Tính:
a, 9×7 + 56
b, 28×3 - 15
Những câu hỏi liên quan
1,Tính
A, 14/7 + 5/9 + 4/9 - 2
B, 31/25 + ( 15/16 - 6/15 ) + 1/16
C, 23/28 - ( 23/28 - 1/3 ) +2/3
D, 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90
a) \(\frac{14}{7}+\frac{5}{9}+\frac{4}{9}-2\)
\(=2\frac{5}{9}+\frac{4}{9}-2\)
\(=3-2=1\)
b) \(\frac{31}{25}+\left(\frac{15}{16}-\frac{6}{15}\right)+\frac{1}{16}\)
\(=\frac{31}{25}+\frac{43}{80}+\frac{1}{16}\)
\(=1\frac{311}{400}+\frac{1}{16}\)
\(=1\frac{21}{25}\)
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Thực hiện phép tính sau:
a)(9/10—15/16)(5/12—11/15—7/20)
b)—3/5+28/5(43/56+5/24—21/63)
Tính
1, 14/7 + 5/9 + 4/9 - 2
2, 31/25 + ( 15/16 - 6/15 ) + 2/3
3, 23/28 - ( 23/28 - 1/3 ) + 2/3
4, 1/12 + 1/20 + 1/30 + 1/42 + 1/56 + 1/72 + 1/90
Làm giúp mình một vài con toán này với: Tính bằng phương pháp hợp lí nhất nhá
a) (9/10 - 15/16) * ( 5/12 - 11/15 -7/20 )
b) -3/5 + 28/5 * ( 43/56 + 5/24 - 21/63)
c) ( 1 +1/2 ) * ( 1 * 1/3 ) * ( 1+1/4 ) *...* ( 1* 1/99 )
(-9/10-15/16).(5/12-11/15-7/20)
5/14.1/3.-4/15:5/7
-3/5+28/5.(43/56+5/24-21/63)
| a) 3/13 + 7/12 - 10/13 + 5/12 | d) -5/10 + 12/28 - 3/27 - 7/18 + 20/35 |
| b) 15/24 - 6/26 + 28/48 - 30/39 + 10/24 | e) 1/56 + 1/72 + 1/90 + 1/110 + 1/132+ 1/156 = |
| c) -1/2 + 3/7 - 1/9 - 7/18 + 4/7 = |
a) \(\left(\frac{9}{10}-\frac{15}{16}\right).\left(\frac{5}{12}-\frac{11}{15}-\frac{7}{20}\right)\)
B) \(\frac{-3}{5}+\frac{28}{5}.\left(\frac{43}{56}+\frac{5}{24}-\frac{21}{63}\right)\)
thực hiện phép tính
Tìm x:a) dfrac{-3}{7}.xdfrac{3}{56}.dfrac{28}{9}b) x-dfrac{3}{16}dfrac{7}{15}:dfrac{3}{5}c) dfrac{2}{5}+dfrac{1}{5}.xdfrac{5}{6}d) dfrac{3}{4}x-dfrac{2}{5}xdfrac{3}{7}.dfrac{1}{6}+dfrac{5}{7}.dfrac{1}{6}*Lưu ý: Trình bày chi tiết kết quả.
Đọc tiếp
Tìm x:
a) \(\dfrac{-3}{7}\).x=\(\dfrac{3}{56}\).\(\dfrac{28}{9}\)
b) x-\(\dfrac{3}{16}\)=\(\dfrac{7}{15}\):\(\dfrac{3}{5}\)
c) \(\dfrac{2}{5}\)+\(\dfrac{1}{5}\).x=\(\dfrac{5}{6}\)
d) \(\dfrac{3}{4}\)x-\(\dfrac{2}{5}\)x=\(\dfrac{3}{7}\).\(\dfrac{1}{6}\)+\(\dfrac{5}{7}\).\(\dfrac{1}{6}\)
*Lưu ý: Trình bày chi tiết kết quả.
