Tính bằng cách hợp lí
(3.4.2^16)/11.2^13.4^11-16^9 các bạn ơn giúp minh với minh đang gấp nhớ ghi cách giải cho minh với nhé
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
Giúp mình với! Nhớ ghi cả cách giải nữa nhé.
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^{19}}\)
\(\Leftrightarrow\)\(\frac{3^2.\left(2^2\right)^2.2^{16.2}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^{19}}\)
\(\Leftrightarrow\)\(\frac{2^4.2^{32}.3^2}{11.2^{35}-2^{76}}\)
\(\Leftrightarrow\)\(\frac{2^{36}.3^2}{2^{35}.\left(11-2^{41}\right)}\)
\(\Leftrightarrow\)\(\frac{2.3^2}{11-2^{41}}\)
Hết biết giải rồi
\(\frac{3^2.4^2.2^{32}}{11.2^{13}.2^{22}-2^{36}}=\frac{3^2.2^4.2^{32}}{11.2^{35}-2^{36}}\)\(=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}=\frac{3^2.2}{9}=\frac{3^2.2}{3^2}=2\)
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\)\(\frac{3^2.2^{2.2}.2^{16.2}}{11.2^{13}.2^{11.2}-2^{4.9}}\)
\(=\)\(\frac{2^{36}.3^2}{11.2^{35}-2^{36}}\)
\(=\)\(\frac{2^{36}.3^2}{2^{35}.\left(11-2\right)}\)
\(=\)\(\frac{2.3^2}{9}\)
\(=\)\(\frac{2.3^2}{3^2}\)
\(=\)\(2\)
Thực hiện phép tính một cách hợp lí
(3.4.2^16)^2.(11.2^13.4^11-169)
(3.4.2^16)^2 . (11.2^13.4^11-16^9)=?
giúp mik cách giải nha
\(\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
giải giúp mình với. đề bài là làm bằng cách hợp lý.mình cần gấp
\(\dfrac{\left(3\cdot4\cdot2^{16}\right)^2}{11\cdot2^{13}\cdot4^{11}-16^9}=\dfrac{\left(3\cdot2^2\cdot2^{16}\right)^2}{11\cdot2^2\cdot\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(=\dfrac{3^2\cdot\left(2^2\right)^2\cdot\left(2^{16}\right)^2}{11\cdot2^2\cdot2^{22}-2^{36}}=\dfrac{3^2\cdot2^4\cdot2^{32}}{11\cdot2^{24}-2^{36}}\)
\(=\dfrac{3^2\cdot2^{34}}{11\cdot2^{24}-2^{36}}=\dfrac{3^2\cdot2^{24}\cdot2^{10}}{11\cdot2^{24}-2^{12}\cdot2^{24}}\)
\(=\dfrac{3^2\cdot2^{24}\cdot2^{10}}{\left(11-2^{12}\right)\cdot2^{24}}=\dfrac{3^2\cdot2^{10}}{11-2^{12}}\)
tính giá trị của biểu thức:
(3.4.2^16)^2/11.2^13.4^11-16^9
bạn nào biết giải giúp mình bài này với
các bạn giúp mik với : (3.4.2^16)^2/11.2^13.4^11-16^9
thank mấy bạn nhak
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)\(=\frac{3^2.4^2.2^{32}}{11.2^{12}.2^{22}-2^{36}}\)\(=\frac{3^2.2^4.2^{32}}{11.2^{34}-2^{34}.2^2}\)\(=\frac{3^2.2^{34}.2^2}{2^{34}.\left(11-2^2\right)}\)\(=\frac{2^{34}.36}{2^{34}.7}=\frac{36}{7}\)
Tính bằng cách hợp lí
\(\dfrac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\dfrac{3^2\cdot2^{36}}{11\cdot2^{13}\cdot2^{22}-2^{36}}=\dfrac{3^2\cdot2^{36}}{2^{35}\cdot9}=2\)
Tính theo cách hợp lý
a) (10^2+11^2+12^2):(13^2+14^2)
b)1.2.3....9 -1.2.3...8-1.2.3...7.8^2
c)(3.4.2^16)^2 /11.2^13.4^11-16^9
a: \(\dfrac{10^2+11^2+12^2}{13^2+14^2}=\dfrac{100+121+144}{169+196}=\dfrac{365}{365}=1\)
c: \(=\dfrac{3^2\cdot2^{36}}{11\cdot2^{13}\cdot2^{22}-2^{36}}=\dfrac{3^2\cdot2^{36}}{2^{35}\cdot\left(11-2\right)}=2\)
Tính:
A= ( 3.4.2^16)^2 / 11.2^13.4^11-16^9
bạn sai rồi
Oh
\(\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}\)
\(=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}\)
\(=\frac{3^2.3^{36}}{2^{35}.\left(11-2\right)}\)
\(=\frac{9.2}{9}=2\)
\(A=\frac{\left(3.4.2^{16}\right)^2}{11.2^{13}.4^{11}-16^9}\)
\(A=\frac{3^2.4^2.2^{32}}{11.2^{13}.4^{11}-16^9}\)
\(A=\frac{3^2.2^4.2^{32}}{11.2^{13}.\left(2^2\right)^{11}-\left(2^4\right)^9}\)
\(A=\frac{3^2.2^{36}}{11.2^{13}.2^{22}-2^{36}}\)
\(A=\frac{3^2.2^{36}}{11.2^{35}-2.2^{35}}\)
\(A=\frac{3^2.2^{36}}{\left(11-2\right).2^{35}}\)
\(A=\frac{3^2.2}{9}=\frac{18}{9}=2\)