a, \(-\left(x+3\right)\left(x-4\right)+\left(x+1\right)\left(x-1\right)=10\)

\(\Rightarrow-\left(x^2-4x+3x-12\right)+x^2-1=10\)

\(\Rightarrow-x^2+x+12+x^2-1=10\)

\(\Rightarrow x=10+1-12\Rightarrow x=-1\)

b, \(\left(2x-1\right)\left(x-2\right)-\left(x+3\right)\left(2x-7\right)=3\)

\(\Rightarrow2x^2-4x-x+2-\left(2x^2-7x+6x-21\right)=3\)

\(\Rightarrow2x^2-5x+2-2x^2+x+21=3\)

\(\Rightarrow-4x=3-21-2\Rightarrow-4x=-20\)

\(\Rightarrow x=5\)

Các câu còn lại làm tương tự! Phá ngoặc ra!

Chúc bạn học tốt!!!

có ai giải ko

\(2\left(x-1\right)+3\left(3x-2\right)=x-4\)

\(2x-2+9x-6=x-4\)

\(2x+9x-x-2-6=-4\)

\(10x-2-6=-4\)

\(10x-2=2\)

\(10x=4\)

\(x=\frac{2}{5}\)

Vậy \(x=\frac{2}{5}\)

\(3\left(4-x\right)-2\left(x-1\right)=x+20\)

\(12-3x-2x+2=x+20\)

\(12-5x+2=x+20\)

\(12-5x-x+2=20\)

\(12-6x+2=20\)

\(12-6x=18\)

\(6x=-6\)

\(x=-1\)

Vậy \(x=-1.\)

\(4\left(2x+7\right)-3\left(3x-2\right)=24\)

\(8x+28-9x+6=24\)

\(8x-9x+28+6=24\)

\(-x+34=24\)
\(-x=-10\)

\(x=10\)

Vậy \(x=10\)

\(3\left(x-2\right)+2x=10\)

\(3x-6+2x=10\)

\(3x+2x-6=10\)
\(5x=16\)

\(x=\frac{16}{5}\)

Vậy \(x=\frac{16}{5}\)

2(x-1)+3(3x-2)=x-4

=>2x-2=9x-6-x+4=0

=>10x-4=0

=>x=\(\frac{2}{5}\)

3(4-x)-2(x-1)=x+20

=>12-3x-2x+2-x-20=0

=>-6x-6=0

=>-6(x-1)=0

=>x-1=0

=>x=1

1: \(=6x^2+2x-15x-5-x^2+6x-9+4x^2+20x+25-27x^3-27x^2-9x-1\)

=-27x^3-18x^2+4x+10

2: =4x^2-1-6x^2-9x+4x+6-x^3+3x^2-3x+1+8x^3+36x^2+54x+27

=7x^3+37x^2+46x+33

5:

\(=25x^2-1-x^3-27-4x^2-16x-16-9x^2+24x-16+\left(2x-5\right)^3\)

\(=8x^3-60x^2+150-125+12x^2-x^3+8x-60\)

=7x^3-48x^2+8x-35

2:

a: =>x^2+3x-4x-12-(x^2-5x+x-5)=8

=>x^2-x-12-x^2+4x+5=8

=>3x-7=8

=>3x=15

=>x=5

b: =>3x^2+3x-2x-2-3x^2-21x=13

=>-20x=15

=>x=-3/4

c: =>x^2-25-x^2-2x=9

=>-2x=25+9=34

=>x=-17

d: =>x^3-1-x^3+3x=1

=>3x-1=1

=>3x=2

=>x=2/3