a)\(x=\left(\dfrac{3}{56}\cdot\dfrac{28}{9}\right):\dfrac{-3}{7}=\dfrac{1}{6}:\dfrac{-3}{7}=-\dfrac{7}{18}\)
b)\(x=\left(\dfrac{7}{15}\cdot\dfrac{5}{3}\right)+\dfrac{3}{16}=\dfrac{7}{9}+\dfrac{3}{16}=\dfrac{139}{144}\)
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c)\(x=\left(\dfrac{5}{6}-\dfrac{2}{5}\right).5=\dfrac{13}{6}\)
d)\(=>x\left(\dfrac{3}{4}-\dfrac{2}{5}\right)=\dfrac{1}{6}\cdot\left(\dfrac{3}{7}+\dfrac{5}{7}\right)\)
\(x\cdot\dfrac{7}{20}=\dfrac{4}{21}=>x=\dfrac{4}{21}\cdot\dfrac{20}{7}=\dfrac{80}{147}\)
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tính
a)\(\dfrac{-10}{11}.\dfrac{8}{9}+\dfrac{7}{18}.\dfrac{10}{11}\)
b)\(\dfrac{3}{14}:\dfrac{1}{28}-\dfrac{13}{21}:\dfrac{1}{28}+\dfrac{29}{42}:\dfrac{1}{28}-8\)
c)\(-1\dfrac{5}{7}.15+\dfrac{2}{7}\left(-15\right)+\left(-105\right).\left(\dfrac{2}{3}-\dfrac{4}{5}+\dfrac{1}{7}\right)\)
a)\(\dfrac{-10}{11}.\dfrac{8}{9}+\dfrac{7}{18}.\dfrac{10}{11}\)
=\(\dfrac{10}{11}.\dfrac{-8}{9}+\dfrac{7}{18}.\dfrac{10}{11}\)
=\(\dfrac{10}{11}(\dfrac{-8}{9}+\dfrac{7}{18})\)
=\(\dfrac{10}{11}.\dfrac{-1}{2}\)
=\(\dfrac{-5}{11}\)
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b;
B = \(\dfrac{3}{14}\) : \(\dfrac{1}{28}\) - \(\dfrac{13}{21}\): \(\dfrac{1}{28}\) + \(\dfrac{29}{42}\) : \(\dfrac{1}{28}\) - 8
B = (\(\dfrac{3}{14}\) - \(\dfrac{13}{21}\) + \(\dfrac{29}{42}\)) - 8
B = (\(\dfrac{9}{42}\) - \(\dfrac{26}{42}\) + \(\dfrac{29}{42}\)) - 8
B = (\(\dfrac{-17}{42}\) + \(\dfrac{29}{42}\)) - 8
B = \(\dfrac{2}{7}\) - 8
B = \(\dfrac{2}{7}-\dfrac{56}{7}\)
B = - \(\dfrac{54}{7}\)
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c; C = -1\(\dfrac{5}{7}\).15 + \(\dfrac{2}{7}\)(-15) + (-105).(\(\dfrac{2}{3}\) - \(\dfrac{4}{5}\) + \(\dfrac{1}{7}\))
C = - 15.(- 1 - \(\dfrac{5}{7}\) + \(\dfrac{2}{7}\) + \(\dfrac{14}{3}\) - \(\dfrac{28}{5}\) + \(1\))
C = -15.[(1 - 1) - (\(\dfrac{5}{7}\) - \(\dfrac{2}{7}\)) + \(\dfrac{14}{3}\) - \(\dfrac{28}{5}\)]
C = -15.[0 - \(\dfrac{3}{7}\) + \(\dfrac{14}{3}\) - \(\dfrac{28}{5}\)]
C = -15 . [- \(\dfrac{45}{105}\) + \(\dfrac{490}{105}\) - \(\dfrac{588}{105}\)]
C = -15. [ \(\dfrac{445}{105}\) - \(\dfrac{588}{105}\)]
C = - 15.(- \(\dfrac{143}{105}\))
C = \(\dfrac{143}{7}\)
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