\(a:=\left(\dfrac{1}{4}+\dfrac{3}{4}\right)+\left(\dfrac{1}{5}+\dfrac{2}{5}\right)\\ =1+\dfrac{3}{5}=1\dfrac{3}{5}\\ b:=\left(\dfrac{2}{7}+\dfrac{1}{7}\right)+\left(\dfrac{5}{14}+\dfrac{3}{14}\right)\\ =\dfrac{3}{7}+\dfrac{8}{14}\\ =\dfrac{3}{7}+\dfrac{4}{7}=1\)

a) = 1/2 - 1/2 + 1/3 -1/3 + 1/4 - 1/4 + 1/5 - 1/5 + 1/6

    =  0 + 0 + 0 + 0 + 1/6

    = 1/6

b) 2/3 + 2/4 - 2/4 + 2/5 - 2/5 + 2/6 - 2/6 + 2/7 - 2/7 + 28

=  2/3 + 28

=     86/3

[tick cho mik nha]

a) A = 1 + 2 + 3 + 4+... + 50;

Tổng A có 50 số hạng nên A = (1 + 50).50:2 = 1275,

b) B = 2 + 4 + 6 + 8 + ...+100;

Số số hạng của tổng B là: (100 - 2): 2+1 = 50 (số)

Do đó B = (2 +100).50 : 2 = 2550.

c) C = 1 + 3 + 5 + 7 +... + 99;

Số số hạng của tổng C là: (99 - 1): 2 +1 = 50 (số)

Do đó C = (1 + 99). 50 : 2 = 2500.

d = 2 + 5 + 8 + 11 .... 98 

= ( 92 - 2 ) : 3 + 1 = 33 

= 33 . ( 98 + 2 ) : 2 

 = 1650

tick cho tớ với

Số phần tử của D là: (98-2):3+1=33

Suy ra D = 33.(98+2):2=1650

can you tách ra đc hum

a: =(1-2-3+4)+(5-6-7+8)+...+(21-22-23+24)

=0+0+...+0

=0

b: =-7111+53+711-153=-6400-100=-6500

c: =-43(-1-296+296)=-43*(-1)=43

\(=\left(\dfrac{5}{7}+\dfrac{9}{7}\right)\times\dfrac{3}{2}=2\times\dfrac{3}{2}=3\)

\(=\dfrac{4}{5}\times\left(6+1+3\right)=\dfrac{4}{5}\times10=\dfrac{40}{5}=8\)

a) 5/7 x 3/2 + 3/2 x 9/7 
= (5/7 + 9/7) x 3/2
= 2 x 3/2
= 6/2 = 3
b) 4/5 + 4/5 x 6 + 3 x 4/5
= 4/5 x 1 + 4/5 x 6 + 3 x 4/5
= 4/5 x (1 + 6 + 3)
= 4/5 x 10
= 40/5 = 8

=2 × 3/2

b. =4/5 × (6 + 1 + 3)

=40/5

a: \(=\dfrac{5}{9}\cdot\dfrac{7}{4}+\dfrac{13}{9}\cdot\dfrac{7}{4}=\dfrac{7}{4}\cdot2=\dfrac{7}{2}\)

b: \(=\dfrac{14}{13}\cdot2+\dfrac{3}{13}\cdot2-2\cdot\dfrac{7}{13}=\dfrac{28}{13}+\dfrac{6}{13}-\dfrac{14}{13}=\dfrac{20}{13}\)

Bài 2: 

a: =>x-35=-23

=>x=12

b: =>|x-8|=13

=>x-8=13 hoặc x-8=-13

=>x=21 hoặc x=-5

Bài 1: 

a: =42-98-42+12-12=-98

b: =10x4x3x(-25)=40x(-25)x3=-1000x3=-3000

Câu 1: 

a) \(-\dfrac{3}{7}-\left(\dfrac{2}{3}-\dfrac{3}{7}\right)=\dfrac{-3}{7}-\dfrac{2}{3}+\dfrac{3}{7}=\dfrac{-2}{3}\)

Câu 2: 

b) \(\dfrac{2}{15}:\left(\dfrac{1}{3}\cdot\dfrac{4}{5}-\dfrac{1}{3}\cdot\dfrac{6}{5}\right)=\dfrac{2}{15}:\left[\dfrac{1}{3}\left(\dfrac{4}{5}-\dfrac{6}{5}\right)\right]=\dfrac{2}{15}:\left(\dfrac{1}{3}\cdot\dfrac{-2}{5}\right)=\dfrac{2}{15}:\dfrac{-2}{15}=\dfrac{2}{-2}=-1\)

`a)(1-1/2)xx(1-1/3)xx(1-1/4)xx(1-1/5)`

`=1/2xx2/3xx3/4xx4/5`

`=[1xx2xx3xx4]/[2xx3xx4xx5]`

`=1/5`

`b)(1-3/4)xx(1-3/7)xx(1-3/10)xx(1-3/13)xx .... xx(1-3/97)xx(1-3/100)`

`=1/4xx4/7xx7/10xx10/13xx .... xx94/97xx97/100`

`=[1xx4xx7xx10xx...xx94xx97]/[4xx7xx10xx13xx....xx97xx100]`

`=1/100`