trước số 8 là dấu nhân nha mn

\(=\dfrac{2}{7}\cdot\dfrac{3}{2}\cdot8-\dfrac{4}{5}=\dfrac{24}{7}-\dfrac{4}{5}=\dfrac{120-28}{35}=\dfrac{92}{35}\)

=2/7.3/2.8-4/5

=3/7.8-4/5

=24/7-4/5

=120/35-28/35

=82/35

\(\dfrac{2\cdot3\cdot8}{4\cdot5\cdot6\cdot7}=\dfrac{1}{2}\cdot\dfrac{1}{2}\cdot\dfrac{8}{35}=\dfrac{2}{35}\)

=(15a-15a):55

=0

Giải dc cho tiền tỳ!

ko hỉu đề bài thui        

Bảo người khác là đăng linh tinh thế mà chính mình cũng đăng linh tinh

Ta có \(x1-\frac{1}{9}=x2-\frac{2}{8}=...=x9-\frac{9}{1}\)

\(=\frac{x1-1}{9}=\frac{x2-2}{8}=\frac{x3-3}{7}=...=\frac{x9-9}{1}\)

= \(\frac{x1-1+x2-2+x3-3+...+x9-9}{9+8+7+...+1}\)

\(=\frac{\left(x1+x2+x3+...+x9\right)-\left(1+2+3+...+9\right)}{9+8+7+....+1}\)

=\(\frac{90-45}{45}=\frac{45}{45}=1\)

=> \(\hept{\begin{cases}\begin{cases}x1=10\\x2=10\end{cases}\\.....\\x9=10\end{cases}}\)

( 1 +8+ 2+3+..... +8+ 9+10 ) x( 6x8-48)

=(1+2+3+.......+8+9+10)x 48-48

=(1+2+3+.........+8+9+10)x0

= 0
^    ^ chúc bạn học tốt k cho mình nha

Bằng 0 nhé

what the hell?

`x^8+36x^4=0`

`<=>x^4(x^4+36)=0`

\(\Leftrightarrow\left[{}\begin{matrix}x^4=0\\x^4+36=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x^4=-36\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=0\\x\in\varnothing\end{matrix}\right.\)

__

`(x-5)^3 -x+5=0`

`<=> (x-5)^3 -(x-5)=0`

`<=> (x-5) [(x-5)^2 -1]=0`

`<=> (x-5)(x-5-1)(x-5+1)=0`

`<=>(x-5)(x-6)(x-4)=0`

\(\Leftrightarrow\left[{}\begin{matrix}x-5=0\\x-6=0\\x-4=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=5\\x=6\\x=4\end{matrix}\right.\)

__

`5(x-2)-x^2+4=0`

`<=>5(x-2)-(x^2-4)=0`

`<=>5(x-2)-(x-2)(x+2)=0`

`<=>(x-2)(5-x-2)=0`

`<=>(x-2)(-x-3)=0`

\(\Leftrightarrow\left[{}\begin{matrix}x-2=0\\-x-3=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=2\\x=-3\end{matrix}\right.\)