Đặt S= 1.2 + 2.3 + 3.4 + ...+ 99.100
 3S = 1.2.3+2.3.3+3.4.3+...+98.99.3+99.100.3
3S= 1.2.3+2.3(4-1)+3.4(5-2)+...+98.99(100-97)+99.100(101-98)
3S= 1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...-97.98.99+99.100.101-98.99.100
3S = 99.100.101  3S = 3.33.100.101 
 S=33.100.101= 333300

Bạn rút gọn chéo đi 2 với 2 ,3 với 3 cứ như thế còn mỗi 1/100. k nhé

Ta có: C = 1.2 + 2.3 + 3.4 + ... + 99.100

=> 3C=3 (1.2 + 2.3 + 3.4 + ... + 99.100)

=> 3C = 1.2.(3-0)+2.3.(4-1)+....+99.100.(101-98)

=> 3C= 1.2.3-1.2.3+2.3.4-2.3.4+....+99.100.101

=> 3C=99.100.101

=> C=99.100.101/3=333300

Nha bạn      

tick nha

 S=1.2+ 2.3+.......+99.100 
Nhân cả 2 vế với 3, ta được: 
3S=1.2.3+ 2.3.3+ 3.4.3+ 4.5.3+...... 99.100.3 
= 1.2.3 + 2.3(4-1) + 3.4.(5-2) +...+ 99.100.(101-98) 
= 1.2.3 + 2.3.4 -1.2.3 + 3.4.5-2.3.4 +...+ 99.100.101-98.99.100 
= 99.100.101 
----> S = (99.100.101):3 
S = 333300 
Vậy S=333300 

de

3S=1.2.(3-0)+2.3.(4-1)+...+99.100(101-98)

3S=1.2.3-0.1.2+2.3.4-1.2.3+...+99.100.101-98.99.100

3S=(1.2.3+2.3.4+...+99.100.101)-(0.1.2+1.2.3+...+98.99.100)

3S=99.100.101-0.1.2

3S=99.100.101

S=\(\frac{99.100.101}{3}=333300\)

S = 1 . 2 + 2 . 3 + 3 . 4 + ...... + 99 . 100 

Gấp S lên 3 lần ,ta có: 

S . 3 = 1 . 2 . 3 + 2 . 3 . 3 + 3 . 4 . 3 + … + 99 . 100 . 3 

S . 3 = 1 . 2 . 3 + 2 . 3 . ( 4 - 1 ) + 3 . 4 . ( 5 - 2 ) + … + 99 . 100 . ( 101 - 98 ) 

S . 3 = 1 . 2 . 3 + 2 . 3 . 4 - 1 . 2 . 3 + 3 . 4 . 5 - 2 . 3 . 4 + … + 99 . 100 . 101 - 98 . 99 . 100 

S . 3 = 99 . 100 . 101 

S = 99 . 100 .101 : 3 

S = 33 . 100 . 101 

S = 333300

Gọi A là biểu thức ta có: 
S = 1.2+2.3+3.4+......+98.99+99.100 
Gấp S lên 3 lần ta có: 
S . 3 = 1.2.3 + 2.3.3 + 3.4.3 + … + 99.100.3 
S . 3 = 1.2.3 + 2.3.(4 - 1) + 3.4.( 5 - 2) + … + 99.100. (101 - 98) 
S . 3 = 1.2.3 + 2.3.4 - 1.2.3 + 3.4.5 - 2.3.4 + … + 99.100.101 - 98.99.100 
S . 3 = 99.100.101 
S = 99.100.101 : 3 
S = 33.100.101 
S = 333 300

S=1.2+2.3+3.4+4.5+....+99.100

3S=1.2.3+2.3.3+3.4.3+4.5.3+....+99.100.3

3S=1.2.3+2.3.(4-1)+3.4.(5-1)+4.5(6-3)+....+99.100(101-98)

3S=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-2.4.5+....+99.100.101-98.99.100

3S=1.2.3-1.2.3+2.3.4-2.3.4+3.4.5-3.4.5+4.5.6-4.5.6+.......+99.100.101

3S=99.100.101

3S=999900

S=999900:3

S=333300

S=1.2+2.3+3.4+4.5+...+99.100

3S=1.2.3+2.3.(4-1)+3.4.(5-2)+4.5.(6-3)+...+99.100.(101-98)

