Tính \(\left(\sqrt{7}+\sqrt{11}+\sqrt{13}\right)\left(\sqrt{11}+\sqrt{13}-\sqrt{7}\right)\left(\sqrt{7}+\sqrt{13}-\sqrt{11}\right)\left(\sqrt{7}+\sqrt{11}-\sqrt{13}\right)\)
Những câu hỏi liên quan
Giải các phương trìnha/ \(x^2+8=3\sqrt{x^3+8}\)
b/ \(\sqrt{7+3x}+\sqrt{13-3x}+5\sqrt{\left(7+3x\right)\left(13-3x\right)}=46\)
c/ \(\sqrt[11]{x-4}+\sqrt[11]{x-5}+\sqrt[11]{2x-9}=2\)
a) \(x^2+8=3\sqrt{x^3+8}\)
\(\left(x^2+8\right)^2=\left(3\sqrt{x^2+8}\right)^2\)
\(x^4+16x^2+64=9x^2+72\)
\(\Rightarrow\orbr{\begin{cases}x=1\\x=-1\end{cases}}\)
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Rút gọn
\(C=\left(\sqrt{12+2\sqrt{14+2\sqrt{13}}}-\sqrt{12+2\sqrt{11}}\right)\left(\sqrt{11}+\sqrt{13}\right)\)
C = \(\left(\sqrt{12+2\sqrt{14+2\sqrt{13}}}-\sqrt{12+2\sqrt{11}}\right)\left(\sqrt{11}+\sqrt{13}\right)\)
C = \(\left(\sqrt{12+2\sqrt{\left(\sqrt{13}+1\right)^2}}-\sqrt{\left(\sqrt{11}+1\right)^2}\right)\left(\sqrt{11}+\sqrt{13}\right)\)
C = \(\left(\sqrt{14+2\sqrt{13}}-\left(\sqrt{11}+1\right)\right)\left(\sqrt{11}+\sqrt{13}\right)\)
C = \(\left(\sqrt{\left(\sqrt{13}+1\right)^2}-\sqrt{11}-1\right)\left(\sqrt{11}+\sqrt{13}\right)\)
C = \(\left(\sqrt{13}+1-\sqrt{11}-1\right)\left(\sqrt{13}+\sqrt{11}\right)\)
C \(\left(\sqrt{13}-\sqrt{11}\right)\left(\sqrt{13}+\sqrt{11}\right)\) = \(13-11\) = \(2\)
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\(\left(\sqrt{12+2\sqrt{14+2\sqrt{13}}-\sqrt{12+2\sqrt{11}}}\right)\left(\sqrt{11}+\sqrt{3}\right)\)
\(\left(\sqrt{12+2\sqrt{14+2\sqrt{13}}}-\sqrt{12+2\sqrt{11}}\right)\left(\sqrt{11}+\sqrt{13}\right)\)
\(=\left(\sqrt{12+2\sqrt{\left(\sqrt{13+1}\right)^2}}-\sqrt{\left(\sqrt{11+1}\right)^2}\right)\left(\sqrt{11}+\sqrt{13}\right)\)
\(=\left(\sqrt{12+2\sqrt{13+2}}-\sqrt{11}-1\right)\left(\sqrt{11}+\sqrt{13}\right)\)
\(=\left(\sqrt{\left(\sqrt{13}+1\right)^2}-\sqrt{11}-1\right)\left(\sqrt{11}+\sqrt{13}\right)\)
\(=\left(\sqrt{13}+1-\sqrt{11}-1\right)\left(\sqrt{11}+\sqrt{13}\right)\)\(=\left(\sqrt{13}-\sqrt{11}\right)\left(\sqrt{11}+\sqrt{13}\right)=13-11=2\)
sao dấu= thứ 2 lại ra như vậy
Thực hiện phép tính:
a) \(\left(2-\sqrt{3}\right)\sqrt{7+4\sqrt{3}}\).
