a) -2 (x+6)+6 (x-10)=8

-2.x + (-2).6 + 6.x - 6.10 = 8

-2x + (-12) + 6x - 60 = 8

-2x + 6x + [60 + (-12)] = 8

4x + 48 = 8

4x = 8 - 48

4x = -40

x = -40 : 4

x = -10

vậy_____

b) ( x-12)-15=(20-7) - (18-x)

x - 12 - 15 = 13 - 18 + x

x - 27 = -5 + x

x - x = -5 + 27

0x = 22

x = 22 : 0

=> x ∈ ∅

c)2(5+3x)+x=31

2.5 + 2.3x + x = 31

10 + 6x + x = 31

6x + x = 31 - 10

7x = 21

x = 21 : 7

x = 3

vậy_____

d) -x (x+7) ( x-4) =0

=> -x = 0 hoặc x+ 7 = 0 hoặc x - 4 = 0

=> x = 0 hoặc x = 0 - 7 hoặc x = 0 + 4

=> x = 0 hoặc x = -7 hoặc x = 4

vậy_____

e) x-96 = (443 - x) - 15

x - 96 = 443 - x - 15

x - 96 = (443 - 15) - x

x - 96 = 428 - x

x + x = 428 + 96

2x  = 524

x = 524 : 2

x = 262

vậy_____

tham khảo nek: https://olm.vn/hoi-dap/detail/9664557962.html

a) x - 96 = (433 - x) - 15

x - 96 = 433 - x - 15

2x = 433 - 15 + 96

2x = 514

x = 257

b) 7x (-x-10) = 0

\(\Leftrightarrow\orbr{\begin{cases}7x=0\\-x-10=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=-10\end{cases}}\)

c) 17 (3x - 6) (2x - 8) = 0

(3x - 6) (2x - 8) = 0

\(\Leftrightarrow\orbr{\begin{cases}3x-6=0\\2x-8=0\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}3x=6\\2x=8\end{cases}}\)\(\Leftrightarrow\orbr{\begin{cases}x=2\\x=4\end{cases}}\)

a, x - 96 = (443 - x) - 15

<=>x - 96 = 443 - x - 15

<=>x + x = 443 - 15 + 96

<=>2x = 524

<=>x = 524 : 2

<=>x = 262

b, (x - 12) - 15 = (20 - 7) - (18 + x)

<=>x - 12 - 15 = 20 - 7 - 18 - x

<=>x + x = 20 - 7 - 18 + 12 + 15

<=>2x = 22

<=> x = 22 : 2

<=> x = 11  

a) x - 96 = (443 - x) - 15

x - 96 = 443 - x - 15

x + x = 443 -15 + 96

2x = 524

x = 524 : 2

x = 262

b) (x  -12) - 15 = (20 - 7) - (18 + x)

x - 12 - 15 = 20 - 7 - 18 - x

x + x = 20 - 7 - 18 + 12 + 15

2x = 22

x = 22 : 2

x = 11

c) 311 - x + 82 = 46 + (x - 21)

311 - x + 82 = 46 + x - 21

-x - x = 46 - 21 - 311 - 81

-2x = -367

x = -367 : (-2)

x = 183,5

d) -(x - 3 + 85) = (x + 70 - 71) - 5

-x + 3 - 85 = x + 70 - 71 - 5

-x - x = 70 - 71 - 5 - 3 + 85

-2x = 76

x = 76 : (-2)

x = -38

e,f làm tương tự

a) x - 96 = (443 - x) - 15

x - 96 = 443 - x - 15

x + x = 443 -15 + 96

2x = 524

x = 524 : 2

x = 262

b) (x  -12) - 15 = (20 - 7) - (18 + x)

x - 12 - 15 = 20 - 7 - 18 - x

x + x = 20 - 7 - 18 + 12 + 15

2x = 22

x = 22 : 2

x = 11

c) 311 - x + 82 = 46 + (x - 21)

311 - x + 82 = 46 + x - 21

-x - x = 46 - 21 - 311 - 81

-2x = -367

x = -367 : (-2)

x = 183,5

d) -(x - 3 + 85) = (x + 70 - 71) - 5

-x + 3 - 85 = x + 70 - 71 - 5

-x - x = 70 - 71 - 5 - 3 + 85

-2x = 76

x = 76 : (-2)

x = -38

e,f làm tương tự

a) x - 96 = (443 - x) - 15

x - 96 = 443 - x - 15

x + x = 443 -15 + 96

2x = 524

x = 524 : 2

x = 262

b) (x  -12) - 15 = (20 - 7) - (18 + x)

x - 12 - 15 = 20 - 7 - 18 - x

x + x = 20 - 7 - 18 + 12 + 15

2x = 22

x = 22 : 2

x = 11

c) 311 - x + 82 = 46 + (x - 21)

311 - x + 82 = 46 + x - 21

-x - x = 46 - 21 - 311 - 81

-2x = -367

x = -367 : (-2)

x = 183,5

d) -(x - 3 + 85) = (x + 70 - 71) - 5

-x + 3 - 85 = x + 70 - 71 - 5

-x - x = 70 - 71 - 5 - 3 + 85

-2x = 76

x = 76 : (-2)

x = -38

e,f làm tương tự

caau 1 5.(3x-21)=0

3x-21=0

3x=21

x=7

câu2 x-90=443-x-15

x+x=443+90-15

2x=524

x=262

câu3 (3-x).(x+4)=0

=> 3- x=0 hoặc x+4=0=>x=4

x=3

1: Sửa đề: 3x-5

\(=\dfrac{-x^2\left(3x-5\right)-3\left(3x-5\right)}{3x-5}=-x^2-3\)

