\(\dfrac{7}{10}+3:10+\dfrac{2}{5}+1:10\\ =\left(\dfrac{7}{10}+\dfrac{2}{5}\right)+\left(3:10+1:10\right)\\ =\dfrac{11}{10}+\left(3+1\right)\times\dfrac{1}{10}\\ =\dfrac{11}{10}+4\times\dfrac{1}{10}\\ =\dfrac{11}{10}+\dfrac{2}{5}\\ =\dfrac{3}{2}\)

\(\dfrac{7}{10}+3:10+\dfrac{2}{5}+1:10\\ =\dfrac{7}{10}+\dfrac{3}{10}+\dfrac{2}{5}+\dfrac{1}{10}\\ =\left(\dfrac{7}{10}+\dfrac{3}{10}\right)+\left(\dfrac{2}{5}+\dfrac{1}{10}\right)\\ =\dfrac{10}{10}+\left(\dfrac{4}{10}+\dfrac{5}{10}\right)=\dfrac{10}{10}+\dfrac{5}{10}=\dfrac{15}{10}=\dfrac{3}{2}\)

= \(\dfrac{3}{2}\)

(1+10) +(2+9) +....+ (5+6) + (10+1) +(9+2) +........+ (6+5)

= 11 x 10 = 110

Giải

 (1+9)+(2+8)...(6+4)+(7+3)...(9+1)+10+10

10*11=110

         1 + 2 + 3 + ... + 10 + 10 + 9 + 8 + ... + 3 + 2 + 1

Hoặc: 1 + 2 + 3 + ... + 10 + 1 + 2 + 3 + ... + 8 + 9 + 10

      = (1 + 2 + 3 + ... + 10) x 2

      =          (11 x 5)           x 2

      =             55                x 2

      =                     110

Bài 7:

Số phần kẹo Hùng đã cho Hà và Hồng là:

\(\dfrac{2}{7}+\dfrac{1}{7}=\dfrac{3}{7}\left(phần\right)\)

Hùng còn lại số phần của gói kẹo là:

\(\dfrac{6}{7}-\dfrac{3}{7}=\dfrac{3}{7}\left(phần\right)\)

1:

 2 3/4

5 6/5

3 3/9

7 6/8

2:

1/3 + 2/3 + (3/4 + 1/4) = 2

=2

= 4 5/10

1:

\(2+\dfrac{3}{4}=\dfrac{8}{4}+\dfrac{3}{4}=\dfrac{11}{4};5+\dfrac{6}{5}=\dfrac{25}{5}+\dfrac{6}{5}=\dfrac{31}{5};\dfrac{3}{9}+3=\dfrac{1}{3}+\dfrac{9}{3}=\dfrac{10}{3}\)

2: 

a: \(=\left(\dfrac{1}{3}+\dfrac{2}{3}\right)+\left(\dfrac{3}{4}+\dfrac{1}{4}\right)\\ =1+1=2\)

b: \(=\left(\dfrac{3}{4}+\dfrac{2}{8}\right)+\left(\dfrac{3}{5}+\dfrac{4}{10}\right)\\ =\left(\dfrac{6}{8}+\dfrac{2}{8}\right)+\left(\dfrac{6}{10}+\dfrac{4}{10}\right)\\ =1+1=2\)

c:\(=\left(\dfrac{1}{10}+\dfrac{9}{10}\right)+\left(\dfrac{2}{10}+\dfrac{8}{10}\right)+\left(\dfrac{3}{10}+\dfrac{7}{10}\right)+\left(\dfrac{4}{10}+\dfrac{6}{10}\right)+\dfrac{5}{10}\\ =1+1+1+1+\dfrac{5}{10}=4\dfrac{5}{10}\)

Ta có

\(\frac{1}{10}+\frac{2}{10}+\frac{3}{10}+\frac{4}{10}+\frac{5}{10}+\frac{6}{10}+\frac{7}{10}+\frac{8}{10}+\frac{9}{10}\)

\(=\frac{1+2+3+4+5+6+7+8+9}{10}\)

\(=\frac{\left(1+9\right)+\left(2+8\right)+\left(3+7\right)+\left(4+6\right)+5}{10}=\frac{10.4+5}{10}=\frac{45}{10}=\frac{9}{2}\)

Mình cũng làm như Trần Thuỳ Dung và bằng 9/2

mk cũng làm giống Trần Thùy Dung

\(=10^3:5^3+10^4:5^3+125^2:5^3\)

\(=2^3+2^3\times10+125\)

\(=8+80+125\)

\(=88+125\)

\(=213\)

( 10 mũ 3 + 10 mũ 4 + 125 mũ 2 ) : 5 mũ 3

= (1000 + 10000 + 5 mũ 3 .2 ) : 5 mũ 3

= ( 1000 + 10000 + 5 mũ 6 ) ;  5 Mũ 3

= ( 11000 + 15625 ) : 125

= 26625 : 125

=  213

\(a,3456731-19994=3436737\)

\(b,3\times31\times16+2\times24\times42+4\times27\times12\)

\(=\left(3\times16\right)\times31+\left(2\times24\right)\times42+\left(4\times12\right)\times27\)

\(=48\times31+48\times42+48\times27\)

\(=48\times\left(31+42+27\right)\)

\(=48\times100\)

\(=4800\)

\(c,\left(3^{10}+3^{12}\right):3^{10}\)

\(=3^{10}:3^{10}+3^{12}:3^{10}\)

\(=1+3^2\)

\(=1+9\)

\(=10\)

\(d,\left(2^{13}-3.2^{10}\right):2^{10}+\left(5^{10}-5^9\right):5^9\)

\(=2^{13}:2^{10}-3.2^{10}:2^{10}+5^{10}:5^9-5^9:5^9\)

\(=2^3-3+5-1\)

\(=8-3+5-1\)

\(=9\)

Giúp mik với! mik cần gấp trong 5 phút.

\(\text{Ta có: 10/7 x 2/3 + 6/5 : 3/10 - 2/3 x 3/7 = 10/7 x 2/3 + 4 - 2/3 x 3/7 }\)    
\(\text{ = 2/3 x ( 10/7 - 3/7) + 4 }\)   

\(\text{= 2/3 x 1 + 4}\)
\(\text{ = 2/3 + 12/3 }\)                                                      

\(\text{ = 14/3}\)

Ta có:

10/7 x 2/3 + 6/5 : 3/10 - 2/3 x 3/7

= (10/7 - 3/7) x 2/3 + 6/5 : 3/10

= 1 x 2/3 + 4

= 2/3 + 4

= \(4\frac{2}{3}\)

Đáp số: \(4\frac{2}{3}\)

Ta có

10/7 x 2/3 + 6/5 : 3/10 - 2/3 x 3/7

= 2/3 x [ 10/7 - 3/7 ] + 4

= 2/3 x 1 + 4 

= 2/3 + 12/3

= 14/3

Vậy : 10/7 x 2/3 + 6/5 : 3/10 - 2/3 x 3/7 = 14/3