a) \(3x-10=2x+13\Leftrightarrow x=13+10=23\)

b) \(x+12=-5-x\Leftrightarrow2x=-17\Leftrightarrow x=-\frac{17}{2}\)

c) \(x+5=10-x\Leftrightarrow2x=5\Leftrightarrow x=\frac{5}{2}\)

d) \(6x+23=2x-12\Leftrightarrow4x=-35\Leftrightarrow x=-\frac{35}{4}\)

e) \(12-x=x+1\Leftrightarrow2x=11\Leftrightarrow x=\frac{11}{2}\)

f) \(14+4x=3x+20\Leftrightarrow x=20-14=6\)

g) \(2\left(x-1\right)+3\left(x-2\right)=x-4\Leftrightarrow2x-2+3x-6=x-4\)

\(\Leftrightarrow5x-8=x-4\Leftrightarrow4x=4\Leftrightarrow x=1\)

h ) \(3\left(4-x\right)-2\left(x-1\right)=x+20\Leftrightarrow12-3x-2x+2=x+20\)

\(\Leftrightarrow14-5x=x+20\Leftrightarrow6x=-6\Leftrightarrow x=-1\)

i ) \(4\left(2x+7\right)-3\left(3x-2\right)=24\Leftrightarrow8x+28-9x+6=24\)

\(\Leftrightarrow34-x=24\Leftrightarrow x=34-24=10\)

k) \(3\left(x-2\right)+2x=10\Leftrightarrow3x-6+2x=5x-6=10\)

\(\Leftrightarrow5x=10+6=16\Leftrightarrow x=\frac{16}{5}\)

Tự KL cho các phần

a. 3x-10=2x+13

    3x-2x=13+10

            x=23

a) \(3x-10=2x+13\)

\(\Leftrightarrow3x-2x=13+10\)

\(\Leftrightarrow x=23\)

b) \(x+12=-5-x\)

\(\Leftrightarrow x+x=-5-12\)

\(\Leftrightarrow2x=-17\)

\(\Leftrightarrow x=-\frac{17}{2}\)

c) \(x+5=10-x\)

\(\Leftrightarrow x+x=10-5\)

\(\Leftrightarrow2x=5\)

\(\Leftrightarrow x=\frac{5}{2}\)

d) \(6x+2^3=2x-12\)

\(\Leftrightarrow6x+8=2x-12\)

\(\Leftrightarrow6x-2x=-12-8\)

\(\Leftrightarrow4x=-20\)

\(\Leftrightarrow x=-5\)

e) \(12-x=x+1\)

\(\Leftrightarrow-x-x=1-12\)

\(\Leftrightarrow-2x=-11\)

\(\Leftrightarrow x=\frac{11}{2}\)

g) \(2\left(x-1\right)+3\left(x-2\right)=x-4\)

\(\Leftrightarrow2x-2+3x-6=x-4\)

\(\Leftrightarrow2x+3x-x=-4+6+2\)

\(\Leftrightarrow4x=4\)

\(\Leftrightarrow x=1\)

h) \(14+4x=3x+20\)

\(\Leftrightarrow4x-3x=20-14\)

\(\Leftrightarrow x=6\)

i) \(4\left(2x+7\right)-3\left(3x-2\right)=24\)

\(\Leftrightarrow8x+28-9x+6=24\)

\(\Leftrightarrow8x-9x=24-6-28\)

\(\Leftrightarrow-x=-10\)

\(\Leftrightarrow x=10\)

k) \(3\left(4-x\right)-2\left(x-1\right)=x+20\)

\(\Leftrightarrow12-3x-2x+2=x+20\)

\(\Leftrightarrow-3x-2x-x=20-2-12\)

\(\Leftrightarrow-6x=6\)

\(x=-1\)

l) \(3\left(x-2\right)+2x=10\)

\(\Leftrightarrow3x-6+2x=10\)

\(\Leftrightarrow3x+2x=10+6\)

\(\Leftrightarrow5x=16\)

\(\Leftrightarrow x=\frac{16}{5}\)

Lần sau bạn chỉ nên đăng ít câu hỏi một thôi nhé, đăng nnay các bạn làm không xuể đâu

x + 12 =(-5)-x

x + x = -5 - 12

2x = -17

  \(x=-\frac{17}{2}\)  

x +  5 = 10 - x

x + x = 10 - 5

2x = 5

  \(x=\frac{5}{2}\)

12-x=x+1

12 - 1 = x+x

11=2x

x=\(\frac{11}{2}\)

14+4x=3x-20

4x-3x=-20-14

       x=-34

5x-16=40+x

=> 5x-16-x = 40

=> 5x-x -16=40

4x-16=40

4x= 40+16

4x=56

x= 56:4

x=14

Vậy...