2: \(=\dfrac{5x^4-5x^3+14x^3-14x^2+12x^2-12x+8x-8}{x-1}\)

=5x^2+14x^2+12x+8

3: \(=\dfrac{5x^3+10x^2+4x^2+8x+4x+8}{x+2}=5x^2+4x+4\)

4: \(=\dfrac{\left(x^2-1\right)\left(x^2+1\right)-2x\left(x^2-1\right)}{x^2-1}=x^2+1-2x\)

5: \(=\dfrac{x^2\left(5-3x\right)+3\left(5-3x\right)}{5-3x}=x^2+3\)

\(\dfrac{11}{8}:x-\dfrac{2}{5}+-\dfrac{1}{6}=-\dfrac{1}{5}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{5}-\left(-\dfrac{1}{6}\right)\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{5}+\dfrac{1}{6}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{6}{30}+\dfrac{5}{30}\\ =>\dfrac{11}{8}:x-\dfrac{2}{5}=-\dfrac{1}{30}\\ =>\dfrac{11}{8}:x=-\dfrac{1}{30}+\dfrac{2}{5}\\ =>\dfrac{11}{8}:x=-\dfrac{1}{30}+\dfrac{12}{30}\\ =>\dfrac{11}{8}:x=\dfrac{11}{30}\\ =>x=\dfrac{11}{8}:\dfrac{11}{30}\\ =>x=\dfrac{11}{8}.\dfrac{30}{11}\\ =>x=\dfrac{30}{8}\\ =>x=\dfrac{15}{4}\\ \dfrac{4}{7}x-\dfrac{1}{3}x+\left(-\dfrac{16}{21}\right)=-\dfrac{2}{3}\\ =>\left(\dfrac{4}{7}-\dfrac{1}{3}\right)x=-\dfrac{2}{3}-\left(-\dfrac{16}{21}\right)\\ =>\left(\dfrac{12}{21}-\dfrac{7}{21}\right)x=-\dfrac{2}{3}+\dfrac{16}{21}\\ =>\dfrac{5}{21}x=-\dfrac{14}{21}+\dfrac{16}{21}\\ =>\dfrac{5}{21}x=\dfrac{2}{21}\\ =>x=\dfrac{2}{21}:\dfrac{5}{21}\)

\(=>x=\dfrac{2}{21}.\dfrac{21}{5}\\ =>x=\dfrac{2}{5}\\ -\dfrac{11}{12}x+\dfrac{15}{2}\left(x+-\dfrac{1}{5}\right)=\dfrac{67}{8}\\ =>-\dfrac{11}{12}x+\dfrac{15}{2}.x-\dfrac{1}{5}=\dfrac{67}{8}\\ =>\left(-\dfrac{11}{12}+\dfrac{15}{2}\right)x=\dfrac{67}{8}+\dfrac{1}{5}\\ =>\left(-\dfrac{11}{12}+\dfrac{90}{12}\right)x=\dfrac{335}{40}+\dfrac{8}{40}\\ =>\dfrac{79}{12}x=\dfrac{343}{40}\\ =>x=\dfrac{343}{40}:\dfrac{79}{12}\\ =>x=\dfrac{343}{40}.\dfrac{12}{79}\\ =>x=\dfrac{343.12}{40.79}\\ =>x=\dfrac{343.3}{10.79}\\ =>x=\dfrac{1029}{790}\)

Giải pt :

a) \(2x\left(x+5\right)-\left(x-3\right)^2=x^2+6\)

\(\Leftrightarrow2x^2+10x-x^2+6x-9-x^2-6=0\)

\(\Leftrightarrow16x-15=0\)

\(\Leftrightarrow x=\frac{15}{16}\)

b) \(6\left(x-3\right)+\left(x-1\right)^2-\left(x+1\right)^2=2x\)

\(\Leftrightarrow2x-18=2x\)

\(\Leftrightarrow-18=0\)( vô lí )

=> x thuộc rỗng

c)d) tương tự

e) \(\frac{5x-2}{6}+\frac{3-4x}{2}=2-\frac{x+7}{3}\)

\(\Leftrightarrow\frac{5x-2}{6}+\frac{9-12x}{6}=\frac{12}{6}-\frac{2x+14}{6}\)

\(\Leftrightarrow5x-2+9-12x=12-2x-14\)

\(\Leftrightarrow-5x+9=0\)

\(\Leftrightarrow x=\frac{9}{5}\)

f) \(\frac{2x-1}{2}=\frac{2x+1}{4}-\frac{1-2x}{8}\)

\(\Leftrightarrow\frac{4\left(2x-1\right)}{8}=\frac{2\left(2x+1\right)}{8}-\frac{1-2x}{8}\)

\(\Leftrightarrow8x-4=4x+2-1+2x\)

\(\Leftrightarrow2x-5=0\)

\(\Leftrightarrow x=\frac{5}{2}\)

Tìm x :

a) \(3x^3-27x=0\)

\(\Leftrightarrow3x\left(x^2-9\right)=0\)

\(\Leftrightarrow3x\left(x-3\right)\left(x+3\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}3x=0\\x-3=0\\x+3=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=0\\x=3\\x=-3\end{matrix}\right.\)

b) \(2x^3-12x^2+18x=0\)

\(\Leftrightarrow2x\left(x^2-6x+9\right)=0\)

\(\Leftrightarrow2x\left(x-3\right)^2=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=3\end{matrix}\right.\)