\(6xX=\frac{4}{7}\) \(x:2=\frac{1}{5}\)
Những câu hỏi liên quan
\(2xX+\frac{1}{2xX}+\frac{6xX+1}{6xX}+\frac{12xX+1}{12xX}+\frac{20xX+1}{20xX}=5\)
5 tháng 2 2017 lúc 14:37
1) Giá trị xin Z để frac{x-5}{7-x} là số hữu tỉ dương. x ?
2) Cặp số nguyên dương chẵn x; y thỏa mãn biểu thức frac{x}{2}+frac{3}{7}frac{5}{4}. Vậy x .... ; y ....
3) Giá trị Afrac{frac{2}{5}+frac{2}{7}-frac{2}{11}}{frac{3}{5}+frac{3}{7}-frac{3}{11}}+frac{frac{1}{4}-frac{1}{5}+frac{1}{7}}{frac{3}{4}-frac{3}{5}+frac{3}{4}}
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1) Giá trị \(x\in Z\) để \(\frac{x-5}{7-x}\) là số hữu tỉ dương. x = ?
2) Cặp số nguyên dương chẵn x; y thỏa mãn biểu thức \(\frac{x}{2}+\frac{3}{7}=\frac{5}{4}\). Vậy x = .... ; y = ....
3) Giá trị \(A=\frac{\frac{2}{5}+\frac{2}{7}-\frac{2}{11}}{\frac{3}{5}+\frac{3}{7}-\frac{3}{11}}+\frac{\frac{1}{4}-\frac{1}{5}+\frac{1}{7}}{\frac{3}{4}-\frac{3}{5}+\frac{3}{4}}\)
Bài 3:
\(A=\dfrac{2\left(\dfrac{1}{5}+\dfrac{1}{7}-\dfrac{1}{11}\right)}{3\left(\dfrac{1}{5}+\dfrac{1}{7}-\dfrac{1}{11}\right)}+\dfrac{1\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{4}\right)}{3\left(\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{4}\right)}=\dfrac{2}{3}+\dfrac{1}{3}=1\)
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Tìm số nguyên x
a) \(\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)
b)\(\frac{5}{17}+\frac{-9}{4}+\frac{-26}{31}+\frac{12}{17}+\frac{-11}{31}< \frac{x}{9}\le\frac{-3}{7}+\frac{7}{15}+\frac{4}{-7}+\frac{8}{15}\)
\(a)\frac{1}{3}+\frac{-2}{5}+\frac{1}{6}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{2}{7}+\frac{-1}{4}+\frac{3}{5}+\frac{5}{7}\)
\(\Rightarrow\frac{1}{3}+\frac{1}{6}+\frac{-2}{5}+\frac{-1}{5}\le x< \frac{-3}{4}+\frac{-1}{4}+\frac{2}{7}+\frac{5}{7}+\frac{3}{5}\)
\(\Rightarrow\frac{2}{6}+\frac{1}{6}+\frac{-3}{5}\le x< -1+1+\frac{3}{5}\)
\(\Rightarrow\frac{1}{2}+\frac{-3}{5}\le x< \frac{3}{5}\)
\(\Rightarrow\frac{-1}{10}\le x< \frac{6}{10}\)
\(\Rightarrow-1\le x< 6\)
\(\Rightarrow x\in\left\{-1;0;1;2;3;4;5\right\}\)
Bài b tương tự
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bạn ơi bạn giải câu b được ko. mk ko biết làm câu b
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1, frac{2}{9}.left(x-frac{9}{4}right)+frac{1}{2}frac{3}{7}.left(7-frac{1}{6}right)+frac{1}{3}2, 2.left(frac{3}{2}-xright)-frac{1}{3}7x-frac{1}{4}3,-frac{3}{2}.left(5-frac{1}{6}right)+4.left(x-frac{1}{2}right)frac{1}{2}+x4,-frac{5}{7}.left(frac{2}{5}-xright)-frac{1}{3}frac{1}{5}-frac{3}{10}5,4-frac{2}{3}.left(x-3right)2-frac{1}{2}+frac{2}{3}6,frac{2}{3}-frac{5}{3}.xfrac{7}{10}.x+frac{5}{6}7,3.left(x-frac{5}{3}right)+frac{1}{2}2left(x-frac{1}{4}right)+frac{5}{2}Phần nào có bn giải rầu các men đừng...
