Tìm số nguyên x biết :
a, -28 - 7.|-3x + 15| = -70
b, |18 - 2 |-x + 5|| = 12
c, 12 - 2.(-x + 3)mũ 2 = -38
d, -20 + 3.(2x +1)mũ 3 = -101
tìm x
a)\2x+1\-19=-7
b)-28-7.\-3x+15\=-70
c)12-2.(-x+3)mũ 2 =-38
d)-20+3.(2x+1)mũ3=-101
phàn mũ mik ko viết được
a) \(|2x+1|-19=-7\)
\(\Leftrightarrow|2x+1|=12\)
\(\Leftrightarrow\orbr{\begin{cases}2x+1=12\\2x+1=-12\end{cases}\Leftrightarrow\orbr{\begin{cases}2x=11\\2x=-13\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=\frac{11}{2}\\x=\frac{-13}{2}\end{cases}}}\)
b) \(-28-7\cdot|-3x+15|=-70\)
\(\Leftrightarrow-7\cdot|-3x+15|=-42\)
\(\Leftrightarrow|-3x+15|=6\)
\(\Leftrightarrow\orbr{\begin{cases}-3x+15=6\\-3x+15=-6\end{cases}\Leftrightarrow\orbr{\begin{cases}-3x=-9\\-3x=-21\end{cases}\Leftrightarrow}\orbr{\begin{cases}x=3\\x=7\end{cases}}}\)
Tìm số nguyên x:
a, |2x+1|-19= -7
b, -28 - 7.|-3x+15|= -70
c, |18-2.|-x+5||= 12
d, 12-2.(-x+3)2 = -38
e, -20+3.(2x+1)3 = -101
a, |2x+1| - 19 = -7
|2x+1| = 12
TH1: 2x + 1 = 12
2x = 11
x = \(\frac{11}{2}\)
TH2: 2x + 1 = -12
2x = -13
x = \(\frac{-13}{2}\)
b, -28 - 7.|-3x+15| = -70
-7.|-3x+15| = -42
|-3x+15| = 6
TH1: -3x + 15 = 6
-3x = -9
x = 3
TH2: -3x + 15 = -6
-3x = -21
x = 7
d, 12 - 2( -x + 3)2 = -38
-2( -x + 3)2 = -50
( -x + 3)2 = 25
( -x + 3)2 = +- 52
-x + 3 = +- 5
TH1: -x + 3 = 5
-x = 2
x = -2
TH2: -x + 3 = -5
-x = -8
x = 8
e, -20 + 3(3x+1)3 = -101
3(3x+1)3 = -81
(3x+1)3 = -27
(3x+ 1)3 = -33
3x + 1 = -3
3x = -4
x = \(\frac{-4}{3}\)
Chúc bạn học tốt !
a, |2x+1|-19= -7
|2x+1|=-7+(-19) |2x+1|=-26 truong hop 1: 2x+1=-26 2x=-26-1 2x=-27 x=-27:2( vo li) truong hop 2 2x+1=26 2x=26-1 2x=25 x=25:2 ( vo li) Vay x ko co gia tri nao thoa manTìm số nguyên x:
a, |2x+1| -19= -7
b, -28-7.|-3x+15|= -70
c, |18-2|-x+5||=12
d, 12-2(-x+3)2 = -38
e, -20+3(2x+1)3 = -101
Bài tập:
a) |2x + 1| - 19 = -7
b) -28 - 7 .|- 3x + 15| = -70
c) | 18 - 2.| -x + 5|| = 12
d) 12 - 2 .(-x + 3)2= -38
e) -20 + 3.(2x + 1) ^3 = -101
Ai giúp e vs!
