nhiều quá bạn chọn câu nào jhos nhất thôi

a, ( - 168 ) + 72 . ( - 168 ) + ( - 168 ) . 27

= ( - 168 ) + ( - 12096 ) + ( - 4536 )

= - 12264 + - 4536

= - 16800

b, 2² . ( - 3 ) - ( 1¹⁰ + 8 ) : ( - 3 )²

= 4 . ( - 3 ) - ( 1 + 8 ) : 9

= ( - 12 ) - 9 : 9

= ( - 12 ) - 1

= - 13

c, ( - 1075 ) - ( 29 - 1075 )

= ( - 1075 ) - ( - 1046 )

= - 29

d, ( - 9 ) + ( - 11 )  + 21 + ( - 1 )

= - 20 + 21 + ( - 1 )

= 1 + - 1

= 0

e, 30 + 12 + ( - 20 ) + ( - 12 ) - ( 30 - 20 ) + ( 12 - 12 ) 

= 42 + ( - 20 ) + ( - 12 ) - 10 + 0

= 22 + ( - 12 ) - 10 + 0

= 10 - 10 + 0

= 0 + 0

= 0

g, ( 13 - 135 + 49 ) - ( 13 + 49 )

= [( - 122 ) + 49  ] - 62

= ( - 73 ) - 62

= - 135

h, 35 - { 12 - [ ( - 14 ) + ( - 2 ) } ]

= 35 - { 12 - ( - 16 ) }

= 35 - 28

= 7

Bài 2:

a. x - 35 = ( - 12 ) - 3

    x - 35 = - 15

         x  = - 15 + 35

         x  = 20

b, \(\frac{1}{4}\)+ \(\frac{1}{3}\): 3x = - 5

\(\frac{3}{12}+\frac{4}{12}\): 3x = - 5

\(\frac{7}{12}\): 3x =  - 5

3x = \(\frac{7}{12}\): - 5

3x = \(\frac{-7}{60}\)

 x = \(\frac{-7}{60}\): 3

 x = \(\frac{-7}{180}\)

c,2^x-1 = 8

2^x-1 = 2⁴

x = 4 + 1

x = 5

Mình chữa lại phần c bài 2 nha:

2^x-1 = 8

2^x-1 = 2³

x = 3 + 1

x = 4

c= - 1/10 nha

a) \(\dfrac{4}{6}+\dfrac{7}{13}+\dfrac{17}{9}-\dfrac{8}{9}+\dfrac{14}{6}+\dfrac{19}{13}\)

\(=\dfrac{2}{3}+\dfrac{7}{13}+\dfrac{17}{9}-\dfrac{8}{9}+\dfrac{7}{3}+\dfrac{19}{13}\)

\(=\left(\dfrac{2}{3}+\dfrac{7}{3}\right)+\left(\dfrac{7}{13}+\dfrac{19}{13}\right)+\left(\dfrac{17}{9}-\dfrac{8}{9}\right)\)

\(=\dfrac{9}{3}+\dfrac{26}{13}+\dfrac{9}{9}\)

\(=3+2+1\)

\(=6\)

b) \(\dfrac{328}{435}\times\dfrac{468}{432}\times\dfrac{435}{164}\times\dfrac{432}{984}\times\dfrac{164}{468}\)

\(=\dfrac{328\times468\times435\times432\times164}{435\times432\times164\times984\times468}\)

\(=\dfrac{328}{984}\)

\(=\dfrac{1}{3}\)

a) \(\dfrac{3}{8}+\dfrac{7}{12}+\dfrac{10}{16}+\dfrac{10}{24}\)

\(=\dfrac{3}{8}+\dfrac{7}{12}+\dfrac{5}{8}+\dfrac{5}{12}\)

\(=\left(\dfrac{3}{8}+\dfrac{5}{8}\right)+\left(\dfrac{7}{12}+\dfrac{5}{12}\right)\)

\(=1+1\)

\(=2\)

b) \(\dfrac{4}{6}+\dfrac{7}{13}+\dfrac{17}{9}+\dfrac{19}{13}+\dfrac{1}{9}+\dfrac{14}{6}\)

\(=\dfrac{2}{3}+\dfrac{7}{13}+\dfrac{17}{9}+\dfrac{19}{13}+\dfrac{1}{9}+\dfrac{7}{3}\)

\(=\left(\dfrac{2}{3}+\dfrac{7}{3}\right)+\left(\dfrac{7}{13}+\dfrac{19}{13}\right)+\left(\dfrac{17}{9}+\dfrac{1}{9}\right)\)

\(=3+2+2\)

\(=7\)

c) \(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}\)

\(=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}+\dfrac{1}{5\cdot6}+\dfrac{1}{6\cdot7}\)

\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}\)

\(=1-\dfrac{1}{7}\)

\(=\dfrac{6}{7}\)

\(A=\frac{2^{10}.13+2^{10}.65}{2^8.104}\)

\(A=\frac{2^8.2.78}{2^8.104}\)

\(A=\frac{2}{13}\)

\(\)

c) Ta có: \(\dfrac{3}{5}+\dfrac{-5}{20}+\dfrac{30}{75}+\dfrac{-7}{4}\)

\(=\dfrac{3}{5}+\dfrac{2}{5}+\dfrac{-1}{4}+\dfrac{-7}{4}\)

\(=1-2=-1\)

Giải:

a)-1/12+4/3=-1/12+16/12=15/12=5/4

b)(-4/14-3/15)-(1/5-20/35-(-1)).7

=-17/35-22/35.7

=-17/35-22/5

=-171/35

c)3/5+-5/20+30/75+-7/4

=3/5+-1/4+2/5+-7/4

=(3/5+2/5)+(-1/4+-7/4)

=1+-2

=-1

d)5/6.-12/14+7/13

=-5/7+7/13

=-16/91

e)2/-9-5/-36-1/4

=-1/12-1/4

=-1/3

f)2/23+-5/12+7/18+21/23+-7/12

=(2/23+21/23)+(-5/12+-7/12)+7/18

=1+-1+7/18

=7/18

xcsxccsz

a) -36

b) 390

c) 323

d) 1270

e) 0

f)  0

잘 공부

a)Ta có 60 = 2 2 .3. 5; 280 = 2 3 .5.7

BCNN(60; 280) =  2 3 . 3.5.7= 840

b) Ta có: 84 =  2 2 .3.7; 108 =  2 2 . 3 3

BCNN(84; 108) =  2 2 . 3 3 .7 = 756

c) Ta có: 13 =13; 15= 3.5

BCNN(13; 15) = 13.3.5= 195.

d) Ta có; 10 = 2.5; 12 =  2 2 .3; 15 = 3.5

BCNN(10;12; 15) =  2 2 .3.5 = 60

e) Ta có: 8 = 2 3 ; 9 =  3 2 ; 11 = 11

BCNN(8; 9; 11) = 2 3 . 3 2 .11= 792

f) Ta có: 24 = 3. 2 3 ; 40 =  2 3 .5; 168 =  2 3 .3.7

BCNN(24; 40; 168)=  2 3 .3. 5.7= 840

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