Tìm x biết
X^3 + 4x^2 +5x
Tìm x biết a) (x^2-4x+5)_(x^2-2x+1)=3 lớp 7
b)(4x^3-5X^2+3x-1)+(3-5x+5x^2-4x^3)=2
c)(3x-2)-(5x+4)=(x-3)-(X+5)
a, \(-4x+5+2x-1=3\Leftrightarrow-2x=-1\Leftrightarrow x=\dfrac{1}{2}\)
b, \(-2x+2=2\Leftrightarrow x=0\)
c, \(-2x-6=-8\Leftrightarrow x=1\)
Tìm x, biết:
A) (x -1)^3+(2-x)(4+2x+x^2)+3x(x+2)=17
B) (x+2)(x^2-2x+4)-x(x^2-2)=15
C) (5x-2)(5x+2)-(5x+3)(5x-4)=8
D) (4x-3)(4x+2)+(4x+5)(1-4x)=2.5^2
Tìm x biết :
5x-3{4x-2[4x-3(5x-2)]}=182
5x-3{4x-2[4x-3(5x-2)]}
= 5x - 3.[4x - 2(4x - 15x + 6)]
= 5x - 3.(4x - 8x + 30x - 12)
= 5x - 12x + 24x - 90x + 36
= -73x + 36 = 182
=> -73x = 182 - 36 = 146
=> x = 146 : (-73) = -2
\(VT=-\left(73x-36\right)\)
\(\Leftrightarrow-\left(73x-36\right)=182\)
\(\Leftrightarrow36-73x=182\)
\(\Leftrightarrow-73x=182-36\)
\(\Leftrightarrow-73x=146\)
\(\Leftrightarrow x=-2\)
5x -3 { 4x - 2 [ 4x - 3 (5x - 2)]} = 182
<=> 5x -3 { 4x -2 [ 4x - 15x +6 ]} =182
<=> 5x -3 { 4x -2 [ -11x +6 ]} =182
<=> 5x -3 { 4x + 22x -12 } = 182
<=> 5x -3 { 26x -12 } =182
<=> 5x - 78x + 36 = 182
<=> -73x = 146
<=> x= -2
Tìm x biết :
5x-3{4x-2[4x-3(5x-2)]}=182
Mình nghĩ là vậy :
5x -3 { 4x - 2 [ 4x - 3 (5x - 2)]} = 182
<=> 5x -3 { 4x -2 [ 4x - 15x +6 ]} =182
<=> 5x -3 { 4x -2 [ -11x +6 ]} =182
<=> 5x -3 { 4x + 22x -12 } = 182
<=> 5x -3 { 26x -12 } =182
<=> 5x - 78x + 36 = 182
<=> -73x = 146
<=> x= -2
\(VT=-\left(73x-36\right)\)
\(\Leftrightarrow-\left(73x-36\right)=182\)
\(\Leftrightarrow36-73x=182\)
\(\Leftrightarrow-73x=182-36\)
\(\Leftrightarrow-73x=146\)
\(\Leftrightarrow x=-2\)
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TÌM X biết:
a. (5x - 2)(5x + 2) - (5x + 3)(5x - 4) = 8
b. (4x - 3)( 4x + 2) + (4x + 5)(1 - 4x) =2.52
a) \(\left(5x-2\right)\left(5x+2\right)-\left(5x+3\right)\left(5x-4\right)=0\)
\(\Leftrightarrow5x+8=8\)
\(\Leftrightarrow5x=8-8\)
\(\Leftrightarrow x=5.0\)
\(\Leftrightarrow x=0\)
b)
\(\left(4x-3\right)\left(4x+2\right)+\left(4x+5\right)\left(1-4x\right)=2.5^2\)
\(16x^2+8x-12x-6+4x-16x^2+5-20x=50\)
\(-20x-1=50\)
\(-20x=51\)
\(x=\frac{-51}{20}\)
Vậy \(x=\frac{-51}{20}\)
tìm x biết
5x-3(4x-2(4x-3(5x-2)))=182
b) 5x -3 {4x-2 [4x-3.(5x-2)]} =182 <=> 5x - (12x -6 [4x-15x+6])=182
<=> 5x - (12x-24x+90x-36)=182 <=> 5x-12x+24x-90x+36 =182
-73x = 146 => x= -2
tìm x biết :
a) 2 . |5x-3| - 2x = 14
b) |3x-2| - x = 7
c) |4x+3| - x = 15
d) |3x-2| + 5x = 4x -10
e) |3x-2| + 5x = 4x-10
f) |2x-6| + 5x = 9
g) |5x-3| - x = 7
a) \(2.\left|5x-3\right|-2x=14\)
\(2\left|5x-3\right|=14+2x\)
\(\left|5x-3\right|=\frac{14+2x}{2}\)
\(\Rightarrow\orbr{\begin{cases}5x-3=\frac{-14-2x}{2}\\5x-3=\frac{14+2x}{2}\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}\left(5x-3\right).2=-14-2x\\\left(5x-3\right).2=14+2x\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}10x-6+2x=-14\\10x-6-2x=14\end{cases}\Rightarrow\orbr{\begin{cases}12x=-14+6\\8x=14+6\end{cases}}}\Rightarrow\orbr{\begin{cases}12x=-8\\8x=20\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{-2}{3}\\x=2,5\end{cases}}\)
vậy \(\orbr{\begin{cases}x=\frac{-2}{3}\\x=2,5\end{cases}}\)
Những câu sau tương tự nhé.
Tìm x, biết:
5 x - 3 4 x - 2 [ 4 x - 3 ( 5 x - 2 ) ] = 182 .
Thực hiện phá ngoặc lần lượt và rút gọn VT = -73x + 36.
Giải phương trình -73x + 36 = 182 thu được x = -2.
Tìm x , biết
5x-3{4x-2[4x-3(5x-2]}=182
5x - 3{4x - 2[4x - 3(5x - 2)]} = 5x - {12x - 6[4x - (15x - 6)]} = 5x - 12x + 6(6 - 11x) = 36 + 66x - 7x = 36 + 59x = 182
=> 59x = 182 - 36 = 146 => x = 146/59
Tìm x, biết
a) 5x-3{4x-2[4x-3(5x-2)]}=182
b)(x2+2x+4).(2-x)+x.(x-3).(x+4)-x2+24=0
#)Giải :
a)\(5x-3\left\{4x-2\left[4x-3\left(5x-2\right)\right]\right\}\)
\(\Leftrightarrow5x-3\left[4x-2\left(4x-15x+6\right)\right]\)
\(\Leftrightarrow5x-3\left(4x-8x+30x-12\right)\)
\(\Leftrightarrow5x-12x+24x-90x+36\)
\(\Leftrightarrow-73x+36=182\)
\(\Leftrightarrow-73x=146\)
\(\Leftrightarrow x=-2\)