a)29 . (19 – 13) – 19 . (29 – 13)

= 29 . 6 – 19 . 16

= 174 – 304

= –130.

b)31.(-18)+31.(-81)-31       

= 31. [-18 + (-81) - 1 ]

= 31. (-100)

= -3100

c)(7.3-3):(-6)  

(7.3-3):(-6)

= (21-3):(-6)

= 18 : (-6)

= 3

d)72:[(-6).2+4)]       

= 72 : ( -12 + 4 )

= 72 : -8

= -9

Bài 2:

a)(-12).47+(-12).52+(-12)       

= (-12).(47+52+1)

= -1200

b)13.(23+22)-3.(17+28)  

13 . (23 + 22) - 3 . (17 + 28)

= 13 . 45 - 3 . 45

= ( 13 - 3 ) . 45

= 10 . 45

= 450

c)18-10:(-2)-7   

= 18-5+7

= 13+7

= 20

d)99:[(-7).2+5)

1. Tính nhanh

a) 29 . (19 – 13) – 19 . (29 – 13)

= 29 . 6 – 19 . 16

= 174 – 304

= –130.

b) 31 . (-18) + 31 . (-81) - 31       

= 31. [-18 + (-81) - 1 ]

= 31. (-100)

= -3100

c) (7 . 3 - 3) : (-6)

= (21 - 3) : (-6)

= 18 : (-6)

= 3

d) 72 : [(-6) . 2 + 4)]       

= 72 : ( -12 + 4 )

= 72 : -8

= -9

2. Tính nhanh

a) (-12) . 47 + (-12) . 52 + (-12)

= (-12) . (47 + 52 + 1)

= (-12) . 100

= -1200        
b) 13 . (23 + 22) - 3 . (17 + 28)   

= 13 . 45 - 3 . 45

= (13 - 3) . 45

= 10 . 45

= 450
c) 18 - 10 : (-2) - 7   

= 18-5+7

= 13+7

= 20

d) 99 : [(-7) . 2 + 5]

= 99 : -9

= -11

2/ 5 + 7/ 12 + 13 /12 = 2/ 5 + 20/ 12 = 2/ 5 + 5/ 3 = 6/ 15 + 25/ 15 = 31/ 15

\(=\dfrac{2}{5}+\left(\dfrac{7}{12}+\dfrac{13}{12}\right)\)

\(=\dfrac{2}{5}+\dfrac{5}{3}\)

\(=....\)

2/5 + 7/12 + 13/12

= 2/5 + 20/12

= 2/5 + 5/3

= 6/15 + 25/15

= 31/15

1, ( 37 . 13 - 13 . 1 ) : ( 24 + 37 . 12 )

    [ 13 . ( 37 - 1 ) ] : ( 12 . 2 + 37 . 12 )

    ( 13 . 36 ) : [ 12 ( 2 + 37 ) ]

   ( 13 . 36 ) : ( 12 . 36 )

    36

chắc z ^^ 

lm bừa ko cần mt

chac dung do 

bạn michial làm sai rồi phải biến đổi số bị chia để được số chia và đáp số là 1

=(17/12+19/12)+(3/5+2/5)+(8/13+18/13)

=3+1+2

=6

\(\frac{17}{12}+\frac{3}{5}+\frac{19}{12}+\frac{8}{13}+\frac{2}{5}+\frac{18}{13}\)

\(=\left(\frac{17}{12}+\frac{19}{12}\right)+\left(\frac{8}{13}+\frac{18}{13}\right)+\left(\frac{3}{5}+\frac{2}{5}\right)\)

\(=3+2+1\)

\(=6\)

a, 12- (-4)= 16
b, 12- (-14)= 26
c, (-13)-(-5)=-8
d, (-2)-(-10)= 8

a) \(\frac{1}{2}\times\frac{12}{13}+\frac{1}{3}\times\frac{12}{13}+\frac{1}{4}\times\frac{12}{13}\)

