\(\left(3-\sqrt{2x}\right)\left(2-3\sqrt{2x}\right)=6x-5\)ĐK : x>= 0 

\(\Leftrightarrow6-9\sqrt{2x}-2\sqrt{2x}+6x=6x-5\)

\(\Leftrightarrow-11\sqrt{2x}+6x+6=6x-5\Leftrightarrow-11\sqrt{2x}=-11\)

\(\Leftrightarrow\sqrt{2x}=1\Leftrightarrow2x=1\Leftrightarrow x=\dfrac{1}{2}\left(tm\right)\)

\(\Leftrightarrow\left(2x+3-2x+5\right)^2=x^2+6x+64\)

=>x^2+6x=0

=>x(x+6)=0

=>x=0 hoặc x=-6

a) = (3x +1)² =0 

3x+1 =0

x = -1/3

b) = (5x)² -2² =0

(5x+2)(5x-2) = 0

5x+2 =0

x = -2/5

5x -2  =0

x= 2/5

xem đi rui lam tip

a) 9x² + 6x + 1 = 0  => (3x)² + 2 x 3x + 1 = 0  => (3x + 1)²  = 0  => 3x + 1 = 0  => x = \(\frac{-1}{3}\)

b) 25x² = 4  => x² = 4 : 25  => x² = 0,16  => x = 0,4 hoặc x = -0,4

c) 8 - 125x³ = 0  => 125x³ = 8  => x³ = 8 : 125  => x³ = \(\frac{8}{125}\)=> x = \(\frac{2}{5}\)

c) = 2³ - (5x)³ =0

(2-5x)(4 +10x +25x²) =0

2-5x=0

x = 2/5

4 + 10x +25x²  = 0 (máy tính giải dc)

d) = (( 2x+1) - 5(x+2))² =0

2x+1 -5x -10=0

3x= -9

x = -3

(hoàn toàn ad hđt đáng nhớ thui,bn à)

a)\(2x^4-6x^3+x^2+6x-3=0\)

\(\Leftrightarrow2x^4-6x^3+3x^2-2x^2+6x-3=0\)

\(\Leftrightarrow x^2\left(2x^2-6x+3\right)-\left(2x^2-6x+3\right)=0\)

\(\Leftrightarrow\left(x^2-1\right)\left(2x^2-6x+3\right)=0\)

\(\Leftrightarrow\left(x-1\right)\left(x+1\right)\left(2x^2-6x+3\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x-1=0\\x+1=0\\2x^2-6x+3=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=1\\x=-1\\\Delta_{2x^2-6x+3}=\left(-6\right)^2-4\left(2.3\right)=12\end{array}\right.\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x=1\\x=-1\\x_{1,2}=\frac{6\pm\sqrt{12}}{4}\end{array}\right.\)

b)\(x^3+9x^2+26x+24=0\)

\(\Leftrightarrow x^3+5x^2+6x+4x^2+20x+24=0\)

\(\Leftrightarrow x\left(x^2+5x+6\right)+4\left(x^2+5x+6\right)=0\)

\(\Leftrightarrow\left(x^2+5x+6\right)\left(x+4\right)=0\)

\(\Leftrightarrow\left(x+2\right)\left(x+3\right)\left(x+4\right)=0\)

\(\Leftrightarrow\left[\begin{array}{nghiempt}x+2=0\\x+3=0\\x+4=0\end{array}\right.\)\(\Leftrightarrow\left[\begin{array}{nghiempt}x=-2\\x=-3\\x=-4\end{array}\right.\)

12x/6 + 4x/6 - 3x/6 = 3/8 - 1/4 - 1/6

13x/6 = (9 - 6 - 4)/24 = -1/24

--> x = -1/52

4x(3x - 5) + 2x(8 - 6x) = 24

12x² - 20x + 16x - 12x² = 24

-4x = 24

x = -6

* Chúc bạn học tốt .

4x(3x -5)+2x(8-6x) =24

=>2x(3x-5)+x(8-6x)=12

=>6x²-10x+8x-6x²=12

=>-2x=12

=>x=-6

=>x+6=0

=>x=-6