a) /2x+1/-19=-7 /2x+1/=-7+-19 /2x+1/=-12 vì /2x+1/=12 chứ ko đc =-12 =>x ko xảy ra
a) x=5,5 và x=16,5
b) x=7 và x=3
c) x=-10 và x=8 và x=2 và x=20
d) x=8 và x =-2
e) x=-3,5
1. 6 X mũ 3 -8 =40
2. 4 X mũ 5 +15=47
3. 2 X mũ 3-4=12
4. 5 X mũ 3-5=0
5. (X -5) mũ 2016 = (X-5) mũ 2018
6. (3X -2) mũ 20= (3X-1) mũ 20
7. (3X -1) mũ 10 = (3X-1) mũ 20
8. (2X -1) mũ 50 = 2X-1
9. (X phần 3 -5) mũ 2000= ( X phần 3-5) mũ 2008
1. \(6x^3-8=40\\ 6x^3=48\\ x^3=8\\ \Rightarrow x=2\)Vậy x = 2
2. \(4x^5+15=47\\ 4x^5=32\\ x^5=8\\ \Rightarrow x\in\varnothing\left(\text{vì }x\in N\right)\)Vậy x ∈ ∅
3. \(2x^3-4=12\\ 2x^3=16\\ x^3=8\\ \Rightarrow x=2\)Vậy x = 2
4. \(5x^3-5=0\\ 5x^3=5\\ x^3=1\\ \Rightarrow x=1\)Vậy x = 1
5. \(\left(x-5\right)^{2016}=\left(x-5\right)^{2018}\\ \Rightarrow\left[{}\begin{matrix}x-5=0\\x-5=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=5\\x=6\end{matrix}\right.\)Vậy \(x\in\left\{5;6\right\}\)
6. \(\left(3x-2\right)^{20}=\left(3x-1\right)^{20}\\ \Rightarrow3x-2=3x-1\\ 3x-3x=2-1\\ 0=1\left(\text{vô lí}\right)\)Vậy x ∈ ∅
7. \(\left(3x-1\right)^{10}=\left(3x-1\right)^{20}\\ \left(3x-1\right)^{10}=\left[\left(3x-1\right)^2\right]^{10}\\ \Rightarrow\left(3x-1\right)^2=3x-1\\ \left(3x-1\right)^2-\left(3x-1\right)=0\\ \left(3x-1\right)\left[\left(3x-1\right)-1\right]=0\\ \left(3x-1\right)\left(3x-2\right)=0\\ \Rightarrow\left[{}\begin{matrix}3x-1=0\\3x-2=0\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}3x=1\\3x=2\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}x=\frac{1}{3}\left(\text{loại vì }x\in N\right)\\x=\frac{2}{3}\left(\text{loại vì }x\in N\right)\end{matrix}\right.\)Vậy x ∈ ∅
8. \(\left(2x-1\right)^{50}=2x-1\\ \left(2x-1\right)^{50}-\left(2x-1\right)=0\\ \left(2x-1\right)\left[\left(2x-1\right)^{49}-1\right]=0\\ \Rightarrow\left[{}\begin{matrix}2x-1=0\\\left(2x-1\right)^{49}=1\end{matrix}\right.\Rightarrow\left[{}\begin{matrix}2x=1\\2x-1=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=\frac{1}{2}\left(\text{loại vì }x\in N\right)\\x=1\left(t/m\right)\end{matrix}\right.\)Vậy x = 1
9. \(\left(\frac{x}{3}-5\right)^{2000}=\left(\frac{x}{3}-5\right)^{2008}\\ \left(\frac{x}{3}-5\right)^{2008}-\left(\frac{x}{3}-5\right)^{2000}=0\\ \left(\frac{x}{3}-5\right)^{2000}\left[\left(\frac{x}{3}-5\right)^8-1\right]=0\\ \Rightarrow\left[{}\begin{matrix}\left(\frac{x}{3}-5\right)^{2000}=0\\\left(\frac{x}{3}-5\right)^8=1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}\frac{x}{3}-5=0\\\frac{x}{3}-5=1\\\frac{x}{3}-5=-1\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}\frac{x}{3}=5\\\frac{x}{3}=6\\\frac{x}{3}=4\end{matrix}\right.\\ \Rightarrow\left[{}\begin{matrix}x=5\cdot3=15\\x=6\cdot3=18\\x=4\cdot3=12\end{matrix}\right.\)Vậy \(x\in\left\{15;18;12\right\}\)
\(1.6x^3-8=40\\ \Leftrightarrow6x^3=48\\ \Leftrightarrow x^3=8\Leftrightarrow x^3=2^3=\left(-2\right)^3\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)
Vậy \(x\in\left\{2;-2\right\}\)
\(2.4x^3+15=47\) (T nghĩ đề là mũ 3)
\(\Leftrightarrow4x^3=32\Leftrightarrow x^3=8=2^3=\left(-2\right)^3\Leftrightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)
Vậy \(x\in\left\{2;-2\right\}\)
Câu 3, 4 tương tự nhé.
