a: 3/5>-19/5

b: 8/7<8/3

c: 3/4=15/20

2/5=8/20

mà 15>8

nên 3/4>2/5

d: -3/5=-18/30

-4/6=-20/30

mà -18>-20

nên -3/5>-4/6

a: 3/5>-19/5

b: 8/7<8/3

c: 3/4=15/20

2/5=8/20

mà 15>8

nên 3/4>2/5

d: -3/5=-18/30

-4/6=-20/30

mà -18>-20

nên -3/5>-4/6

\(A=2^5.5^2-8^2-7=800-64-7=729=27^2\)

\(B=2^3.4^2+3^2.3^2-40=128+81-40=169=13^2\)

\(C=11.2^4+6^2.19+40=176+684+40=900=30^2\)

\(D=4^3+6^3+7^3+2=64+216+343+2=625=25^2\)

`a, 2/3 + 1/5 . 10/7`

`= 2/3 + 10/35`

`=2/3 +2/7`

`=14/21 + 6/21`

`=20/21`

`b, 2/7 + 5/7 . 14/25`

`=  2/7 +2/5`

`= 10/35+14/35`

`= 24/35`

`c, 7/12 - 27/7 . 1/18`

`= 7/12 - 3/14`

`= 31/84`

`d, 3/10 . (-5/6) - 1/8`

`= -1/4 -1/8`

`= -2/8 -1/8`

`= -3/8`

a)

\(\dfrac{2}{3}+\dfrac{1}{5}.\dfrac{10}{7}\)

\(=\dfrac{2}{3}+\dfrac{2}{7}\)

\(=\dfrac{14}{21}+\dfrac{6}{21}\)

\(=\dfrac{20}{21}\)

b)

\(\dfrac{2}{7}+\dfrac{5}{7}.\dfrac{14}{25}\)

\(=\dfrac{2}{7}+\dfrac{2}{5}\)

\(=\dfrac{10}{35}+\dfrac{14}{35}\)

\(=\dfrac{24}{35}\)

c)

\(\dfrac{7}{12}-\dfrac{27}{7}.\dfrac{1}{18}\)

\(=\dfrac{7}{12}-\dfrac{3}{14}\)

\(=\dfrac{98}{168}-\dfrac{36}{168}\)

\(=\dfrac{31}{84}\)

d)

\(\dfrac{3}{10}.\left(-\dfrac{5}{6}\right)-\dfrac{1}{8}\)

\(=-\dfrac{1}{4}-\dfrac{1}{8}\)

\(=-\dfrac{2}{8}-\dfrac{1}{8}\)

\(=\dfrac{-3}{8}\)

phân số nào bn

a: 4/5=12/15

9/15=9/15

b: 7/8=35/40

4/5=32/40

a: \(=\dfrac{-7}{8}\left(\dfrac{3}{5}+\dfrac{2}{5}\right)+3+\dfrac{7}{8}=\dfrac{-7}{8}+\dfrac{7}{8}+3=3\)

b: \(=-\dfrac{8}{5}:\dfrac{5}{3}=-\dfrac{24}{25}\)

c: \(=\dfrac{6}{7}+\dfrac{1}{8}-\dfrac{3}{4}=\dfrac{6}{7}+\dfrac{1}{8}-\dfrac{6}{8}=\dfrac{6}{7}-\dfrac{5}{8}=\dfrac{48}{56}-\dfrac{35}{56}=\dfrac{13}{56}\)

Phương pháp giải:

- Đếm số lượng các số hạng giống nhau của mỗi tổng.

- Viết phép nhân thích hợp.

Lời giải chi tiết:

a) 2 + 2 + 2 + 2 + 2 = 2 × 5

b) 5 + 5 + 5 + 5 = 5 × 4

c) 8 + 8 + 8 = 8 × 3

d) 4 + 4 + 4 = 4 × 3

e) 7 + 7 + 7 + 7 + 7 = 7 × 5

g) 10 + 10 = 10 × 2

a: \(\dfrac{7}{8}=\dfrac{441}{504}\)

\(\dfrac{5}{14}=\dfrac{180}{504}\)

\(\dfrac{4}{63}=\dfrac{32}{504}\)

b: \(\dfrac{2}{5}=\dfrac{72}{180}\)

\(\dfrac{13}{45}=\dfrac{52}{180}\)

\(\dfrac{5}{12}=\dfrac{75}{180}\)

a: \(=\dfrac{6}{7}\cdot\dfrac{-3}{5}=\dfrac{-18}{35}\)

b: \(=\dfrac{2}{5}\cdot\dfrac{-15}{8}=\dfrac{-30}{40}=-\dfrac{3}{4}\)

c: \(=\dfrac{2}{4}\cdot\dfrac{7}{3}=\dfrac{1}{2}\cdot\dfrac{7}{3}=\dfrac{7}{6}\)

d: \(=\dfrac{8}{3}\cdot\dfrac{16}{4}=\dfrac{128}{12}=\dfrac{32}{3}\)

a)-18/35

b)-3/4

c)7/6

d)32/3

e)5/21

sai thì xin lỗi nhé bn

Mình làm mẫu 1 bài rùi bạn tự giải những bài còn lại nha

1, 7A = 7+7^2+7^3+....+7^2008

6A = 7A - A = (7+7^2+7^3+....+7^2008)-(1+7+7^2+....+7^2007) = 7^2008-1

=> A = (7^2008-1)/6

Tk mk nha

\(A=1+7+7^2+7^3+...+7^{2007}\)

\(\Rightarrow7A=7+7^2+7^3+7^4+...+7^{2008}\)

\(\Rightarrow7A-A=\left(7+7^2+7^3+...+7^{2008}\right)-\left(1+7+7^2+...+7^{2007}\right)\)

\(\Rightarrow6A=7^{2008}-1\)

\(\Rightarrow A=\frac{7^{2008}-1}{6}\)

4b=4+4^2+4^3+...+4^101

4b-b=(4+4^2+...+4^101)-(1+4+4^2+...+4^100)

3b=4^101-1

b=(4^101-1):3