4x-10=15-x

=> 4x-10+x= 15

4x+x -10=15

5x= 15+10

5x= 25

x= 25:5

x=5

Vậy....

5x -16=40+x

=> 5x-x=40+16

=>4x=56

=>x=56:4

x=14

a) x+3=12

x=12-3

x=9

b)(x-3):2=5¹⁴:5¹²

=>(x-3):2=5²

=>(x-3):2=25

=>x-3=25.2

=>x-3=50

=>x=50+3

=>x=53

c)4x+3x=30-20:10

=>x(4+3)=30-2

=>7x=28

=>x=28:7

=>x=4

d)2x-138=2³.3²

=>2x-138=8.9

=>2x-138=72

=>2x=72+138

=>2x=210

=>x=210:2

=>x=105

a) x + 3 = 12

x = 12 - 3

x = 9

b) ( x - 3 ) : 2 = 5¹⁴ : 5¹²

( x - 3 ) : 2 = 5^14-12

( x - 3 ) : 2 = 5²

( x - 3 ) : 2 = 25

x - 3 = 50

x = 53

c) 4x + 3x = 30 - 20 : 10

7x = 28

x = 4

d) 2x - 138 = 2³ x 3²

2x - 138 = 8 x 9

2x - 138 = 72

2x = 210

x = 105

a: \(\left(2x-3\right)\left(3x^2+1\right)-6x\left(x^2-x+1\right)+3x^2-2x=10\)

\(\Leftrightarrow6x^3+2x-9x^2-3-6x^3+6x^2-6x+3x^2-2x=10\)

\(\Leftrightarrow-6x-3=10\)

=>-6x=13

hay x=-13/6

b: \(\Leftrightarrow3x^2-3x+x-2-3x^2+5x=-8-5x\)

=>3x-2=-5x-8

=>8x=-6

hay x=-3/4

c: \(\Leftrightarrow64x^3-27-64x^3+32x^2-32x^2+x=20\)

=>x-27=20

hay x=47

a) \(\Rightarrow72-20x-36x+84=30x-240-6x-84\)

\(\Rightarrow80x=480\Rightarrow x=6\)

b) \(\Rightarrow15x+25-8x+12=5x+6x+36+1\)

\(\Rightarrow4x=0\Rightarrow x=0\)

c) \(\Rightarrow10x-16-12x+15=12x-16+11\)

\(\Rightarrow14x=4\Rightarrow x=\dfrac{2}{7}\)

Đề hơi khó hiểu nhưng vẫn biết cách làm !!!

Bài giải 

a) +)Ta có :  4x - 7 =   12x +5

=> 4x - 12x = 5 + 7 

<=> -8x     = 12

<=> x =\(\frac{-12}{8}=\frac{-3}{2}\)

+)Ta có :  2x -1 = 6x + 5 

<=> 2x - 6x      = 5 + 1 

<=>  -4x            = 6

<=> x = \(\frac{-6}{4}=\frac{-3}{2}\)

=> đây là cặp phương trình tương đương .

b) +) 7.( x - 10 ) =12 

+) 14 . ( x - 10 ) = 24

<=> \(\frac{1}{2}.\left[14.\left(x-10\right)\right]=\frac{1}{2}.24\)

<=>7 . ( x - 10 ) = 12 

=> Đây là 2 phương trình tương đương .

c) +) \(\frac{4}{x+3}-3=\frac{4}{x+3}+x.\left(ĐK:x\ne-3\right)\)

<=> \(\left(\frac{4}{x+3}-\frac{4}{x+3}\right)-3=x\)

<=> 0 - 3 = x 

<=>x = 3 

+) Với x= -3 => x + 3 = 0

=> ko thỏa mãn 

=> ko xét tính tương đương