\(5.\left(x-5\right)^{2016}=\left(x-5\right)^{2018}\\ \Leftrightarrow\left(x-5\right)^{2018}-\left(x-5\right)^{2016}=0\\ \Leftrightarrow\left(x-5\right)^{2016}\left[\left(x-5\right)^2-1\right]=0\\ \Leftrightarrow\left(x-5\right)^{2016}\left(x-5-1\right)\left(x-5+1\right)=0\\ \Leftrightarrow\left(x-5\right)^{2016}\left(x-6\right)\left(x-4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}\left(x-5\right)^{2016}=0\\x-6=0\\x-4=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x-5=0\\x=6\\x=4\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=5\\x=6\\x=4\end{matrix}\right.\)
Vậy \(x\in\left\{4;5;6\right\}\)
Tìm x:
a) (x-20) mũ 2 -(x+1)(x+3)=-7
b) (3x+5)(4-3x)=0
c) x mũ 3 -9x=0
d)2/3x (x mũ 2 -4)=0
e) (2x+1)-x(2x+1)=0
f)(2x-1) mũ 2 -(2x+5) (2x-5) =18
g)x mũ 2 -25 =6x-9
Bài 1 Tìm x biết
A.89-(73-x)=20
B.(x+7)-25=13
C.98-(x+4)=20
D.140÷(x-8)=7
E.4(x+41)=400
F.x-[42+(-28)]=-8
G.x+5=20-(12--7)
H.(x-11)=2.2 mũ 3+20:5
I.4(x-3)=7 mũ 2-1 mũ 3
J.2 mũ x+1 ×2 mũ 2014=2 mũ 2015
2x-49=5×3 mũ 2
L.3 mũ 2(x+14)-5 mũ 2 =5×2 mũ 2
M.6x+x=5 mũ 11 ÷ 5 mũ 9 + 3 mũ 1
N.7x-x=5 mũ 21 : 5 mũ 19 +3.2 mũ2 -7 mũ 0
O.7x-2x=6 mũ 17 ÷6 mũ 15 + 44 ÷ 11
P.3 mũ x =9
Q.4 mũ x =64
R.9 mũ x-1= 9
S.x mũ 4 = 16
T.2 mũ x : 2 mũ 5=1
may cai bai day ma cung khong biet oc cho
a) 89-(73-x)=20
=>73-x=89-20
=>73-x=69
=>x=73-69
=>x=4
Dài quá bn ơi, vs lại mấy cái này cx ko khó lắm đâu (nếu ko lm đc đăng mỗi lần một ít thui chứ dài quá mk đọc cn lười chứ đừng ns là làm)
tìm x, biết:
a) (2x-1) mũ 20= (2x-1)mũ 18
b) ( 2x-3) mũ 2= 9
c) (x-5) mũ 2 = (1-3x)mũ 2
bài 2: Chứng minh rằng:
a) 15 mũ 20 - 15 mũ 19 chia hết cho 14
b) 3 mũ 20 + 3 mũ 21+ 3 mũ 22 chia hết cho 13
c) 3+ 3 mũ 2 + 3 mũ 3+.......+ 3 mũ 2007 chia hết cho 13
7 mũ 1+ 7 mũ 2+ 7 mũ 3+.........+ 7 mũ 4n chia hết cho 400
Bài 1:
a) Ta có: \(\left(2x-1\right)^{20}=\left(2x-1\right)^{18}\)
\(\Leftrightarrow\left(2x-1\right)^{20}-\left(2x-1\right)^{18}=0\)
\(\Leftrightarrow\left(2x-1\right)^{18}\left[\left(2x-1\right)^2-1\right]=0\)
\(\Leftrightarrow\left(2x-1\right)^{18}\cdot\left(2x-2\right)\cdot2x=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{2}\\x=1\end{matrix}\right.\)
b) Ta có: \(\left(2x-3\right)^2=9\)
\(\Leftrightarrow\left[{}\begin{matrix}2x-3=3\\2x-3=-3\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}2x=6\\2x=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=3\\x=0\end{matrix}\right.\)
c) Ta có: \(\left(x-5\right)^2=\left(1-3x\right)^2\)
\(\Leftrightarrow\left(x-5\right)^2-\left(3x-1\right)^2=0\)
\(\Leftrightarrow\left(x-5-3x+1\right)\left(x-5+3x-1\right)=0\)
\(\Leftrightarrow\left(-2x-4\right)\left(4x-6\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-2\\x=\dfrac{3}{2}\end{matrix}\right.\)
Bài 2:
a) \(15^{20}-15^{19}=15^{19}\left(15-1\right)=15^{19}\cdot14⋮14\)
b) \(3^{20}+3^{21}+3^{22}=3^{20}\left(1+3+3^2\right)=3^{20}\cdot13⋮13\)
c) \(3+3^2+3^3+...+3^{2007}\)
\(=3\left(1+3+3^2\right)+...+3^{2005}\left(1+3+3^2\right)\)
\(=13\left(3+...+3^{2005}\right)⋮13\)