3S=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+4.5.6-3.4.5+...+99.100.101-98.99.100

3S=99.100.101

S=(99.100.101):3=333300

S=1.2+2.3+3.4+4.5+...+99.100

=>3S=1.2.3+2.3.3+3.4.3+4.5.3+...+99.100.3

=1.2.3+2.3.﴾4‐1﴿+3.4.﴾5‐2﴿+4.5.﴾6‐3﴿+...+99.100.﴾101‐98﴿

=1.2.3+2.3.4‐1.2.3+3.4.5‐2.3.4+4.5.6‐3.4.5+...+99.100.101‐98.99.100

=1.2.3‐1.2.3+2.3.4‐2.3.4+3.4.5‐3.4.5+4.5.6‐4.5.6+...+99.100.101

=99.100.101=999900

=>S=999900:3=333300

Vậy S=333300

Ta có: 3A=1.2.3+2.3.3+3.4.3+.....+99.100.3

3A=1.2.3+2.3.(4-1)+3.4..(5-2)+....+99.100.(101-98)

3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+....+99.100.101-98.99.100

3A=99.100.101

A=\(\frac{99.100.101}{3}\)

A=333300

Đặt A= 1.2+2.3 +.......+99.100

3A= 1.2.3+2.3.4+3.4.3 +......+ 99.100.3

3A= 1.2. (3 - 0) + 2.3.(4 - 1) +3.4. (5 - 2)....... . 99.100. (101 - 98)

3A = (1.2.3 + 2.3.4 + 3.4.5 +...... + 99.100.101) - (0.1.2 + 1.2.3 + 2.3.4 +.......+ 98.99.100)

3A = 99.100.101 - 0.1.2

3A = 999900 - 0

3A= 999900

A= 999900 : 3

A = 333300

3A=1×2×3+2×3×3+3×4×3+...+99×100×3

3A=1×2×(3-0)+2×3×(4-1)+3×4×(5-2)+...+99×100×(101-98)

3A=1×2×3 + 2×3×4 - 2×3×1 + 3×4×5 - 3×4×2 +...+ 99×100×101 - 99×100×98

3A=99×100×101

=>A=99×100×101/3=333300

Tk mình nha bn !

\(\frac{1}{1.2}+\frac{1}{2.3}+...+\frac{1}{12.13}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{12}-\frac{1}{13}\)

\(=1-\frac{1}{13}\)

\(=\frac{12}{13}\)

1/1.2+1/2.3+...+1/12.13

=1-1/2+1/2-1/3+...+1/12-1/13

=1-1/13

=12/13

\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{12.13}\)

\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{12}-\frac{1}{13}\)

\(=1-\frac{1}{13}\)

\(=\frac{12}{13}\)

=.= hk tốt!!

3A=1.2.3+2.3.(4-1)+3.4.(5-2)+...+99.100.(101-98)

3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+...+99.100.101-98.99.100

3A=98.100.101

A=99.100.101 / 3

A=333300

Mình cho bạn dạng tổng quát nha

1.2+2.3+...+n.(n+1)=n(n+1)(n+2) / 3

3A=1.2.3+2.3.(4-1)+...........+99.100.(101-98)

3A=1.2.3+2.3.4-1.2.3+............+99.100.101-98.99.100

3A=99.100.101

A=99.100.101:3

A=333300

ta có 3A=1.2.(3-0)+2.3(4-1)+2.4(5-2)+ ...+97.98(99-96)

            =(1.2.3+2.3.4+3.4.5+....+97.98.99+98.99.100)-(0.1.2+1.2.3+2.3.4+....+96.97.98+97.98.99)

            =98.99.100=970200

=>A=970200:3=323400

mk học bài này rồi

\(P=\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{99\cdot100}\)

\(P=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{99}-\frac{1}{100}\)

\(P=1-\frac{1}{100}\)

\(P=\frac{99}{100}\)

P = 1/1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4+ 1/4 - 1/5 + ............. + 1/99 - 1/100

   = 1/1 - 1/100

   = 99/100

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