b) \(\sqrt{13+4\sqrt{10}}+\sqrt{13-4\sqrt{10.}}\)
c) \(\sqrt{7-3\sqrt{5.}}\)
d) \(\left(\sqrt{2}-\sqrt{9}\right)\sqrt{11+2\sqrt{16.}}\)
\(a.\left(2-\sqrt{3}\right)\sqrt{7+4\sqrt{3}}=\left(2-\sqrt{3}\right)\sqrt{4+2.2\sqrt{3}+3}=\left(2-\sqrt{3}\right)\sqrt{\left(2+\sqrt{3}\right)^3}\) = \(\left(2-\sqrt{3}\right)\) | \(2+\sqrt{3}\) | = \(4-3=1\)
\(b.\sqrt{13+4\sqrt{10}}+\sqrt{13-4\sqrt{10}}=\sqrt{8+2.2\sqrt{2}.\sqrt{5}+5}+\sqrt{8-2.2\sqrt{2}.\sqrt{5}+5}=\sqrt{\left(2\sqrt{2}+\sqrt{5}\right)^2}+\sqrt{\left(2\sqrt{2}-\sqrt{5}\right)^2}\) \(=\) | \(2\sqrt{2}+\sqrt{5}\) | \(+\) | \(2\sqrt{2}-\sqrt{5}\) | \(=4\sqrt{2}+2\sqrt{5}\)
\(c.\sqrt{7-3\sqrt{5}}=\dfrac{\sqrt{14-2.3\sqrt{5}}}{\sqrt{2}}=\dfrac{\sqrt{9-2.3\sqrt{5}+5}}{\sqrt{2}}=\dfrac{\sqrt{\left(3-\sqrt{5}\right)^2}}{\sqrt{2}}\)\(=\) \(\dfrac{\text{ |}3-\sqrt{5}\text{ |}}{\sqrt{2}}\) \(=\dfrac{3-\sqrt{5}}{\sqrt{2}}\)
\(d.\) Tương Tự nhé bạn.
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\(\left(\sqrt{11}-\sqrt{3}\right)\left(\sqrt{13-\sqrt{6}+2\sqrt{30-\sqrt{54}}}+\sqrt{11}-\sqrt{10-\sqrt{6}}\right)\)
RÚT GỌN
Rút gọn:
A = \(\left(\sqrt{11}-\sqrt{3}\right)\left(\sqrt{13-\sqrt{6}+2\sqrt{30-\sqrt{54}}}+\sqrt{11}-\sqrt{10-\sqrt{6}}\right)\)
Rút gọn
1) \(E=\left(\sqrt{11}-3\right)\left(\sqrt{13-\sqrt{6}+2\sqrt{30-\sqrt{54}}}+\sqrt{11}-\sqrt{10-\sqrt{6}}\right)\)
2) \(F=\frac{\left(\sqrt{3-\sqrt{5}}-1\right)\left(\sqrt{3-\sqrt{5}}\left(3-\sqrt{5}\right)+1\right)}{4-\sqrt{5}-\sqrt{3-\sqrt{5}}}+\sqrt{5}\)
a) 11+6\(\sqrt{2}\) = \(\left(3+\sqrt{2}\right)^2\)
b) 8-2\(\sqrt{7}\)=\(\left(\sqrt{7}-1\right)^2\)
c)\(\sqrt{11+6\sqrt{2}}=\sqrt{11-6\sqrt{2}}=6\)
d) \(\sqrt{8-2\sqrt{7}}-\sqrt{8+2\sqrt{7}}=-2\)
21 tháng 7 2023 lúc 9:12
Rút gọn: (Giải chi tiết từng bước)
7) \(\left(\sqrt{28}-\sqrt{12}-\sqrt{7}\right)\sqrt{7}+2\sqrt{21}\)
8) \(\left(\sqrt{99}-\sqrt{18}-\sqrt{11}\right)\sqrt{11}+3\sqrt{22}\)
`a, (sqrt 28 - sqrt 12 - sqrt 7) sqrt 7 + 2 sqrt 21`.
`= sqrt(28.7) - sqrt(12.7) - sqrt(7.7) + 2 sqrt 21`.
`= sqrt(4. 7.7) - sqrt (12.7) - 7 + 2 sqrt 21`.
`= 14 - sqrt(4.3.7) - 7 + 2 sqrt 21`.
`= 7`.
`b, (sqrt99-sqrt18-sqrt11)sqrt11+3sqrt22`
`= sqrt(99.11)- sqrt(18.11)-sqrt(11.11) +3sqrt22`
`= sqrt(9.11.11)-sqrt(2.9.11)-11+3sqrt22`
`= 33 - 11 = 22`.
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