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1, \(\frac{2}{9}.\left(x-\frac{9}{4}\right)+\frac{1}{2}=\frac{3}{7}.\left(7-\frac{1}{6}\right)+\frac{1}{3}\)
2, \(2.\left(\frac{3}{2}-x\right)-\frac{1}{3}=7x-\frac{1}{4}\)
3,\(-\frac{3}{2}.\left(5-\frac{1}{6}\right)+4.\left(x-\frac{1}{2}\right)=\frac{1}{2}+x\)
4,\(-\frac{5}{7}.\left(\frac{2}{5}-x\right)-\frac{1}{3}=\frac{1}{5}-\frac{3}{10}\)
5,\(4-\frac{2}{3}.\left(x-3\right)=2-\frac{1}{2}+\frac{2}{3}\)
6,\(\frac{2}{3}-\frac{5}{3}.x=\frac{7}{10}.x+\frac{5}{6}\)
7,\(3.\left(x-\frac{5}{3}\right)+\frac{1}{2}=2\left(x-\frac{1}{4}\right)+\frac{5}{2}\)
Phần nào có bn giải rầu các men đừng giải lại nha mk sẽ ko tk đâu chỉ tik những phần chưa lm
1,\(\frac{2}{9}.\left(x-\frac{9}{4}\right)+\frac{1}{2}=\frac{3}{7}.\left(7-\frac{1}{6}\right)+\frac{1}{3}\)
\(\frac{2}{9}.\left(x-\frac{9}{4}\right)+\frac{1}{2}=\frac{3}{7}.\frac{41}{6}+\frac{1}{3}\)
\(\frac{2}{9}.\left(x-\frac{9}{4}\right)+\frac{1}{2}=\frac{41}{14}+\frac{1}{3}\)
\(\frac{2}{9}.\left(x-\frac{9}{4}\right)+\frac{1}{2}=\frac{137}{42}\)
\(\frac{2}{9}.\left(x-\frac{9}{4}\right)=\frac{137}{42}-\frac{1}{2}\)
\(\frac{2}{9}.\left(x-\frac{9}{4}\right)=\frac{58}{21}\)
\(\left(x-\frac{9}{4}\right)=\frac{5}{2}:\frac{2}{9}\)
\(\left(x-\frac{9}{4}\right)=\frac{45}{4}\)
\(x=\frac{45}{4}+\frac{9}{4}\)
\(x=\frac{27}{2}\)
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Bước cưối 58/21 minh man viết nhầm nên sai
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\(\left(x-\frac{9}{4}\right)=\frac{58}{21}:\frac{2}{9}\)
\(\left(x-\frac{9}{4}\right)=\frac{87}{7}\)
\(x=\frac{87}{7}+\frac{9}{4}\)
\(x=\frac{411}{28}\)
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1)\(\frac{1}{2}x-\frac{3}{5}=-\frac{4}{5}\)
2) \(3\frac{1}{5}-2\frac{1}{3}x=-1\frac{3}{5} +1\frac{7}{10}\)
4)\(x-\frac{2}{3}.(-\frac{3}{7})=-\frac{9}{14}\)
5)\(-2\frac{1}{4}.(x-7\frac{1}{4})=-1,5\)
Lm đc bài nào thì giải giúp mik vs nha.
\(1)\frac{1}{2}x-\frac{3}{5}=\frac{-4}{5}\)
\(\Rightarrow\frac{1}{2}x=\frac{-4}{5}+\frac{3}{5}\)
\(\Rightarrow\frac{1}{2}x=\frac{-1}{5}\)
\(\Rightarrow x=\frac{-1}{5}:\frac{1}{2}=\frac{-1}{5}\cdot\frac{2}{1}=\frac{-2}{5}\)
\(\Leftrightarrow x=\frac{-2}{5}\)
\(2)3\frac{1}{5}-2\frac{1}{3}x=-1\frac{3}{5}+1\frac{7}{10}\)
\(\Rightarrow\frac{16}{5}-\frac{7}{3}x=-\frac{8}{5}+\frac{17}{10}\)
\(\Rightarrow\frac{7}{3}x=\frac{16}{5}-\frac{-8}{5}+\frac{17}{10}\)
\(\Rightarrow\frac{7}{3}x=\frac{16}{5}+\frac{8}{5}+\frac{17}{10}\)
\(\Rightarrow\frac{7}{3}x=\frac{24}{5}+\frac{17}{10}\)
\(\Rightarrow\frac{7}{3}x=\frac{48}{10}+\frac{17}{10}\)
Đến đây tìm được rồi nhé
3,4, áp dụng bài 1,2 rồi làm :v
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1. 1/2x - 3/5 = -4/5
=> 1/2x = -4/5 + 3/5
=> 1/2x = -1/5
=> x = -1/5 : 1/2
=> x = -2/5