  = (1/2 + 1/3 + 1/4) x 12/13

  = 13/12 x 12/13

  = 1

b) (1 - 1/2 ) x (1 - 1/3) x (1 - 1/4) x ( 1  - 1/5)

=   1/2 x 2/3 x 3/4 x 4/5

=    1/5

\(\frac{2^{13}.3+2^{12}.3^2}{2^{12}.3}\)

\(=\frac{2^{12}.3\left(2+3\right)}{2^{12}.3}\)

\(=2+3\)

\(=5\)

tử số 2¹³.3+2¹².3²

        2¹².3.( 2+3 )

mẫu số 2¹².3

2¹³.3+2¹².3² : 2¹².3² = 2¹².3.( 2+3 ) : 2¹².3 = 1.5 = 5      

câu a) lấy mẫu số chung cộng với nhau

câu b) lấy 1 để ngoài nhân r 1/2-1/3 rồi tương tự

a) \(\dfrac{3}{8}+\dfrac{7}{12}+\dfrac{10}{16}+\dfrac{10}{24}\)

\(=\dfrac{3}{8}+\dfrac{7}{12}+\dfrac{5}{8}+\dfrac{5}{12}\)

\(=\left(\dfrac{3}{8}+\dfrac{5}{8}\right)+\left(\dfrac{7}{12}+\dfrac{5}{12}\right)\)

\(=1+1\)

\(=2\)

b) \(\dfrac{4}{6}+\dfrac{7}{13}+\dfrac{17}{9}+\dfrac{19}{13}+\dfrac{1}{9}+\dfrac{14}{6}\)

\(=\dfrac{2}{3}+\dfrac{7}{13}+\dfrac{17}{9}+\dfrac{19}{13}+\dfrac{1}{9}+\dfrac{7}{3}\)

\(=\left(\dfrac{2}{3}+\dfrac{7}{3}\right)+\left(\dfrac{7}{13}+\dfrac{19}{13}\right)+\left(\dfrac{17}{9}+\dfrac{1}{9}\right)\)

\(=3+2+2\)

\(=7\)

c) \(\dfrac{1}{2}+\dfrac{1}{6}+\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}+\dfrac{1}{42}+\dfrac{1}{56}\)

\(=\dfrac{1}{1\cdot2}+\dfrac{1}{2\cdot3}+\dfrac{1}{3\cdot4}+\dfrac{1}{4\cdot5}+\dfrac{1}{5\cdot6}+\dfrac{1}{6\cdot7}\)

\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}\)

\(=1-\dfrac{1}{7}\)

\(=\dfrac{6}{7}\)

Ta có:

\(A=\frac{3}{2}+\frac{7}{6}+\frac{13}{12}+...+\frac{9901}{9900}\)

\(A=1+\frac{1}{2}+1+\frac{1}{6}+1+\frac{1}{12}+...+1+\frac{1}{9900}\)\(A=1+1+1+...+1(51c/s)+\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{9900}\)

\(A=51+\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{99\cdot100}\)

\(A=51+1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{99}-\frac{1}{100}\)

\(A=51+1-\frac{1}{100}\)

\(A=52-\frac{1}{100}\)

\(A=\frac{5199}{100}\)

Cái đoạn 1+1+1+...+1 ( 51 c/s) số tớ ko thể giải thích trên máy tính đc nên bn tự suy nghĩ nhé:)))

A= 3/2+7/6+...+9901/9900

A=1+1/2+1+1/6+1+1/12+...+1/9900

A=(1+1+1+...+1)+(1/2+1/6+1/12+...+1/9900)

A=(1+1+1+...+1)+(1/1x2+1/2x3+1/3x4+...+1/99x100)

A=(1+1+1+...+1)+(1/1-1/2+1/2-1/3+1/3-1/4+1/4-...-1/99+1/99-1/100)

A=99+(1/1-1/100)

A=99+99/100

A=9999/100

A=9900/100+99