a) \(\frac{X}{2}-\frac{11}{5}=\frac{7}{8}\cdot\frac{64}{49}\)

\(\Rightarrow\frac{x}{2}-\frac{11}{5}=\frac{8}{7}\)

\(\Rightarrow\frac{x}{2}=\frac{8}{7}+\frac{11}{5}\)

\(\Rightarrow\frac{x}{2}=\frac{117}{35}\)\(\Rightarrow x=\frac{117}{35}\cdot2=\frac{234}{35}\)

b)\(\frac{x}{5}+\frac{9}{2}=\frac{6}{7}\cdot\frac{36}{49}\)

\(\Rightarrow\frac{x}{5}+\frac{9}{2}=\frac{216}{343}\)

\(\Rightarrow\frac{x}{5}=\frac{216}{343}-\frac{9}{2}=\frac{-2655}{686}\)

\(\Rightarrow x=\frac{-2655}{686}\cdot5=\frac{-13275}{686}\)

        x/2 - 11/5 = 7/8 . 64/49

        x/2 - 11/5 = 8/7

        x/2          =8/7 + 11/5

        x/2          = 117/35

        x             = 2.117/35 ( tính chất phân số bằng nhau)

        x             = 234/35 

       x/5 + 9/2 = 6/7 . 36/49

       x/5 + 9/2 = 216/343

        x/5         = 216/343 - 9/2

        x/5         = -2655/686

        x           = 5.(-2655)/686

        x           = -13275/686 

tui trả lời trước mà ko tk

\(-\dfrac{3}{6}=-\dfrac{x}{2}=-\dfrac{18}{y}=-\dfrac{z}{24}\)

 vs cái này thì e kêu lmj thế?

=>x/-2=-18/y=z/-24=-1/2

=>x=-1; y=36; z=12

A=1/1.2+1/2.3+...1/x =49/50

A=1-1/2+1/2-1/3+...+1/x-1-1/x=49/50

A=1-1/x=49/50

A=50/50-1=x=49/50

x=1/50

\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{x}=\frac{49}{50}\)

\(\Rightarrow\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{x\left(x-1\right)}=\frac{49}{50}\)

\(\Rightarrow1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x-1}-\frac{1}{x}=\frac{49}{50}\)

\(\Rightarrow1-\frac{1}{x}=\frac{49}{50}\)

\(\Rightarrow\frac{1}{x}=\frac{1}{50}\)

\(\Rightarrow x=50\)

\(A=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{x}\)

\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{\left(n-1\right)n}\) với \(\left(n-1\right)n=x\)

\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{n-1}-\frac{1}{n}\)

\(A=1-\frac{1}{n}\)

Mà \(A=\frac{49}{50}\)

\(\Rightarrow1-\frac{1}{n}=\frac{49}{50}\)

              \(\frac{1}{n}=1-\frac{49}{50}\)

              \(\frac{1}{n}=\frac{1}{50}\)

\(\Rightarrow n=50\)

Có \(x=\left(n-1\right)n\)

\(\Rightarrow x=\left(50-1\right)50\)

    \(x=49.50\)

    \(x=2450\)

trong nâng cao và phát triển có bài này thật đấy

-4.10 = 8.x 

=> x = -40 : 8

     x = -5

10.7 = -5.y

=> y = 70 : (-5) = -14

7.(-24) = -14.z

=> z = -168 : (-14) = 12 

\(\frac{-4}{8}=\frac{x}{-10}\Leftrightarrow\left(-4\right).\left(-10\right)=8.x\Rightarrow x=\frac{\left(-4\right).\left(-10\right)}{8}=\frac{40}{8}=5\)

\(\frac{5}{-10}=\frac{-7}{y}\Leftrightarrow5.y=\left(-7\right).\left(-10\right)\Rightarrow y=\frac{\left(-7\right).\left(-10\right)}{5}=\frac{70}{5}=24\)

\(\frac{-7}{24}=\frac{z}{-24}\Leftrightarrow\left(-7\right).\left(-24\right)=z.24\Rightarrow z=\frac{\left(-7\right).\left(-24\right)}{24}=\frac{168}{24}=7\)

Vậy x = 5 ; y = 24 ; z = 7

Không rõ đề lắm bạn ơi

câu hỏi của bạn có sai ko ạ

a) \(x=\dfrac{1}{2}+\dfrac{3}{4}\)

\(\Rightarrow x=\dfrac{2}{4}+\dfrac{3}{4}\\ \Rightarrow x=\dfrac{5}{4}\)

b) \(\dfrac{x}{5}=\dfrac{1}{2}-\dfrac{2}{3}\)

\(\Rightarrow\dfrac{x}{5}=\dfrac{3}{6}-\dfrac{4}{6}\)

\(\Rightarrow\dfrac{x}{5}=-\dfrac{1}{6}\)

\(\Rightarrow x=-\dfrac{1}{6}.5\)

\(\Rightarrow x=-\dfrac{5}{6}\)

c) \(x=\dfrac{1}{2}-\dfrac{2}{3}\)

\(\Rightarrow x=\dfrac{3}{6}-\dfrac{4}{6}\)

\(\Rightarrow x=-\dfrac{1}{6}\)

d) \(\dfrac{x}{3}=\dfrac{2}{3}-\dfrac{1}{7}\)

\(\Rightarrow\dfrac{x}{3}=\dfrac{14}{21}-\dfrac{3}{21}\)

\(\Rightarrow\dfrac{x}{3}=\dfrac{11}{21}\)

\(\Rightarrow x=\dfrac{11}{21}.3\)

\(\Rightarrow x=\dfrac{33}{21}\)

\(\frac{x}{3\frac{1}{2}.2\frac{2}{3}}=\frac{9}{56}\Rightarrow\frac{x}{\frac{7}{2}.\frac{8}{3}}=\frac{9}{56}\Rightarrow x=\frac{9}{56}.\frac{28}{3}=\frac{3}{2}\)

\(x:\left(3\frac{1}{2}.2\frac{2}{3}\right)=\frac{9}{56}\)

\(x:\left(\frac{7}{2}.\frac{8}{3}\right)=\frac{9}{56}\)

\(x:\left(\frac{7.4}{3}\right)=\frac{9}{56}\)

\(x.\frac{3}{28}=\frac{9}{56}\)

\(x=\frac{9}{56}.\frac{28}{3}=\frac{3}{2}\)

Vậy \(x=\frac{3}{2}\)