tìm x
x-4=26 (40+x)x2=180 (14+5x):2= 3 mũ 5 : 3 mũ 2
tìm x
x-4=26 (40+x)x2=180 (14+5x):2= 3 mũ 5 : 3 mũ 2
\(x-4=26\\ \Leftrightarrow x=30\)
\(\left(40+x\right).2=180\\ \Leftrightarrow40+x=90\\ \Leftrightarrow x=50\)
\(\left(14+5x\right):2=3^5:3^2\\ \Leftrightarrow\left(14+5x\right):2=27\\ \Leftrightarrow14+5x=54\\ \Leftrightarrow5x=40\\ \Leftrightarrow x=8\)
a) x-4=26
x=26+4= 30
b) (40+x)x2=180
40+x=180:2
40+x= 90
x=90-40=50
c) ( 14+5x):2=35: 32
14+5x:2=33=27
14+5x=27x2
14+5x=54
5x=54-14
5x=40
x=8
x-4=26 (40+x).2=180 (14+5.x):2=35:32
x=26+4 40+x= 90 (14+5.x):2=33
x=30 x=90-40 (14+5.x):2=27
x=50 (14+5.x)=27.2
14+5.x=54
5.x=54-14
5.x=40
x=40:5
x=8
tìm x
x-4=26 (40+x)x2=180 (14+5x):2= 3 mũ 5 : 3 mũ 2
làm jum tui đi ;((
bài 49; tìm x;
1, 3x ( x - 7) 2x - 14 = 0
2, x mũ 3 + 3x mũ 2 - ( x + 3) = 0
3, 15x - 5 + 6x mũ 2 - 2x = 0
4, 5x - 2 - 25x mũ 2 + 10x = 0
1, \(3x\left(x-7\right)+2x-14=0\)
\(\Rightarrow3x\left(x-7\right)+2\left(x-7\right)=0\)
\(\Rightarrow\left(x-7\right)\left(3x+2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=7\\x=\frac{-2}{3}\end{cases}}\)
2, \(x^3+3x^2-\left(x+3\right)=0\)
\(\Rightarrow x^2\left(x+3\right)-\left(x+3\right)=0\)
\(\Rightarrow\left(x+3\right)\left(x^2-1\right)=0\)
\(\Rightarrow\left(x+3\right)\left(x-1\right)\left(x+1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x=-3\\x=\pm1\end{cases}}\)
3, \(15x-5+6x^2-2x=0\)
\(\Rightarrow\left(15x-5\right)+\left(6x^2-2x\right)=0\)
\(\Rightarrow5\left(3x-1\right)+2x\left(3x-1\right)=0\)
\(\Rightarrow\left(3x-1\right)\left(5+2x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}3x-1=0\\5+2x=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{3}\\x=\frac{-5}{2}\end{cases}}\)
4, \(5x-2-25x^2+10x=0\)
\(\Rightarrow\left(5x-25x^2\right)-\left(2-10x\right)=0\)
\(\Rightarrow5x\left(1-5x\right)-2\left(1-5x\right)=0\)
\(\Rightarrow\left(1-5x\right)\left(5x-2\right)=0\)
\(\Rightarrow\orbr{\begin{cases}1-5x=0\\5x-2=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{5}\\x=\frac{2}{5}\end{cases}}\)
bài 9; tìm x
1, 3x( x - 7) 2x - 14 = 0
2, x mũ 3 + 3x mũ 2 - ( x + 3 )= 0
3, 15x - 5 + 6x mũ 2 - 2x =0
4, 5x - 2 - 25x mũ 2 + 10x = 0
12+(5+x)=20
5.2 mũ 2+(x+3)=5 mũ 2
2 mũ 3 +(x+3)=5 mũ 2
4 mũ 3 -(x-2)=5 mũ 2
7 nhân ( x +5 ) + 14 = 7 mũ 3
14 x - 2 nhân 7 mũ 2=2 nhân 3 nhân 7
6 nhân ( x + 2 mũ 3 ) + 40 = 100
155 - 10 nhan ( x +1)=55
12 + ( 5 + x ) = 20 5.22 + ( x + 3 ) = 52 23 + ( x + 3 ) = 52 43 - ( x - 2 ) = 52
17 + x = 20 5.4 + x + 3 = 25 8 + x + 3 = 25 64 - x + 2 = 25
x = 20 - 17 20 + 3 + x = 25 11 + x = 25 66 - x = 25
x = 3 23 + x = 25 x = 25 - 11 x = 66 - 25
x = 25 - 23 x = 14 x = 41
x = 2
Đăng nhìu v bn :) Đáng quan ngại đây :)
bài 1 tìm x biết rằng
a, [ 2x - 3 ] mũ 2 - [2x + 1] mũ 2 = -3
b, [5x - 1] mũ 2 - [5x + 4] [5x - 4] = 7
c, [ x- 5] mũ 2 + [x-3][x+3] - 2[x + 1] mũ 2 =0