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tìm x biết :a) left(x+frac{1}{2}right).left(frac{2}{3}-2xright)0b) left(x.6frac{2}{7}+frac{3}{7}right).2frac{1}{5}-frac{3}{7}-2c) x.3frac{1}{4}+left(-frac{7}{6}right).x-1frac{2}{3}frac{5}{12}d) 5frac{8}{17}:x+left(-frac{4}{17}right):x+3frac{1}{7}:17frac{1}{3}frac{4}{11}e) frac{17}{2}-left|2x-frac{3}{4}right|-frac{7}{4}
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tìm x biết :
a) \(\left(x+\frac{1}{2}\right).\left(\frac{2}{3}-2x\right)=0\)
b) \(\left(x.6\frac{2}{7}+\frac{3}{7}\right).2\frac{1}{5}-\frac{3}{7}=-2\)
c) \(x.3\frac{1}{4}+\left(-\frac{7}{6}\right).x-1\frac{2}{3}=\frac{5}{12}\)
d) \(5\frac{8}{17}:x+\left(-\frac{4}{17}\right):x+3\frac{1}{7}:17\frac{1}{3}=\frac{4}{11}\)
e) \(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)
a) (x + 1/2) . (2/3 − 2x) = 0
\(\Rightarrow\left[\begin{array}{nghiempt}x+\frac{1}{2}=0\\\frac{2}{3}-2x=0\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=-\frac{1}{2}\\2x=\frac{2}{3}\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=-\frac{1}{2}\\x=\frac{1}{3}\end{array}\right.\)
b) \(\left(x.6\frac{2}{7}+\frac{3}{7}\right).2\frac{1}{5}-\frac{3}{7}=-2\)
\(\Rightarrow\left(x.\frac{44}{7}+\frac{3}{7}\right).\frac{11}{5}=-2+\frac{3}{7}\)
\(\Rightarrow\left(x.\frac{44}{7}+\frac{3}{7}\right).\frac{11}{5}=-\frac{11}{7}\)
\(\Rightarrow x.\frac{44}{7}+\frac{3}{7}=-\frac{11}{7}:\frac{11}{5}=-\frac{11}{7}.\frac{5}{11}\)
\(\Rightarrow x.\frac{44}{7}+\frac{3}{7}=-\frac{5}{7}\)
\(\Rightarrow x.\frac{44}{7}=-\frac{5}{7}-\frac{3}{7}\)
\(\Rightarrow x.\frac{44}{7}=-\frac{8}{7}\)
\(\Rightarrow x=-\frac{8}{7}:\frac{44}{7}=-\frac{8}{7}.\frac{7}{44}\)
\(\Rightarrow x=-\frac{2}{11}\)
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c) \(x.3\frac{1}{4}+\left(-\frac{7}{6}\right).x-1\frac{2}{3}=\frac{5}{12}\)
\(\Rightarrow x\left(3\frac{1}{4}-\frac{7}{6}\right)=\frac{5}{12}+\frac{5}{3}\)
\(\Rightarrow x\left(\frac{13}{4}-\frac{7}{6}\right)=\frac{25}{12}\)
\(\Rightarrow x.\frac{25}{12}=\frac{25}{12}\)
\(\Rightarrow x=\frac{25}{12}:\frac{25}{12}\)
\(\Rightarrow x=1\)
d) \(5\frac{8}{17}:x+\left(-\frac{4}{17}\right):x+3\frac{1}{7}:17\frac{1}{3}=\frac{4}{11}\)
\(\Rightarrow\left(5\frac{8}{17}-\frac{4}{17}\right):x+\frac{22}{7}:\frac{52}{3}=\frac{4}{11}\)
\(\Rightarrow5\frac{4}{17}:x+\frac{33}{182}=\frac{4}{11}\)
\(\Rightarrow\frac{89}{17}:x=\frac{4}{11}-\frac{33}{182}\)
\(\Rightarrow\frac{89}{17}:x=\frac{365}{2002}\)
\(\Rightarrow x=\frac{89}{17}:\frac{365}{2002}\)
\(\Rightarrow x\approx28,7\) (số hơi lẻ)
e) \(\frac{17}{2}-\left|2x-\frac{3}{4}\right|=-\frac{7}{4}\)
\(\Rightarrow\left|2x-\frac{3}{4}\right|=\frac{17}{2}+\frac{7}{4}\)
\(\Rightarrow\left|2x-\frac{3}{4}\right|=\frac{41}{4}\)
\(\Rightarrow\left[\begin{array}{nghiempt}2x-\frac{3}{4}=\frac{41}{4}\\2x-\frac{3}{4}=-\frac{41}{4}\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}2x=11\\2x=-\frac{19}{2}\end{array}\right.\)
\(\Rightarrow\left[\begin{array}{nghiempt}x=\frac{11}{2}\\x=-\frac{19}{4}\end{array}\right.\)
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Phạm Tuấn Kiệt câu a sao nhìn không đc vậy ???
