=2^75

Vì 2^75<2^76 nên 8^75<16^19

b,Ta có:72^45-72^74=72(72^44-72^73)

=>72^45-72^44>72^44-72^43 

c,MÌNH GIẢI PHẦN NÀY SAU NHÉ!

c) \(3^{99}=3^{3.33}=27^{33}\)

VÌ \(27^{33}>11^{21}=>3^{99}>11^{21}\)

27^33>11^21 vì 27>11 và 33>21

1) 2155-(174+2155)+(-68+174)

=2155-174-2155-68+174

=2155-2155+174-174-68

=0+0-68

=-68

2) -25.72+25.21-49.25

=25.[(-72)+21-49]

=25.(-100)

=-2500

3) 35(14 - 23) - 23(14 - 35)

= 35.14 - 35.23 - (23.14 - 23.35)

= 35.14 - 35.23 - 23.14 + 23.35

= (35.14 - 23.14) + (23.55 - 35.23)

= 14.(35-23) + 0

= 14.12 + 0

= 168

4) 8154 - (674 + 8154) + (-98 + 674)

= 8154 - 674 - 8154 - 98 + 674

= (8154 - 8154) + (674 - 674) - 98

= 0 + 0 - 98

= -98

5) (-25).21 + 25.72 + 49.25

= 25.[(-21) + 72 + 49]

= 25.100

= 2500

6) 27(13 - 16) - 16(13 - 27)

= 27.13 - 27.16 - (16.13 - 16.27)

= 27.13 - 27.16 - 16.13 + 16.27

= (27.13 - 16.13) + (16.27 - 27.16)

= 13.(27-16) + 0

= 13.11 + 0

= 143

7) (-1911) - (1234 - 1911)

= (-1911) - 1234 + 1911

= [(-1911) + 1911] - 1234

= 0 - 1234

= -1234

8) 156.72 + 28.156

= 156.(72+28)

= 156.100

= 15600

9) 32.(-39) + 16.(-22)

= 16.2.(-39) + 16.(-22)

= 16.(-78) + 16.(-22)

= 16.[(-78) + (-22)]

= 16.(-100)

= -1600

10) (-1945) - (567 - 1945)

= (-1945) - 567 + 1945

= [(-1945) + 1945] - 567

= 0 - 567

= -567

11) 184.33 + 67.184

= 184.(33 + 67)

= 184.100

= 18400

12) 44.(-36) + 22.(-28)

= 22.2.(-36) + 22.(-28)

= 22.(-72) + 22.(-28)

= 22.[(-72) + (-28)]

= 22.(-100)

= -2200

câu 1 = -68

câu 2 =-2500

câu 3=168

câu 4 =4571

câu 6=124

a>\(16^{19}=2^{4^{19}}=2^{76}\\ 8^{25}=2^{3^{25}}=2^{75}\)

16^19>8^25

1/2+5/6+11/12+19/20+29/30+41/42+55/56+71/72+89/90 

= 1-1/2+1-1/6+1-1/12+1-1/20+1-1/30+1-1/42+1-1/56+1-1/72+1-1/90

= 9 – (1/2+1/6+1/12+1/20+1/30+1/42+1/56+1/72+1/90) 

= 9 – [1/(1x2)+1/(2x3)+1/(3x4)+1/(4x5)+1/(5x6)+1/(6x7)+1/(7x8)+1/(8x9)+1/(9x10)] 

= 9 – ( 1-1/2+1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+1/6-1/7+1/7-1/8+1/8-1/9+1/9-1/10)

=9 – (1 – 1/10) = 9 – 9/10 = 81/10

Đề sai phải đổi \(\frac{11}{16}\) thành \(\frac{11}{12}\)

\(A=9-\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+\frac{1}{8.9}+\frac{1}{9.10}\right)\)

\(A=9-\left(\frac{2-1}{1.2}+\frac{3-2}{2.3}+\frac{4-3}{3.4}+...+\frac{10-9}{9.10}\right)\)

\(A=9-\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{9}-\frac{1}{10}\right)\)

\(A=9-\left(1-\frac{1}{10}\right)=9-\frac{9}{10}=8\frac{1}{10}\)