a, ( 2x - 3 )2- (2x + 1)2 = -3
4x2-12x+9-4x2+4x-1=-3
-8x-1=-3
-8x=-2
x=\(\frac{1}{4}\)
b, (5x - 1) 2 - (5x + 4)(5x - 4) = 7
25x2-10x+1-25x2+16=7
-10x+17=7
-10x=-10
x=1
c, ( x- 5)2 + (x-3)(x+3) - 2(x + 1)2=0
x2-10x+25+x2-9-2x2-4x-2=0
-14x+14=0
-14(x-1)=0
=>x-1=0
x=1
a) \(\left(2x-3\right)^2-\left(2x+1\right)^2=-3\)
\(\Leftrightarrow4x^2-12x+9-4x^2-4x-1=-3\)
\(\Leftrightarrow-16x+8=-3\)
\(\Leftrightarrow-16x=-11\)
\(\Leftrightarrow x=\frac{11}{16}\)
b)\(\left(5x-1\right)^2-\left(5x+4\right)\left(5x-4\right)=7\)
\(\Leftrightarrow25x^2-10x+1-25x^2+16=7\)
\(\Leftrightarrow-10x+17=7\)
\(\Leftrightarrow-10x=-10\)
\(\Leftrightarrow x=1\)
c)\(\left(x-5\right)^2+\left(x-3\right)\left(x+3\right)-2\left(x+1\right)^2=0\)
\(\Leftrightarrow x^2-10x+25+x^2-9-2\left(x^2+2x+1\right)=0\)
\(\Leftrightarrow2x^2-10x-16-2x^2-4x-2=0\)
\(\Leftrightarrow-14x-18=0\)
\(\Leftrightarrow-14x=18\)
\(\Leftrightarrow x=-\frac{9}{7}\)
#H
ài 7:tính giá trị của biểu thức:
a) 3 mũ 8 : 3 mũ 4 + 2 mũ 2 x 2 mũ 3=
b)3x 4 mũ 2 - 2 . 3=
c)4 mũ sáu . 3 mũ 4 . 9 mũ 5 : 6mũ 12=
d)21 mũ 2 . 14. 125 : 35 mũ 3 . 6=
e)45 mũ 3 . 20 mũ 4 . 18 mũ 2 : 180 mũ 5
a) 38 : 34 + 22 x 23 = 113
b) 3 x 42 - 2 . 3 = 42
c) 46 . 34 . 95 : 612 = 9
d) 212 . 14 . 125 : 353 . 6 = 108
e) 453 . 204 .182 : 1805 = 25
#BạcHà#
bn ơi ghi cả cách làm nữa bn
ai lm lun cách làm mk sẽ k cho 2 k lun
đợi xíu nhé tí nữ mình trả lời cho bh mình đanbg bận
tìm x
a, 100-7(x-5)=31+3 mũ 3
b, 12(x-1) : 3 = 4 mũ 3 + 2 mũ 3
c, 24+5x=7 mũ 5 : 7 mũ 3
5x-206 = 2 mũ 4 . 4
125=x mũ 3
64=x mũ 2
giúp mik nha!!!!!!!!!!!!!
a, 100 - 7 ( x - 5 ) = 31 + 33
100 - 7 ( x - 5 ) = 31 + 27
100 - 7 ( x - 5 ) = 58
7 ( x - 5 ) = 100 - 58
7 ( x - 5 ) = 42
x - 5 = 42 : 7
x - 5 = 6
=> x = 6 +5
=> x = 11
Vậy x = 11
b, 12 ( x - 1 ) : 3 = 43 + 23
12 ( x - 1 ) : 3 = 64 + 8
12 ( x - 1 ) : 3 = 72
12 ( x - 1 ) = 72 . 3
12 ( x - 1 ) = 216
x - 1 = 216 : 12
x - 1 = 18
=> x = 18 + 1
=> x = 19
Vậy x = 19
c, 24 + 5x = 75 : 73
24 + 5x = 72
24 + 5x = 49
5x = 49 - 24
5x = 25
=> x = 25 : 5
=> x = 5
Vậy x = 5
d, 5x - 206 = 24 . 4
5x - 206 = 16 . 4
5x - 206 = 64
5x = 64 + 206
5x = 270
=> x = 270 : 5
=> x = 54
Vậy x = 54
e, 125 = x3
53 = x3
=> x = 5
Vậy x = 5
g, 64 = x2
82 = x2
=> x = 8
Vậy x = 8
27 . 65 + 27 . 35 + 300
3838 : [( 190 - 6 . 5 mũ 2 ) : 4 + 3 }
2022 - x = 2021
26 + 14 : ( x - 5 ) = 33
2 . 3 mũ x + 38 = 92
a)\(27.65+27.35+300=27.\left(65+35\right)+300\)
\(=27.100+300=2700+300=3000\)
b)\(3838:\left[\left(190-6.5^2\right):4+3\right]\)
\(=3838:\left[\left(190-6.25\right):4+3\right]\)
\(=3838:\left[\left(190-150\right):4+3\right]\)
\(=3838:\left[40:4+3\right]=3838:\left[10+3\right]\)
\(=3838:13=\dfrac{3838}{13}\)
c)\(2022-x=2021\)
\(x=2022-2021=1\)
d)\(26+14:\left(x-5\right)=33\)
\(14:\left(x-5\right)=33-26=7\)
\(x-5=14+7=2\)
\(x=2+5=7\)
e)đề hỏi làm j thế bạn