a)\(x\times17,7-7,7\times x=177\)

\(x\times\left(17,7-7,7\right)=177\)

\(x\times10=177\)

\(x=177\div10\)

\(x=17,7\)

b) \(9\times\left(12-2\times x\right)=54\)

\(12-2\times x=54\div9\)

\(12-2\times x=6\)

\(2\times x=12-6\)

\(2\times x=6\)

\(x=6\div2\)

\(x=3\)

c) \(x\times3,9+x\times0,1=16\)

\(x\times\left(3,9+0,1\right)=16\)

\(x\times4=16\)

\(x=16\div4\)

\(x=4\)

a) \(x\times17,7-7,7\times x=177\)

\(x\times\left(17,7-7,7\right)=177\)

\(x\times10=177\)

\(x=177:10\)

\(x=17,7\)

b) \(9\times\left(12-2\times x\right)=54\)

\(12-2\times x=54:9\)

\(12-2\times x=6\)

\(2\times x=12-6\)

\(2\times x=6\)

\(x=6:2\)

\(x=4\)

c) \(x\times3,9+x\times0,1=16\)

\(x\times\left(3,9+0,1\right)=16\)

\(x\times4=16\)

\(x=16:4\)

\(x=4\)

\(#Nulc`\)

Sửa đáp án b ạ:

\(x=6:2=3\)

a)  1 ≤ x ≤ 6 ⇒ x ∈ - 3 ; - 2 ; - 1 ; 0 ; 1

b)  - 7 ≤ x ≤ - 3 ⇒ x ∈ - 3 ; - 2 ; - 1 ; 0 ; 1

\(\dfrac{11}{8}:x-\dfrac{2}{5}+-\dfrac{1}{6}=-\dfrac{1}{5}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{5}-\left(-\dfrac{1}{6}\right)\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{5}+\dfrac{1}{6}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{6}{30}+\dfrac{5}{30}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{30}\\ =>\dfrac{11}{8}:x=-\dfrac{1}{30}+\dfrac{2}{5}\\ =>\dfrac{11}{8}:x=-\dfrac{1}{30}+\dfrac{12}{30}\\ =>\dfrac{11}{8}:x=\dfrac{11}{30}\\ =>x=\dfrac{11}{8}:\dfrac{11}{30}\\ =>x=\dfrac{11}{8}.\dfrac{30}{11}\\ =>x=\dfrac{30}{8}\\ =>x=\dfrac{15}{4}\\ \dfrac{4}{7}x-\dfrac{1}{3}x+\left(-\dfrac{16}{21}\right)=-\dfrac{2}{3}\\ =>\left(\dfrac{4}{7}-\dfrac{1}{3}\right)x=-\dfrac{2}{3}-\left(-\dfrac{16}{21}\right)\\ =>\left(\dfrac{12}{21}-\dfrac{7}{21}\right)x=-\dfrac{2}{3}+\dfrac{16}{21}\\ =>\dfrac{5}{21}x=-\dfrac{14}{21}+\dfrac{16}{21}\\ =>\dfrac{5}{21}x=\dfrac{2}{21}\\ =>x=\dfrac{2}{21}:\dfrac{5}{21}\)

\(=>x=\dfrac{2}{21}.\dfrac{21}{5}\\ =>x=\dfrac{2}{5}\\ -\dfrac{11}{12}x+\dfrac{15}{2}\left(x+-\dfrac{1}{5}\right)=\dfrac{67}{8}\\ =>-\dfrac{11}{12}x+\dfrac{15}{2}.x-\dfrac{1}{5}=\dfrac{67}{8}\\ =>\left(-\dfrac{11}{12}+\dfrac{15}{2}\right)x=\dfrac{67}{8}+\dfrac{1}{5}\\ =>\left(-\dfrac{11}{12}+\dfrac{90}{12}\right)x=\dfrac{335}{40}+\dfrac{8}{40}\\ =>\dfrac{79}{12}x=\dfrac{343}{40}\\ =>x=\dfrac{343}{40}:\dfrac{79}{12}\\ =>x=\dfrac{343}{40}.\dfrac{12}{79}\\ =>x=\dfrac{343.12}{40.79}\\ =>x=\dfrac{343.3}{10.79}\\ =>x=\dfrac{1029}{790}\)

a) – 3 < x < 2 => x ∈ {-2;-1;0;1}

b) − 4 21 < x 21 < 2 21 => x ∈ {-3;-2;-1;0;1}

c) 1 ≤  x ≤ 6 => x ∈ {-3;-2;-1;0;1}

d) -7 ≤  x ≤ -3 => x ∈ {-3;-2;-1;0;1}

\(a,\Leftrightarrow x^3-8-x^3-2x=12\Leftrightarrow-2x=20\Leftrightarrow x=-10\\ b,\Leftrightarrow x^2-6x+9-x^2+4=16\Leftrightarrow=-6x=3\Leftrightarrow x=-\dfrac{1}{2}\\ c,\Leftrightarrow x\left(x^2-9\right)=0\\ \Leftrightarrow x\left(x-3\right)\left(x+3\right)=0\Leftrightarrow\left[{}\begin{matrix}x=0\\x=3\\x=-3\end{matrix}\right.\\ d,\Leftrightarrow x^2\left(x-6\right)+9\left(x-6\right)=0\\ \Leftrightarrow\left(x^2+9\right)\left(x-6\right)=0\\ \Leftrightarrow x=6\left(x^2+9>0\right)\)

a ; 29 x 64 +116 x 34 

= 29  x 2 x 32 + 116 : 2 x 2 x 34 

= 58 x 32 + 58 x 68 

= 58 ( 32 + 68)

= 58 x 100 

= 5800

b, 136 x 68 + 16 x 272 

=  136 x 68 + 16 x 2 x 136

= 136 x 68 + 136 x 32

= 136 ( 68 + 32)

= 136 x 100

= 13600

1: \(\Leftrightarrow x=UCLN\left(24;36;150\right)=6\)

2: \(\Leftrightarrow x\in\left\{24;48;72;...\right\}\)

mà 16<=x<=50

nên \(x\in\left\{24;48\right\}\)

3: \(\Leftrightarrow x\inƯ\left(6\right)\)

mà x>-10

nên \(x\in\left\{1;-1;2;-2;3;-3;6;-6\right\}\)

4: \(\Leftrightarrow x\in BC\left(4;5;8\right)\)

\(\Leftrightarrow x\in\left\{...;-40;0;40;80;120;160;200;...\right\}\)

mà -20<x<180

nên \(x\in\left\{0;40;80;120;160\right\}\)

bai toan nay kho

câu d vs e t nghĩ cx dễ thui nhưng mấy câu kia bó tay lun

có bn nào thông minh lm hộ mk đc k z !!!!!!