[(27^4:9^5)+(625^3:125^4)]-2^3

=[(531441:59049)+(244140625:244140625)]-8

=[9+1]-8

=10-8

=2

Nếu dk thì cko mik nhoa

\(50-\left[30-\left(9-4\right)^2\right]=50-\left(30-5^2\right)=50-\left(30-25\right)=50-5=45\)

\(50-[30-(9-4)^2]\)

\(50-[30-25]\)

\(50-5=45\)

\(\left[\left(x^2+5\right)-14\right]\cdot3=45\)

\(\Leftrightarrow x^2-9=15\)

hay \(x=\pm2\sqrt{6}\)

\(\left[\left(x^2+5\right)-14\right].3=45\)
\(\left(x^2+5\right)-14=15\)
\(x^2+5=29\)
x²=34
x=\(\sqrt{34}\)

Chăc chết      \(\left(3.4.2^{16}\right)^2:\left(11.2^{13}.4^{11}-16\right)^{19}\)

o nung qua nung qua de

707: [(2^x -5) + 74] = 4² - 3²

(2^x -5) + 74 = 101

2^x - 5 + 74  = 101

2^x + 69 = 101

2^x = 32 = 2⁵

=> x = 5

707: [(2^x -5) + 74] = 4² - 3²

(2^x -5) + 74 = 101

2^x - 5 + 74  = 101

2^x + 69 = 101

2^x = 32 = 2⁵

=> x = 5

707 : [(2^x-5)+74] = 4²-3²

707 : [(2^x-5)+74]= 16 - 9

707 : [(2^x-5)+74]= 7

         (2^x-5)+74 = 707 :7

          (2^x-5)+74= 101

          (2^x-5)      =101-74

          (2^x-5)     = 27

          2^x            = 27+5

         2^x          =32

        2^x             = 2⁵(vì 32=2⁵)

=> x=5

viết hẳn ra đi đừng viết mở ngoặc rồi đóng ngoặc

=2^4.5-{131-(13-4)^2}

=80-{131-9^2}

=80-50

=30

HT

=16.5-{131-9^2}

=80-{131-81}

=80-50

=30

__HT__

Theo đề bài ta có : 

`2^4 xx 5 - {131-(13-4)^2}`

`=16 xx5 - { 131 - 9^2 }`

`= 16 xx5 -{131-81}`

`=16xx5-50`

`=80-50`

`=30`