\(x^5-x^3+x^2-1=x^3\left(x^2-1\right)+\left(x^2-1\right)=\left(x^2-1\right)\left(x^3+1\right)=\left(x-1\right)\left(x+1\right)^2\left(x^2-x+1\right)\)

bài này cần có đkxđ 

a, 2x3x4x8x25x125= (2x3)x(4x25)x(8x125)= 6x100x1000=600000

b,42/5 +56/9+23/4+3/5+1/3+1/4= (42/5+3/5)+(23/4+1/4)+(56/9+1/3)=9+6+59/9=

a)  2 x 3 x 4 x 8 x 25 x 125=600000

b) 4 2/5 + 5 6/9 + 2 3/4 + 3/5 + 1/3 + 1/4=14

a)  2 x 3 x 4 x 8 x 25 x 125

=(2x3)x(4x25)x(8x125)

=6x100x1000

=600000

b) 4 2/5 + 5 6/9 + 2 3/4 + 3/5 + 1/3 + 1/4

(4+\(\frac{2}{5}\)+\(\frac{3}{5}\))+(5+\(\frac{6}{9}\)+1/3)+(2+\(\frac{3}{4}\)+\(\frac{1}{4}\))

=(4+1)+(5+1)+(2+1)

=5+6+3

=14

a: =>1/3*4+1/4*5+...+1/x(x+1)=10/39

=>1/3-1/4+...+1/x-1/x+1=10/39

=>1/3-1/(x+1)=10/39

=>1/(x+1)=13/39-10/39=3/39=1/13

=>x+1=13

=>x=12

b: =>15x=150

=>x=10

c: =>120-5x=45

=>5x=75

=>x=15

nè

a: Ta có: ⇔x⋅14=134.4⇔x⋅14=134.4

hay x=537,6

b: Ta có: ⇔x:35=13⇔x:35=13

hay 

à quên ở đây ko viết phân số đc đừng viết nha

a/\(0,25.x:3=\dfrac{5}{6}=>0,25.x=\dfrac{5}{6}.3=2,5\)

\(=>x=2,5:0,25=10\)

b/\(\dfrac{-2}{5}.x=\left(\dfrac{-2}{5}\right)^3=>\dfrac{-2}{5}.x=\dfrac{-8}{125}\)

=>x=\(\dfrac{-8}{125}:\left(\dfrac{-2}{5}\right)\)=\(\dfrac{4}{25}\)

`@` `\text {Ans}`

`\downarrow`

\(\left(1-\dfrac{1}{2}\right)\times\left(1-\dfrac{1}{3}\right)\times\left(1-\dfrac{1}{4}\right)\times\left(1-\dfrac{1}{5}\right)...\left(1-\dfrac{1}{1000}\right)\)

`=`\(\left(\dfrac{2}{2}-\dfrac{1}{2}\right)\times\left(\dfrac{3}{3}-\dfrac{1}{3}\right)\times\left(\dfrac{4}{4}-\dfrac{1}{4}\right)...\left(\dfrac{1000}{1000}-\dfrac{1}{1000}\right)\)

`=`\(\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times...\times\dfrac{999}{1000}\)

`=`\(\dfrac{1}{1000}\)

\(=\dfrac{1}{2}.\dfrac{2}{3}.\dfrac{3}{4}.\dfrac{4}{5}.......\dfrac{99}{100}=\dfrac{1}{100}\)

phần 100 mà sao lại 1000,các bạn cố gắng giúp mình với nhé,mình cần gấp !

tính như bth thôi ráng lên bạn nhá

99/32

\(y x 4/9 - 5/8 = 1/2 : 2/3\)

\(y x 4/9 - 5/8 = 3/4\)

\(y x 4/9 = 3/4 + 5/8\)

\(y x 4/9 = 11/8\)

\(y = 11/8 : 4/9\)

\(y = 99/32\)

\(\hept{\begin{cases}\frac{x}{2}=\frac{y}{3}\\\frac{y}{4}=\frac{z}{5}\end{cases}}\)\(\Rightarrow\hept{\begin{cases}\frac{x}{8}=\frac{y}{12}\\\frac{y}{12}=\frac{z}{15}\end{cases}}\)\(\Rightarrow\frac{x}{8}=\frac{y}{12}=\frac{z}{15}\)

\(\Rightarrow\frac{x^2}{64}=\frac{y^2}{144}=\frac{z^2}{225}=\frac{x^2-y^2}{64-144}=\frac{-16}{-80}=\frac{1}{5}\)

\(\Rightarrow\hept{\begin{cases}x^2=\frac{1}{5}.64=12,8\\y^2=\frac{1}{5}.144=28,8\\z^2=\frac{1}{5}.225=45\end{cases}}\)\(\Rightarrow\hept{\begin{cases}x=\pm\sqrt{12,8}\\y=\pm\sqrt{28,8}\\z=\pm\sqrt{45}\end{cases}}\)

Với \(x=\sqrt{12,8}\Rightarrow\hept{\begin{cases}y=\sqrt{28,8}\\z=\sqrt{45}\end{cases}}\)

Với \(x=-\sqrt{12,8}\Rightarrow\hept{\begin{cases}y=-\sqrt{28,8}\\z=-\sqrt{45}\end{cases}}\)