a,\(\frac{1}{5}\times\frac{2}{9}\div\frac{1}{15}\)

\(=\frac{1}{5}\times\frac{2}{9}\times15\)

\(=\left(\frac{1}{5}\times15\right)\times\frac{2}{9}\)

\(=3\times\frac{2}{9}\)

\(=\frac{2}{3}\)

b\(\frac{4}{15}\times\frac{7}{15}\times\frac{5}{4}\)

\(=\left(\frac{4}{15}\times\frac{5}{4}\right)\times\frac{7}{15}\)

\(=\frac{1}{3}\times\frac{7}{15}\)

\(=\frac{7}{45}\)

c,\(\frac{21}{23}\times\frac{5}{11}\times\frac{44}{?}\)

d,\(26\times\frac{13}{42}\div13\)

\(=\left(26\div13\right)\times\frac{13}{42}\)

\(=2\times\frac{13}{42}\)

\(=\frac{13}{21}\)

ờ ờ .......................... hong bt

21/23 x 5/11x 44/35

Mik xin lỗi nha dấu_ mình định ghi là + nha

Giúp mình nhanh lên mình còn nộp bài

 2/3+3/4_4/5+12/9+48/15.

=2/3+3/4+4/5+4/3 +7/4+16/5

= 2/3+4/3+3/4+7/4+4/5+16/5

= 2+10/4+4

=6+5/2=17/2

a: =>-x+2x=3-7

=>x=-4

b: =>6x+2+2x-5=0

=>8x-3=0

hay x=3/8

c: =>5x+2x-2-4x-7=0

=>3x-9=0

hay x=3

d: =>10x²-10x²-15x=15

=>-15x=15

hay x=-1

\(a,2x\left(x-5\right)+4\left(x-5\right)=0\\ \Leftrightarrow\left(x-5\right)\left(2x+4\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-5=0\\2x+4=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=5\\2x=-4\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=5\\x=-2\end{matrix}\right.\)

Vậy \(x\in\left\{5;-2\right\}\)

\(b,3x-15=2x\left(x-5\right)\\ \Leftrightarrow3\left(x-5\right)-2x\left(x-5\right)=0\\ \Leftrightarrow\left(x-5\right)\left(-2x+3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-5=0\\-2x+3=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=5\\2x=3\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=5\\x=\dfrac{3}{2}\end{matrix}\right.\)

Vậy \(x\in\left\{5;\dfrac{3}{2}\right\}\)

\(c,\left(2x+1\right)\left(3x-2\right)=\left(5x-8\right)\left(2x+1\right)\\ \Leftrightarrow\left(2x+1\right)\left(3x-2\right)-\left(5x-8\right)\left(2x+1\right)=0\\ \Leftrightarrow\left(2x+1\right)\left(3x-2-5x+8\right)=0\\ \Leftrightarrow\left(2x+1\right)\left(-2x+6\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}2x+1=0\\-2x+6=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}2x=-1\\2x=6\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=-\dfrac{1}{2}\\x=3\end{matrix}\right.\)

Vậy \(x\in\left\{-\dfrac{1}{2};3\right\}\)

Câu d xem lại đề

150 x 57 : 15

= (150:15) x 57

= 100 x 57

= 5700

46 x 77 : 11

= 46 x ( 77 : 11)

= 46 x 7

= 322

\(150x57:15=\left(150:15\right)x57=10x57=570\)

\(46x77:11=46x\left(77:11\right)=46x7=322\)

C1 :

Mua 1 quyển hết :

35 000 : 5 = 7 000 đồng

Mua 15 quyển hết :

7 000 x 15 = 105 000 đồng

C2 :

35 gấp 5 số lần là :

35 : 5 = 7

Mua 15 quyển vớ hết :

35 000 x 7 = 105 000 đồng 

Đinh Tuấn Việt lm đúng đấy !!!  ( ^ ^ )

a, <=> x = -4 

b, <=> 6x + 2 = -2x + 5 <=> 8x = 3 <=> x = 3/8 

c, <=> 5x + 2x - 2 = 4x + 7 <=> 2x = 9 <=> x = 9 /2 

d, <=> 10x^2 - 10x^2 - 15x = 15 <=> x = -1 

a, <=> x = -4 

b, <=> 6x + 2 = -2x + 5 <=> 8x = 3 <=> x = 3/8 

c, <=> 5x + 2x - 2 = 4x + 7 <=> 2x = 9 <=> x = 9 /2 

d <=> 10x^2 - 10x^2 - 15x = 15 <=> x = -1 

a) x=-4

b)4x=3

x=3/4

c)3x=9

x=3

d) 15x=15

x=1