\(\dfrac{-3}{2}\times\dfrac{-15}{64}+\left(0,8-2\dfrac{4}{5}\right):3\dfrac{2}{3}\\ =\dfrac{45}{128}+\left(-2\right)\times\dfrac{3}{11}\\ =\dfrac{45}{128}-\dfrac{6}{11}\\ =-\dfrac{273}{1408}\)

(x-5)^x = 8^2 = (13-5)^2 => vô nghiệm

3 + 4 + 5 + ... + x = 525

=> 1 + 2 + 3 + 4 + 5 + ... + x = 1 + 2 + 525

=> (1 + x) × x : 2 = 528

=> (1 + x) × x = 528 × 2

=> (1 + x) × x = 1056 = 33 × 32

=> x = 32

ta có : số số hạng là :

\(\left(x-3\right):1+1=x-2\) ( số số hạng )

tổng là : \(\left(x+3\right).\left(x-2\right):2=525\)

               \(\left(x+3\right).\left(x-2\right)=1050\)

Mà 30 x 35 = 1050

\(\Rightarrow x=32\)

\(\left(9-x\right)^3=64\)

\(\left(9-x\right)^3=4^3\)

\(\Leftrightarrow9-x=4\)

\(x=5\)

(9-x)³ = 64

=> 9-x = 4

=>x = 5

(9-x)³=64

(9-x)³=4³

9-x=4

   x=9-4

   x=5

vậy x=5

-2011+|x|=5.16-81

-2011+|x|=80-81

-2011+|x|=-1

|x|          =(-1)-(-2011)

|x|          =2010

-> x=2010 hoặc x=-2010

-1959.16

Ta có: -2011+/x/=5.16-81=-1

\(\Rightarrow\) /x/=2010\(\Rightarrow\orbr{\begin{cases}x=2010\\x=-2010\end{cases}}\)

Xin lỗi nha mk ko biết viết dấu trị tuyệt đối

-1/10

\(\dfrac{3}{4}x\dfrac{2}{5}-\dfrac{3}{10}:\dfrac{4}{3}\) \(=\dfrac{3}{10}-\dfrac{9}{40}=\dfrac{3}{40}\)

a) x²³= 64 . x²⁰

x²³: x²⁰= 64

x³= 64

=> x³= 4³

=> x =4

Vậy...

a)\(x^{23}=64.x^{20}\)

\(\Leftrightarrow\frac{x^{23}}{x^{20}}=64\)

\(\Leftrightarrow x^3=64\Rightarrow x=4\)

b)\(\left(4x-3\right)^4=3-4x\)

\(\Leftrightarrow\left(3-4x\right)^4=3-4x\)

\(\Leftrightarrow\left(3-4x\right)^3=1\)

\(\Leftrightarrow3-4x=1\)

\(\Leftrightarrow x=\frac{1}{2}\)

a) \(3\left(x-5\right)+6=36\)

\(\Rightarrow3\cdot\left(x-5\right)=36-6\)

\(\Rightarrow3\cdot\left(x-5\right)=30\)

\(\Rightarrow x-5=10\)

\(\Rightarrow x=10+5\)

\(\Rightarrow x=15\)

b) \(200-8\cdot\left(x+7\right)=24\)

\(\Rightarrow8\cdot\left(x+7\right)=200-24\)

\(\Rightarrow8\cdot\left(x+7\right)=176\)

\(\Rightarrow x+7=\dfrac{176}{8}\)

\(\Rightarrow x+7=22\)

\(\Rightarrow x=22-7\)

\(\Rightarrow x=15\)

c) \(\left(x-890\right)\left(74-x\right)=0\)

+) \(x-890=0\)

\(\Rightarrow x=890\)

+) \(74-x=0\)

\(\Rightarrow x=74\)

d) \(\left(31-x\right)\cdot\left(x-64\right)=0\)

+) \(31-x=0\)

\(\Rightarrow x=31\)

+) \(x-64=0\)

\(\Rightarrow x=64\)