\(=\dfrac{2}{7}\cdot\dfrac{3}{2}\cdot8-\dfrac{4}{5}=\dfrac{24}{7}-\dfrac{4}{5}=\dfrac{120-28}{35}=\dfrac{92}{35}\)
=2/7.3/2.8-4/5
=3/7.8-4/5
=24/7-4/5
=120/35-28/35
=82/35
\(\dfrac{2}{7}:\dfrac{2}{3}\times8-\dfrac{4}{5}\\ =\dfrac{3}{7}\times\dfrac{36}{5}\\ =\dfrac{108}{35}\)