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tìm x, x\(\in\)Q:
a) \(\frac{\left(x+\frac{3}{4}\right).\frac{7}{2}-\frac{1}{6}}{-\left(\frac{4}{5}+\frac{1}{3}\right).\frac{1}{2}+1}=2\frac{33}{52}\)
b) \(\frac{\left(5-\frac{2}{7}\right).\frac{7}{9}:\frac{3}{5}}{\left(3x-\frac{5}{6}\right):\frac{1}{7}}=5\frac{5}{21}\)
câu 1:thực hiện phép tính (tính nhanh nếu có thể): a, frac{-7}{25}.frac{11}{13}+frac{-7}{25}.frac{2}{13}-frac{18}{25}b,frac{5}{7}.frac{1}{3}-frac{5}{7}.frac{1}{4}-frac{5}{7}.frac{1}{12}c,5frac{2}{5}.4frac{2}{7}+5frac{5}{7}.5frac{2}{5}d,75%-1frac{1}{2}+0,5:frac{5}{12}-left(frac{-1}{2}right)^2câu 2:tìm x biết:a, x+frac{1}{6}frac{-3}{8}b, frac{1}{2}x+frac{1}{8}xfrac{3}{4}c,2-left|frac{3}{4}-xright|frac{7}{12}d,left(2x-4,5right):frac{3}{4}-frac{1}{3}1GIÚP MIK VS MAI MIK PHẢI NỘP BÀI RỒI!
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câu 1:thực hiện phép tính (tính nhanh nếu có thể):
a, \(\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)
b,\(\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{12}\)
c,\(5\frac{2}{5}.4\frac{2}{7}+5\frac{5}{7}.5\frac{2}{5}\)
d,\(75\%-1\frac{1}{2}+0,5:\frac{5}{12}-\left(\frac{-1}{2}\right)^2\)
câu 2:tìm x biết:
a, \(x+\frac{1}{6}=\frac{-3}{8}\)
b, \(\frac{1}{2}x+\frac{1}{8}x=\frac{3}{4}\)
c,\(2-\left|\frac{3}{4}-x\right|=\frac{7}{12}\)
d,\(\left(2x-4,5\right):\frac{3}{4}-\frac{1}{3}=1\)
GIÚP MIK VS MAI MIK PHẢI NỘP BÀI RỒI!
CACS BN GIÚP MIK TRẢ LỜI TRONG TỐI NAY ĐC K
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Xem thêm câu trả lời
1.|x|frac{2}{3} 14.|x+3|frac{4}{5} 2.|x|frac{3}{5} 15.|x-7|frac{-5}{3}3.|x|frac{7}{4} 16.|x-7|frac{5}{3} 4.|x|-frac{-4}{7} 17.|x-frac{1}{2}|frac{1}{2}5.|x||frac{-3}{2}| 18.|x-frac{3}{2}|1frac{1}{3}6.|x|-frac{5}{-2} 19.|x-frac{5}{4}|-frac{1}{3}7.|x|5frac{1}{2} 20.|x+2|frac{1}{3}-frac{1}{5} 8.|x|frac{1}{5}-frac{1}{4} 21.|x-4|frac{1}{5}-left(frac{1}{2}-frac{5}{4}right)9.|x|-|frac{-4}{5}| 22.|x+3|frac{4}{5}-1frac{1}{2}+frac{7}{3}10.|x+1|fra...
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\(1.|x|=\frac{2}{3}\) \(14.|x+3|=\frac{4}{5}\)
\(2.|x|=\frac{3}{5}\) \(15.|x-7|=\frac{-5}{3}\)
\(3.|x|=\frac{7}{4}\) \(16.|x-7|=\frac{5}{3}\)
\(4.|x|=-\frac{-4}{7}\) \(17.|x-\frac{1}{2}|=\frac{1}{2}\)
\(5.|x|=|\frac{-3}{2}|\) \(18.|x-\frac{3}{2}|=1\frac{1}{3}\)
\(6.|x|=-\frac{5}{-2}\) \(19.|x-\frac{5}{4}|=-\frac{1}{3}\)
\(7.|x|=5\frac{1}{2}\) \(20.|x+2|=\frac{1}{3}-\frac{1}{5}\)
\(8.|x|=\frac{1}{5}-\frac{1}{4}\) \(21.|x-4|=\frac{1}{5}-\left(\frac{1}{2}-\frac{5}{4}\right)\)
\(9.|x|=-|\frac{-4}{5}|\) \(22.|x+3|=\frac{4}{5}-1\frac{1}{2}+\frac{7}{3}\)
\(10.|x+1|=\frac{1}{4}\)
\(11.|x-1|=\frac{2}{3}\)
\(12.|x+2|=\frac{1}{12}\)
\(13.|x-4|=\frac{1}{2}\)