tính hợp lí:√25 - 3√4/9
3/ Tính hợp lí :
a/ (- 25).(- 125).(- 4). (- 8)
b/ (- 50).(- 80).(- 2).(- 9)
\(a/ (- 25).(- 125).(- 4). (- 8)=[(-25).(-4)].[(-125).(-8)] =100.1000=100000\)
a/(−25).(−125).(−4).(−8)
= [(−25).(−4)].[(−125).(−8)]
= 100.1000
=100000
b/ (-50) . (-80) . (-2) . (-9)
= [(-50) . (-20)] . [ (-80) . (-9) ]
= 100 . 720
= 72000
1, Thực hiện phép tính bằng cách tính hợp lí
A)(9/25-2x18):(3 4/5+0,2)
\((\frac{9}{25}-2.18):\left(3\frac{4}{5}-0,2\right)\)
=-1,82 : 4
=-0,455
\(\left(\frac{9}{25}-2.18\right):\left(3\frac{4}{5}-0,2\right)\)
= -1,82:4=-0,455
25.(-4)-54:9+(-48):(-8)
tính hợp lí
\(25\cdot\left(-4\right)-54:9+\left(-48\right):\left(-8\right)=-100-6+6=-100\)
25.(-4)-54:9+(-48):(-8)
=-100-6+6
=-106+6
=-100
bài 1 tính hợp lí nếu có thể
a)-0,25 :1/4 +|3/4 +5/3|-9 . V(căn bậc 2 nha)25/81+v(-5)mũ 2
Tính hợp lí
a, -2/5×4/7+-3/5×2/7+-3/5
b,5/9×14/17+1/17×5/9+2/9+5/12
c,-4/25÷11/79+15/11÷25/79
d, (2/101÷5/9+-3/7)×(6/5÷1/3)
a)\(-\dfrac{2}{5}.\dfrac{4}{7}+\dfrac{-3}{5}.\dfrac{2}{7}+\dfrac{-3}{5}\)
=\(-\dfrac{2}{5}.\dfrac{4}{7}+\dfrac{3}{7}.\dfrac{-2}{5}+\dfrac{-3}{5}\)
=\(-\dfrac{2}{5}.\left(\dfrac{4}{7}+\dfrac{3}{7}\right)+\dfrac{-3}{5}\)
=\(\dfrac{-2}{5}.1+\dfrac{-3}{5}\)
=\(-\dfrac{2}{5}+\dfrac{-3}{5}\)
=\(-\dfrac{5}{5}\) = -1
\(\dfrac{5}{9}.\dfrac{14}{17}+\dfrac{1}{17}.\dfrac{5}{9}+\dfrac{2}{9}+\dfrac{5}{12}\)
=\(\dfrac{5}{9}.\left(\dfrac{14}{17}+\dfrac{1}{17}\right)+\dfrac{2}{9}+\dfrac{5}{12}\)
=\(\dfrac{5}{9}.\dfrac{15}{17}+\dfrac{2}{9}+\dfrac{5}{12}\)
=\(\dfrac{25}{51}+\dfrac{2}{9}+\dfrac{5}{12}\)
=\(\dfrac{691}{612}\)
\(-\dfrac{4}{25}:\dfrac{11}{79}+\dfrac{15}{11}:\dfrac{25}{79}\)
=\(-\dfrac{4}{25}.\dfrac{79}{11}+\dfrac{15}{11}.\dfrac{79}{25}\)
=\(-\dfrac{4}{25}.\dfrac{79}{11}+\dfrac{15}{25}.\dfrac{79}{11}\)
=\(\left(-\dfrac{4}{25}+\dfrac{15}{25}\right).\dfrac{79}{11}\)
=\(\dfrac{11}{25}.\dfrac{79}{11}\)
=\(\dfrac{79}{25}\)
Câu 6: Tính bằng cách hợp lí:
25/9 - 1/6 + 4/18 -5/6 =
.......
\(=\left(-\dfrac{1}{6}-\dfrac{5}{6}\right)+\left(\dfrac{25}{9}+\dfrac{2}{9}\right)=-1+3=2\)
Câu 6: Tính bằng cách hợp lí:
25/9 - 1/6 + 4/18 -5/6 = (25/9+4/18)+(-1/6-5/6)
=3-1
=2
\(=\dfrac{25}{9}-\dfrac{1}{6}-\dfrac{2}{9}-\dfrac{5}{6}\\ =\left(\dfrac{25}{9}-\dfrac{2}{9}\right)+\left(\dfrac{5}{6}-\dfrac{1}{6}\right)\\ =\dfrac{23}{9}+\dfrac{2}{3}\\ =\dfrac{23+6}{9}=\dfrac{29}{9}\)
Tính bằng cách hợp lí:
a) (9/25 - 2 . 18 ) / (19/5 + 0,2 )
b) 12 . (-2/3)^2 + 4/3
a) \(=\frac{\left(\frac{9}{25}-36\right)}{\frac{19}{5}+\frac{1}{5}}=\frac{\frac{9}{25}-\frac{900}{25}}{\frac{20}{5}}=\frac{-891}{25}:4\)\(=\frac{-891}{25\cdot4}=\frac{-891}{100}=-8,91\)
b) \(=12\cdot\frac{\left(-2\right)^2}{3^2}+\frac{4}{3}=12\cdot\frac{4}{9}+\frac{4}{3}\)\(=\frac{48}{9}+\frac{4}{3}=\frac{48}{9}+\frac{12}{9}=\frac{60}{9}\)
Bài 3: Tính bằng cách hợp lí.
a. 4 x 5 x 9 x 25
b. 2008 + 2008 + 2008 + 2008 - 2008 x 4
a. ( 4 x 25 ) x (5 x 9)
= 100 x 45
= 4500
b. (2008 x4) - ( 2008 x 4)
= 0
Bài 2: Tính hợp lí
1) 125.(-24) + 24.225
2) 512.(2 – 128) – 128. (-512)
3) (187 -23) – (20 – 180)
4) (-37 – 17). (-9) + 35. (-9 – 11)
5) (-50 +19 +143) – (-79 + 25 + 48)
6) (-8).25.(-2). 4. (-5).125
7) 3784 + 23 – 3785 – 15
8) 215 +(-38) – (-58) –15
9) 5.(-3)2 –14.(-8)+(-40)
10) 215 + (-38) – (- 58) + 90 – 852)
Bài 3*: Tìm các cặp số nguyên (x;y) thỏa mãn xy2 + 2x – y2 =
1) 125.(-24) + 24.225.
\(=24\left(-125+225\right)=24.100=2400.\)
2) 512.(2 – 128) – 128. (-512).
\(=512\left(2-128+128\right)=512.2=1024.\)