\(A=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right).2}\)

\(A=\frac{11.3^{22+7}-\left(3^2\right)^{15}}{2^2.\left(3^{14}\right)^2}\)

\(A=\frac{11.3^{29}-3^{30}}{4.3^{28}}\)

\(A=\frac{11.3^{29}-3^{29}.3}{4.3^{28}}\)

\(A=\frac{3^{29}.\left(11-3\right)}{3^{28}.4}\)

\(A=\frac{3^{28}.3.8}{3^{28}.4}\)

\(A=\frac{3^{28}.3.4.2}{3^{28}.4}\)

\(A=6\)

\(A=3.2\)

Vậy : \(A=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=6\)

a) \(\left(\dfrac{1}{6}+\dfrac{5}{9}\right)+\dfrac{4}{9}\)

\(=\dfrac{1}{6}+\dfrac{5}{9}+\dfrac{4}{9}\)

\(=\dfrac{1}{6}+1\)

\(=\dfrac{7}{6}\)

b) \(\dfrac{3}{17}+\left(\dfrac{14}{17}-\dfrac{2}{3}\right)\)

\(=\dfrac{3}{17}+\dfrac{14}{17}-\dfrac{2}{3}\)

\(=1-\dfrac{2}{3}\)

\(=\dfrac{1}{3}\)

c) \(\left(\dfrac{3}{2}-\dfrac{2}{3}\right)+\dfrac{7}{6}\)

\(=\left(\dfrac{9}{6}-\dfrac{4}{6}\right)+\dfrac{7}{6}\)

\(=\dfrac{13}{6}+\dfrac{7}{6}\)

\(=\dfrac{20}{6}\)

11/18

(10 + 3) - 9

= 13 - 9

= 4

   14 - 4 x 3 

= 14 - 12

= 2

10 x 2 x 3

= 20 x 3

 = 60

a (10+3)-9

13-9

=4

b14-4x3

10x3

30

10x2x3

20x3

60

13-9=4

Câu cuối cùng, em cảm ơn ag

\(\dfrac{7}{9}:\dfrac{14}{15}-\dfrac{1}{2}=\dfrac{5}{6}-\dfrac{1}{2}=\dfrac{5}{6}-\dfrac{3}{6}=\dfrac{2}{6}=\dfrac{1}{3}\)

`7/9:14/15-1/2=7/9xx15/14-1/2=5/6-1/2=5/6-3/6=2/6=1/3`

A = (1- 2) \(\times\) ( 4 - 3) \(\times\) (5 - 6) \(\times\) (8 - 7) \(\times\) (9 - 10) \(\times\) (12 - 11) \(\times\)(13 - 14)

A = (-1) \(\times\) 1 \(\times\) (-1)  \(\times\) 1 \(\times\) (-1) \(\times\) 1 \(\times\) (-1)

A = 1

        a) 7 x 9 – 18 =  63- 18                          b) 24 : 6 + 14 = 4 + 14

                             = 45                                                         = 18     

a) $2^3\cdot3^2+7^{16}:7^{14}-2022^0$

$=8\cdot9+7^2-1$

$=72+49-1$

$=120$

b) $2x-9=3\cdot(-7)$

$\Rightarrow2x-9=-21$

$\Rightarrow2x=-21+9$

$\Rightarrow2x=-12$

$\Rightarrow x=-12:2=-6$